Second question
In order to break even,
total revenue must be equal to total cost. In this case, there is no profit
Let x represent the number of units of tape that would be manufactured to break even.
From the information given,
cost of shooting the video = 84000
If the cost of producing a unit is $15, it means that the cost of x units would be 15x
The total cost of producing x units is
15x + 84000
The wholesale price of the tape is $50 per unit. It means that the revenue from selling x units would be 50x
To break even, it means that
15x + 84000 = 50x
50x - 15x = 84000
35x - 84000
x = 84000/35
x = 2400
2400 units must be manufactured and sold each month for the company to break even
solve the system of linear equations by substitution 3y=-2x and y=x-5
Step 1
Given;
[tex]\begin{gathered} 3y=-2x--(1) \\ y=x-5--(2) \end{gathered}[/tex]Required; To solve the system of linear equations
Step 2
Find the value of y and x
[tex]\begin{gathered} Substitute\text{ 2 into 1} \\ 3(x-5)=-2x \\ 3x-15=-2x \\ 5x=15 \\ \frac{5x}{5}=\frac{15}{5} \\ x=3 \end{gathered}[/tex][tex]\begin{gathered} From\text{ 2, y=x-5} \\ y=3-5=-2 \end{gathered}[/tex]Answers;
[tex]x=3,\text{ y=-2}[/tex]fill in the blank with the correct answer. the number _______is divisibel by 2, 3, 4, 5, and 6
a)44
b)180
c)280
d)385
Answer:
b) 180
Explanation:
[tex]180 / 2 = 90\\180 / 3 = 60\\180 / 4 = 45\\180 / 5 = 36\\180 / 6 = 30[/tex]
Hope you have a nice day and a nice Thanksgiving!
A brainiliest would also be nice. thx.
Zero and negative exponentswrite in simplest for without zero or negative exponents10c -²
Explanation
remember some properties of the exponents
[tex]\begin{gathered} a^m\cdot a^n=a^{m+n} \\ (a^m)^n=a^{m\cdot n} \\ a^{-m}=\frac{1}{a^m} \end{gathered}[/tex]Hence,apply
[tex]10c^{-2}=10\cdot c^{-2}=\frac{10}{c^2}[/tex]I hope this helps you
Simplify: 6-(-9) divided by -9/-4
Answer:
6 2/3
Explanation:
Given the expression:
[tex]\lbrack6-\mleft(-9\mright)\rbrack\div\frac{-9}{-4}[/tex]First, we simplify to obtain:
[tex]=\lbrack6+9\rbrack\div-\frac{9}{-4}[/tex]Note that -9/-4=9/4. The minus sign cancels each other out.
This gives us:
[tex]15\div\frac{9}{4}[/tex]We then change the division sign to multiplication as shown below:
[tex]\begin{gathered} =15\times\frac{4}{9} \\ =\frac{60}{9} \\ =6\frac{6}{9} \\ =6\frac{2}{3} \end{gathered}[/tex]For any right triangle, the side lengths of the triangle can be put in the equation a^2+ b^2 = c^2 where a, b, and c are the side lengths. A triangle with the side lengths 3 inches, 4 inches, and 5 inches is a right triangle. Which way(s) can you substitute the values into the equation to make it true? Which variable has to match the longest side length? Why?
It is given that the side lengths of any right triangle can be put in the equation:
[tex]a^2+b^2=c^2[/tex]For a triangle with the side lengths 3 inches, 4 inches, and 5 inches, it can be substituted in two ways that will make the equation true:
Let a=3, b=4, and c=5:
[tex]\begin{gathered} 3^2+4^2=5^2 \\ \Rightarrow9+16=25 \\ \Rightarrow25=25 \end{gathered}[/tex]Hence, the equation is true.
You can also substitute a=4, b=3, and c=5.
This will also give the same result.
Notice that variable c has to match the longest side length.
The reason for this is that equality can only hold if the longest side is the variable at the right, if not there'll be an inequality instead.
