A buret dispenses 16.4 mL of a 0.521 M NaOH solution. How many moles of NaOH were dispensed?

The mass of hydrogen present in 50.7 grams of ammonia is equal to 8.95 g.

A mole is a scientific unit that is used to determine the huge number of quantities of atoms, molecules, ions, etc. The mass of the 1 mole of any element is called atomic mass and that of one mole of any compound is called molar mass.

The number of entities present in 1 mole was found to be equal to 6.023 × 10 ²³ per mole which is known as Avogadro’s constant.

Given, the mass of ammonia = 50.7 g

The mass of the one mole of ammonia = 17 g/mol

17 g of ammonia contain the mass of hydrogen = 3 g

50.7 g of ammonia contains a mass of hydrogen = (3/17) × 50.7 = 8.95 g

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1) Uncertainty in substraction. the result must have the same number of decimal places as the one with less.

5.1 - 2.3685 = 2.7315

The result must have one decimal place. Since the second decimal place (3) is smaller than five we round down.

The result is 2.7.

1) First let's calculate the molar mass of O₂ and H₂:

O₂: (16x2) = 32 g/mol (for both oxygen 1 and 2)

H₂: (1x2) = 2 g/mol

2) Now let's calculate the mass of gas sample (g) of:

Oxygen 1:

mass = mole x molar mass

mass = 1 x 32 = 32 g

Mass of Oxygen 1: 32 g

Oxygen 2:

mass = mole x molar mass

mass = 2 x 32 = 64 g

Mass of Oxygen 2: 64 g

Hydrogen:

mass = mole x molar mass

mass = 1 x 2 = 2 g

Mass of Hydrogen: 2 g

For the two oxygen samples, if the number of moles double, the mass double and the volume also double.

But the two gases of the same volume have different masses (Hydrogen 2 g and

oxygen 32 g). So there is no relationship between volume and mass for different gases.

Answer

Synthesis

Explanation

Synthesis reaction is when reactants combine to

Le Chatelier's principle is used to determine what effect a change will have on a mixture at equilibrium.

It describes the effect that a mixture suffers when it is exposed to a change.

It means that the correct answer is A.

Explanation

A) Trigonal planar

B) Trigonal pyramid

C) Tetrahedral

D) Linear

E) Linear

F) Tetrahedral

G) Linear

two different substances that are both pure, meaning they each contain only one type of matter. two properties determine which substance has the higher temperature is the kinetic energy of the slowest particle in each substance

The energy can be defined as  ability to work or produce action and / or movement and manifests itself in many different ways, such as body movement, heat, electricity, etc.

The different types of energy include Kinetic energy which is associated with the movement of bodies. Potential energy which is  stored by virtue of a body's position relative to its surface is also called gravitational potential energy.

Thermal Energy or Heat can be defined as the energy  associated with the kinetic energy of the molecules that make up an element, it can be manifested if there is a temperature difference between two bodies.

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Answer:

a) pH= 13.3

b) pOH= 0.7

c) [H+]= 5.01*10^-14M

d) [OH-]= 0.2M

Explanation:

The formula of sodium hydroxide is NaOH. In the molecule there are Na+ ions and OH- that dissociates like this:

That means that 1 mole of NaOH dissociates into 1 mole of Na+ ions and 1 mole of OH-.

So, for a 0.2M solution, 0.2 moles of NaOH will dissociate into 0.2 moles of Na+ ions and 0.2 moles of OH-.

d) [OH-]

From the dissociation of NaOH we know that the concentration of OH- is [OH-]=0.2M.

b) pOH

With the concentration of OH-, we can calulate the pOH:

So, the pOH is 0.7.

a) pH

Knowing the pOH and the following formula, we can calculate the pH of the solution:

The pH of the solution is 13.3.

c) [H+]

Now that we know thw pH of the solution, we can calculate the concentration of H+:

So, the concentration of H+ is 5.01*10^-14M.

Answer:

Explanation:

Here, we want to answer a question of state of matter

While solids have a definite shape and are incompressible under normal conditions, liq

Step 1 - Understanding the stoichiometry of the reaction

The given reaction is:

Note that 1 mole of Nitrogen gas react with 2 moles of Oxygen gas thus producing 1 mole of N2O4 gas. Since this is a fixed relation, we can state that:

each 2 moles of O2 produce 1 mole of N2O4

Step 2 - Converting the relation in moles to a relation in grams

We can convert the relation in moles between O2 and N2O4 to a relation in grams by multiplying each number of moles by the respective molar masses of the substances (32 g/mol for O2; 92 g/mol for N2O4):

We can state therefore that:

64 g of O2 (2 moles) produce 92 g of N2O4

This is like a cake recipe. It is a fixed proportion in grams, and we'll be using it to solve the exercise.