The formula S=C(1+r) models inflation, where C = the value today, r = the annual inflation rate, and S = the inflated value t years from now. a. If the inflation rate is 6%, how much will a house now worth $465,000 be worth in 10 years? b. If the inflation rate is 3%, how much will a house now worth $510,000 be worth in 5 years?
The formula that models inflation is
[tex]S=C(1+r)^t[/tex]C= value today
r= annual inflation rate → usually this value is given as a percentage, but when you input the value in the formula, you have to express it as a decimal value.
S= the inflated value given a determined period of time (t).
a.
r=6%=6/100=0.06/year
C=$465000
t=10 years
[tex]\begin{gathered} S=465000(1+0.06)^{10} \\ S=832744.1789 \end{gathered}[/tex]The price of the house in 10 years at an inflation rate of 6% will be S=$832744.18
b.
r=3%=3/100=0.03/year
C=$510000
t=5years
[tex]\begin{gathered} S=510000(1+0.03)^5 \\ S=437954.3531 \end{gathered}[/tex]The price of the house in 5 years at an inflation rate of 3% will be S=$437954.35
Which of the following is the co-function of cos 58 degrees?tan 58°sin 58°cos 32°sin 32°
ANSWER
[tex]\sin 32^o[/tex]EXPLANATION
We want to find the cofunction of the given function.
The cofunction of a cosine function is:
[tex]\cos (\theta)=\sin (90-\theta)[/tex]Therefore, the cofunction of cos(58) is:
[tex]\begin{gathered} \cos (58)=\sin (90-58) \\ \cos (58^o)=\sin (32^o) \end{gathered}[/tex]That is the answer.
a vector s has the initial point (-2,-4) and terminal point (-1,3) write s in the form s = ai + bj
To write the vector s in the form s=ai + bj, we can use the next formula:
[tex]\vec{s}=(x_2-x_1)\vec{i}+(y_2-y_1)\vec{j}[/tex]Where (x1,y1) are the coordinates of the initial point and (x2,y2) are the coordinates of the terminal point, by replacing these values we have:
[tex]\begin{gathered} \vec{s}=((-1)-(-2))\vec{i}+(3-(-4))\vec{j} \\ \vec{s}=((-1)+2)\vec{i}+(3+4)\vec{j} \\ \vec{s}=(1)\vec{i}+(7)\vec{j} \end{gathered}[/tex]Then the vector s in the form s=ai+bj is: s= 1i + 7j
Use my radians find the amplitude and period of each function then graph
For a function of the form:
[tex]y=acos(b\theta)[/tex]a = amplitude = 2
b = angular frequency = 1/4
The period can be calculated as follows:
[tex]\begin{gathered} T=\frac{2\pi}{b} \\ So: \\ T=\frac{2\pi}{1/4} \\ T=8\pi \end{gathered}[/tex]Now, we can graph the function easily:
Find each unknown function value or x value for f(x) = 4x - 7 and g(x) = -3x + 5
Step 1
Find f(2)
[tex]To\text{ do this we substitute for f= 2 in f(x)}[/tex][tex]\begin{gathered} f(x)\text{ = }4x-7 \\ f(2)\text{ = 4(2) -7 = 8 - 7 = 1} \end{gathered}[/tex]Step 2
Find f(0)
[tex]f(0)\text{ = 4(0) -7 = 0 - 7 = -7}[/tex]Step 3
Find f(-3)
[tex]f(-3)\text{ = 4(-3) -7 = -12 -7 = -19}[/tex]Step 4
Find x, when f(x) = -3
[tex]\begin{gathered} f(x)\text{ = -3}--------------(1) \\ f(x)\text{ =4x-7}---------------(2) \\ \text{Equate both equations} \\ -3=4x-7 \\ -3+7\text{ = 4x} \\ 4x\text{ = 4} \\ x\text{ = }\frac{4}{4}=1 \end{gathered}[/tex]Write the standard form of the equation of the circle described below. (6,-7) r=9
Solution
Step 1
write out the expression for the equation of a circle
[tex](x-h)^2+(y-k)^2=r^2[/tex]Where the centers are (h,k)
h = 6
k = -7
r = 9
Step 2
Write out the required equation of the circle using the parameters
[tex]\begin{gathered} \text{The required equation thus is} \\ (x-6)^2+(y-(-7))^2=9^2 \\ (x-6)^2+(y+7)^2=81_{} \end{gathered}[/tex]A data set has these values: 6, 8, 8, 10, 10, 10, 10, 12, 12, 14. The histogram ofthe distribution is shown.Aanb542<-057 9 11 13 15Data valuesWhich statement does not describe the data set?
It has a range of [tex]$15^{\prime \prime}$[/tex] is not describe the data set.
The data set is Symmetric.
it has a mode m=10= median = mean.
[tex]$$\begin{aligned}\text { Range } &=14-6 \\&=8\end{aligned}$$[/tex]
So option (c) is correct.
"It has a range of [tex]$15^{\prime \prime}$[/tex]
A data set is, for example, each student's test scores in a specific class. A data set is the number of fish consumed by each dolphin in an aquarium.
A data set is a grouping of data. A data set refers to one or more database tables in the case of tabular data, where each column of a table represents a specific variable and each row corresponds to a specific record of the data set in question.
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The function h(x) shown is the result of adding two functions, f(x) and g(x).
Which statement could be used to describe the functions?
The domains of both f(x) and g(x) must be (–∞, ∞).
What is a domain?
The range of values that we are permitted to enter into our function is known as the domain of a function. The x values for a function like f make up this set (x).
Here, we concluded that
The domains of both f(x) and g(x) must be (–∞, ∞).
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Select all of the expressions that are less than 10103O A 103хB. 1x 10oC 103 x 2OD } x 103O E 103
Let's check every option:
[tex]10\frac{2}{3}=\frac{32}{3}\approx10.667[/tex]A.
[tex]10\frac{2}{3}\times\frac{9}{10}=9.6<10.667[/tex]This option is correct
------------------------
B.
[tex]1\times10\frac{2}{3}=10.667=10.667[/tex]This option is not correct.
----------------------
C.
[tex]10\frac{2}{3}\times2\frac{1}{3}\approx24.888>10.667[/tex]This option is not correct
-------------------
D.
[tex]\frac{1}{8}\times10\frac{2}{3}\approx1.33<10.667[/tex]This option is correct
----------------------------
E.
[tex]10\frac{2}{3}\times\frac{3}{5}=6.4<10.667[/tex]This option is correct
Answer:
A
D
E
a. 10x-6=44b. (x+3)-15=48c. 4(x+6)-10=26d. 3(x+3)-15=48e.Which two equations have the same solution set? Write a sentence explaining how the properties of equality can be used to determine the pair without having to find the solution set for each.
a.
[tex]\begin{gathered} 10x-6=44 \\ 10x=44+6 \\ 10x=50 \\ x=\frac{50}{10} \\ x=5 \end{gathered}[/tex]b.
[tex]\begin{gathered} 9(x+3)-15=48 \\ 9x+27-15=48 \\ 9x+12=48 \\ 9x=36 \\ x=\frac{36}{9} \\ x=4 \end{gathered}[/tex]c.
[tex]\begin{gathered} 4(x+6)-10=26 \\ 4x+24-10=26 \\ 4x+14=26 \\ 4x=26-14 \\ 4x=12 \\ x=\frac{12}{4} \\ x=3 \end{gathered}[/tex]d.
[tex]\begin{gathered} 3(x+3)-15=48 \\ 3x+9-15=48 \\ 3x-6=48 \\ 3x=48+6 \\ 3x=54 \\ x=\frac{54}{3} \\ x=18 \end{gathered}[/tex]The answer in set notation
[tex]x=\mleft\lbrace5,4,3,18\mright\rbrace[/tex]e. Equation b and Equation d have the same solution set . Both of the equations is equals to 48.