Step 3 - Finding the required moles of O2

Now that we have found a "recipe" for the reaction, we can use it to predict how much O2 would be needed. Let's remember that, in step 2, we have discovered that 2 moles of O2 produce 92 g of N2O4.

Therefore, to produce 23.6 grams, we can set the following proportion:

Therefore, 0.51 moles of O2 would be required.

answer and explanation

Given:

V1 = 3.50 liters

n1 = 1.65 mols

n2 = 2.60 mols

V2 = unknown

solution

to determine the volume that will be occupied by 2.60 mols we can use to following equation

V1/V2 = n1/n2

and we can rearrange the equation to make V2 subject of the formula like so:

V2 = V1n2/n1

= 3.50L x 2.60mols/1.65 mols

= 5.5 liters

2.60 mols will occupy a volume of 5.5 liters

The definition of wavelength is the distance between two identical points, like the crests of the waves, in a cycle of a waveform, so the distance between two crests, which is the highest point of the wave, this is wavelength

In our question, we have that one crest starts at 1.5 cm and the other starts at 2.5 cm, therefore the wavelength will be 1.0 cm of distance, letter D

The terms excess reactant and limiting reactant refer to how much of each reactant is available to react. Therefore, by its name we can understand that limiting reactant really limits the reaction, that is, it determines how much product can be made (B).

Excess reactant is also very literal, as it refers to the reactant in excess, that is, the one that is not all used up in the reaction (C).

And Theoretical yield refers to the amount of product that is produced based on the amount of reactants that really react, that is, the amount of product that can be made by the given amount of reactants (A)

In conclusion,

A) Theoretical yield.

B) Limiting reactant.

C) Excess reactant.

Answer:

Group 4A (Group IVA)

The answer is B

Explanation:

An element with valence electron configuration:

has 4 valence electrons.

Since the valence shell is n = 3 it is in Period 3. Since there are 4 valence electrons (2 in 3s and 2 in 3p) it is in Group 4A

The equation 2 C₂H₆ + 7 O2 ⇒ 4 CO₂ + 6H₂O. 482.6 gram of H₂O are produced from 268.5 grams of C₂H₆.

A saturated hydrocarbon that exists in a gaseous form is ethane. Methane is the simplest alkane, with ethane coming in second. It has 6 hydrogen atoms and 2 carbon atoms. Ethane's chemical formula is CH

With the chemical formula C₂H₆, ethane is an organic chemical substance. Ethane is a colorless and odorless gas at ordinary temperature and pressure.

Ethane is separated from natural gas on an industrial scale, and it is produced as a by-product of the petrochemical process used to refine crude oil.

268.5 gram of C₂H₆ × ( 1 mole C₂H₆ ÷ 30.07 gram of C₂H₆ ) × ( 6 mole of H₂O ÷ 2 mole C₂H₆ ) × ( 18.015 gram of H₂O ÷ 1 mole of H₂O )

= 482.6 gram of H₂O.

Thus, the equation 2 C₂H₆ + 7 O2 ⇒ 4 CO₂ + 6H₂O. 482.6 gram of H₂O are produced from 268.5 grams of C₂H₆.

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Ok to answer this question we firsst need to fin the number of mol of Urea (CH4N2O). to do this we simply :

1 mol of urea =15/60.055 = 0.25mol

therefore 200g of water contain 0.25mol

the next step is to determine the malality of our solution in 200g of water, to do this we say:

200 g = 1Kg/1000g = 0.2kg

therefor 0.25mol/0.2Kg = 1.25mol/kg

and from the equation:

we know that i = 1

we are given Kf

b is the molality that we just calculated

therefore;

the solutions freezing point is -2.325°C

The freezing point of the given solution was calculated to be -2.325 °C. The freezing point is the point at which a liquid changes from a liquid to a solid under atmospheric pressure.

The two phases, liquid and solid, exist in equilibrium at the freezing point. At the freezing point, both solid and liquid exist at the same time.

Given,

15 grams of CH₄N₂O is dissolved in 200 grams of water.

1 mol of urea = 60 grams

so 15 grams of urea will be found in 15/60 = 0.25 moles

So 0.25 moles of urea is present in 200 grams of water.

To determine the molality of the solution

200gm/1000gm = 0.2 kg water

0.25 moles/0.2 kg = 1.25 kg/mol

So to calculate the freezing point of the solution we use the formula:

ΔT = i× Kf × b  

Given Kf = 1.86 (°C·kg)/mol), b is the molality of the solution that is = 1.25 kg/mol, and i = 1

ΔT = 1 ×  1.86 × 1.25 = 2.325 °C

ΔT  = 0 °C - 2.325 °C =  -2.325 °C

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5.38 g is the mass of iron (0.444 J/goC) that can be heated from 5.4°C to 22.8°C using +41.6 J of energy

q=+41.6 J

c=0.444 J/goC

Δt=17.4

q=mcΔt

m=q/cΔt

m=+41.6 J /0.444 J/goC×17.4

m=5.38 g

Mass is one of the fundamental quantities in chemistry and the most fundamental property of matter. The quantity of matter in a body is referred to as its mass. The SI unit of mass is the kilogram.