What is the y-intercept in this equation: -1.5= y-12/0-4
The y-intercept in this equation: -1.5= y-12/0-4 is 18.
What is equation?
Equation: A statement stating the equality of two expressions with variables or integers. Essentially, equations are questions, and attempt to systematically find the answers to these questions have been the inspiration for the development of mathematics.
Given Equation:
-1.5 = y - 12 / 0-4
Solve the above equation, and we get,
-1.5 = y - 12 / (-4)
y -12 = 6.0
y = 18
Therefore, the y-intercept in this equation: -1.5= y-12/0-4 is 18.
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Factor 2x^2 - 10x - 12.2(x + 2)(x - 3) 2(x - 6)(x + 1)2(x - 1)(x + 6)
The factor is 2(x+1)(x-6).
From the question, we have
2x²-10x-12
=2x²-12x+2x-12
=2x(x-6)+2(x-6)
=(2x+2)(x-6)
=2(x+1)(x-6)
Factors :
The positive integers that can divide a number evenly are known as factors in mathematics. Let's say we multiply two numbers to produce a result. The product's factors are the number that is multiplied. Each number has a self-referential element. There are several examples of factors in everyday life, such putting candies in a box, arranging numbers in a certain pattern, giving chocolates to kids, etc. We must apply the multiplication or division method in order to determine a number's factors.The numbers that can divide a number exactly are called factors. There is therefore no residual after division. The numbers you multiply together to obtain another number are called factors. A factor is therefore another number's divisor.
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in a circle the radius is 11.5 which is the circumference??
The circumference of a circle is the perimeter or external measure.
Given a circle of radius r, the circumference is calculated as:
C=2 π r
The circle has a radius of r=11.5 units
The circumference is:
C=2 π (11.5) = 72.26 units
The circumference is 72.26 units
Daniel opened a small business. His profit for the first month was -$503. If his average profit for months 2-4 was $-421, what was the total profit for months 1-4?Please help me
If Daniel profit for the first month was -$503. If his average profit for months 2-4 was $-421, then $924 was the total profit for months 1-4
What is Equation?Two or more expressions with an Equal sign is called as Equation.
Given,
Daniel opened a small business.
Profit for the first month was -$503 five hundred and three
Average profit for months 2-4 was $-421, four hundred and twenty one.
We need to find the total profit for months 1-4
Add profit for 1s month and 2-4 months.
$503+$421
$924
Hence $924 was the total profit for months 1-4
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The two triangles below are similar. Also, m A = 15° and m ZC - 35° as shown below Find m2P, m 2Q, and m ZR. Assume the triangles are accurately drawn
Answer
Angle R = 15°
Angle P = 130°
Angle Q = 35°
Explanation
First noting that the sum of angles in a triangle is 180°.
We first need to calculate the Angle B for the first triangle.
Angle A + Angle B + Angle C = 180°
15° + Angle B + 35° = 180°
Angle B + 50° = 180°
Angle B = 180° - 50°
Angle B = 130°
We are then told to find Angles P, Q and R.
We are told that the two triangles are similar .
Two similar triangles will have the same angle measures.
So, we just need to note the corresponding angles and equate the unknowns.
Triangle ABC is similar to Triangle RPQ
Angle R = Angle A = 15°
Angle P = Angle B = 130°
Angle Q = Angle C = 35°
Hope this Helps!!!
Find the value of x. 14 6 / 110° 9 70
We are given a triangle crossed by two parallel lines. The lines are parallel since their corresponding angles are the same. Therefore, from Thale's theorem we have the following relationship:
[tex]\frac{14}{6}=\frac{x}{9}[/tex]Now we solve for "x" by multiplying by 9 on both sides of the equation:
[tex]\frac{14}{6}\times9=x[/tex]Solving the operations we get:
[tex]21=x[/tex]Therefore, x = 21
A box contains the name of every student in the school. One hundred names are drawn from the box and students are asked their opinion of the new pizza served in the cafeteria. (A) biased or(B) unbiased
This is an unbiased sampling because there is not a systematically opinion that favors some outcomes over others. So the answer is B
Inequality statement for -13,-25,-8
The inequality statement for -13,-25,-8 is -13 > -25 < -8.
What is an inequality?Inequalities are created through the connection of two expressions. It should be noted that the expressions in an inequality aren't always equal. Inequalities implies that the expressions are not equal. They are denoted by the symbols ≥ < > ≤.
It should be noted that -13 is greater than -25 while -25 is less than -8.
In this case, -13 > -25 < -8.
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Subtract.7x2 - 5x+3(2x2 +7x-4)A. 5x2 - 2x + 7B. 5x2 - 12x +7C. 5x2 + 12x-1D. 5x2 + 2x-1
We have to evaluate the expression 7x^2 - 5x + 3 - (2x^2 +7x-4):
[tex]\begin{gathered} 7x^2-5x+3-(2x^2+7x-4) \\ (7-2)x^2+(-5-7)x+(3-(-4)) \\ 5x^2-12x+(3+4) \\ 5x^2-12x+7 \end{gathered}[/tex]Answer: B. 5x2 - 12x +7
Hello,Can you please help with question 33 on the photo? Thank you
With the help of the given formula, we can find the first four terms of the sequence:
[tex]\begin{gathered} a_1=30 \\ a_2=a_{2-1}-10=a_1-10=20 \\ a_3=a_{3-1}-10=a_2-10=10 \\ a_4=a_{4-1}-10=a_3-10=0 \end{gathered}[/tex]Then, the first four terms of the sequence are 30, 20, 10, 0, ...
Now, as we can see, this is an arithmetic sequence because there is a common difference between each term. The explicit formula of an arithmetic sequence is shown below:
[tex]\begin{gathered} a_n=a_1+d(n-1) \\ \text{ Where} \\ \text{ d is the common difference} \end{gathered}[/tex]Then, we have:
[tex]\begin{gathered} a_1=30 \\ d=-10 \end{gathered}[/tex][tex]\begin{gathered} a_n=a_1+d(n-1) \\ a_n=30-10(n-1) \\ \text{ Apply the distributive property} \\ a_n=30-10*n-10*-1 \\ a_n=30-10n+10 \\ a_n=-10n+40 \end{gathered}[/tex]Thus, a formula for the general term of the sequence is:
[tex]a_{n}=-10n+40[/tex]Now, we substitute n = 20 in the above formula to find the 20th term of the sequence:
[tex]\begin{gathered} a_{n}=-10n+40 \\ a_{20}=-10(20)+40 \\ a_{20}=-200+40 \\ a_{20}=-160 \end{gathered}[/tex]AnswerA formula for the general term of the sequence is:
[tex]a_{n}=-10n+40[/tex]The 20th term of the sequence is -160.
Earn,deposit, increase and raise all have positive valuesTrue or False
We will have the following:
*Earn: By definition represents a positive value, since you cannot "earn" a negative quantity.
*Deposit: Deposits are "neutral" since they represent the movement of money but not neccesarily an increase, and sometimes it can be also a payment, so it can also be net negative.
*Increase: By definition is a positive value.
*Raise: By definition is a positive value.
So, it is false. Reason:
A deposit represents a net neutral, since it is refering to the movement of money but not it's increase neccesarily, and sometimes is also a negative, since it can be used as payment, thus representing a net negative value.
A local bakery has determined the probability distribution for the number of cheesecake that they sell in a given day let X equal the number of cheesecake sold on a randomly selected day
1) First, from the question we see that we have a table with the probability distribution p(X) for the number of cheesecakes (X) sold on a randomly selected day. We know that the numbers in the table for P(X) should sum up to 1, that's because the total probability always sums 1. So using this fact we can see that:
[tex]P(x=15)=0.28[/tex]2) The probability of selling at least 10 cheesecakes is the sum of probabilities P(x) for x ≥ 10, using the data from the table and the probability obtained above we have:
[tex]\begin{gathered} P(x\ge10)=P(x=10)+P(x=15)+P(x=20) \\ P(x\ge10)=0.21+0.28+0.1 \\ P(x\ge10)=0.59 \end{gathered}[/tex]3) The probability of selling 5 or 15 cheesecakes is the joint probability of the events of selling 5 cheesecakes P(x = 5) or 15 cheesecakes P(x = 15) because they are independent events (i.e. P(x=5 ∩ x=15) = 0), we have:
[tex]\begin{gathered} P(x=5orx=15)=P(x=5)+P(x=15)-P(x=5andx=15) \\ P(x=5orx=15)=0.3+0.28-0 \\ P(x=5orx=15)=0.58 \end{gathered}[/tex]4) From the table we see that we don't have an assigned value for the probability of selling x = 25 cheesecakes, so the probability for this event is zero:
[tex]P(x=25)=0[/tex]5) The probability of selling at most 10 cheesecakes is the sum of the probabilities P(x) for x ≤ 10, using the data from the table we have:
[tex]\begin{gathered} P(x\leq10)=P(x=0)+P(x=5)+P(x=10) \\ P(x\leq10)=0.11+0.3+0.21 \\ P(x\leq10)=0.62 \end{gathered}[/tex]6) Finally, we must compute the expected value μ of cheesecakes sold on any given day, applying the following formula and the data of the table we get:
[tex]\begin{gathered} \mu=\sum ^{}_iX_i\cdot P(X_i) \\ \mu=0\cdot0.11+5\cdot0.3+10\cdot0.21+15\cdot0.28+20\cdot0.1 \\ \mu=9.8 \end{gathered}[/tex]Answers summary:
1) P(x = 15) = 0.28
2) P(x ≥ 10) = 0.59
3) P(x = 5 or x = 15) = 0.58
4) P(x = 25) = 0
5) P(x ≤ 10) = 0.62
6) μ = 9.8
The maximum grade allowed between two stations in a rapid transit rail system is 3.5%. Between station a and station b which are 290 feet apart, the tracks rise 8 ft. What is the grade of the tracks between these stations ? Round the answer to the nearest tenth of a percent. Does this grade meet the rapid transit rails standards?
Given,
Station A and Station B are 290 feet apart.
Tracks rise 8 feet.
We need to find the slope of the tracks, because the slope of the track is the gradient of the track.
The slope is rise over run.
The rise is "8"
The run is "290"
Hence, the slope is >>>>>
[tex]\frac{8}{290}\approx0.027586[/tex]To convert it to a percentage, we multiply by 100. Thus,
[tex]0.027586\times100\approx2.76\%[/tex]This is within the tolerance range of less than 3.5%.
So, this grade meets the rapid transit rail standards.
AnswerGrade of tracks = 2.8%Yes, it does meet the rapid transit rail standards.can you please help me
Answer:
15
Explanation:
The y-intercept of a line is the point where it intersects the y-axis. This happens when x = 0; therefore, the y-coordinate of the y-axis is found by putting x = 0 in the equation given. This gives
[tex]18(0)-y=-15[/tex][tex]-y=-15[/tex][tex]y=15[/tex]which is our answer!
Step 1 Step 2 Step 3 Using the figures above, how many small squares will there be in step 4 and step 15? a. Step 4 = b. Step 15 =
Step 4 = 16 squares
Step 15 = 225 squares
1) In the 1st step we can see, 1 square. In the 2nd, 4, and on the third one 9
So there's a sequence, 1, 4, 9
2) We can write the positions and raise them to the 2nd power we can see how it grows:
position (steps) n | 1 | 2 | 3
# squares | 1 | 4 | 9
3) We can derive a formula for that sequence:
[tex]a_n=n^2[/tex]Following this rule, we can find that
Step 4 = 4² = 16 squares
Step 15 = 15² = 225 squares