The mass of a body is constant at all times. only when a body receives or loses a considerable amount of energy, which happens seldom. For instance, a nuclear reaction causes the mass of the material to decrease because a very little amount of matter is converted into a very high amount of energy.

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4Fe + 3O2 ==> 2Fe2O3

1) List the known and unknown quantities.

Molar mass: 34.04 g.

Empirical formula: NH.

Molecular formula: unknown.

2) Find the molar mass of the empirical formula.

N: 14.007 g/mol.

H: 1.008 g/mol.

N + H = 14.007 + 1.008 = 15.015 g/mol.

3) Divide the molar mass by the molar mass of the empirical formula

Multiply the subscripts of the empirical formula by 2.

.

Answer:

Explanation:

Here, we want to get the number of mg of the atom that would remain

Half-life refers to the time taken for exactly half the mass of a radioactive isotope to be lost to radiation

From the question, the half-life is 6 hours

During the first six hours, we have a mass of 60 mg left

In the next 6 hours, which is the second half-life, we have 30 mg left

In the next 6 hours, which is the third half-life, we have 15 mg left

Now, for the next 5 hours, there will not be a complete decay

Thus, we get the decay constant using the following:

Mathematically:

ANSWER

A. acetic acid is a weak acid

We need to determine how is the PH in the given mixtures:

A) A weak base and a strong acid:

Acid and base react to form an acidic solution and, being acidic, this results in a solution with a pH lower than 7

B) A strong base and a strong acid:

When mixing a strong base and a strong acid, neutralization occurs, that is, a neutral pH or equal to 7 is obtained

C) A strong base and acid:

If we have a weak acid, when adding a strong base the pH approaches neutrality without sudden changes, but once the acid has been neutralized, just add a few drops of excess soda to obtain a sudden increase in pH as if there were only base. free. In this case, at the equivalence point the pH> 7

ANSWER:

A) Less than 7

B) Equal to 7

C) Greater than 7

Answer:Neutron = 27 – 13 = 14. Therefore, an aluminum atom has fourteen neutrons. Based on the atomic number, mass number, and neutron number of the element, three things can be considered.

Explanation:

Answer:

A. Designing a radiation containment system

Explanation:

Engineers invent, create, design, and maintain machines, building/structures, and software data.

In this question, we have the following reaction:

6 HCl + 2 Al -> 2 AlCl3 + 3 H2

We have:

250 mL of HCl

2.5 g of Al

And we want to find the molar concentration of HCl

One way of doing it is by finding the number of moles of HCl present in this solution, we can do that by using the number of moles of Al and after that, comparing the molar ratio of HCl and Al. To find the number of moles of Al, we will use its molar mass 27g/mol

27g = 1 mol

2.5g = x moles

x = 0.0926 moles of Al in 2.5 grams

Now by looking at the properly balanced reaction, we can see that the molar ratio between HCl and Al is 6:2, so if we have 0.0926 moles of Al, we will have:

6 HCl = 2 Al

x HCl = 0.0926 Al

x = 0.2778 moles of HCl

Now that we have the volume and the number of moles, we can find the molar concentration of HCl, using the Molarity formula:

M = number of moles/volume in liters

M = 0.2778/0.250

M = 1.11 is the molar concentration of HCl in this given solution

INFORMATION:

We know that:

- 35 ml of liquid has the mass of 41.6 g

And we must find its density

STEP BY STEP EXPLANATION:

To find it, we must use the following formula

From given information:

- mass of the liquid: 41.6 g

- volume of the liquid: 35 ml

Now, replacing the values in the formula

Finally, the density of the liquid is 1.19 g/ml

ANSWER:

The density of the liquid is 1.19 g/ml

Iron is an element.

This is because Iron consists of a single type of atom.

Ibuprofen has a molecular formula of C13H18O2, meaning it has 13 carbon atoms, 18 hydrogen atoms, and 2 oxygen atoms.

The molar mass of ibuprofen (206 g/mol) is determined by adding up the atomic masses of each element in the molecule:  

C (12.01 g/mol) + H (1.01 g/mol) + O (16.00 g/mol) = C13H18O2  

Ibuprofen's percent composition (75.7% C, 8.80% H, 15.5% O) can be used to determine the number of each type of atom in the molecule:  

13 C atoms x 100% = 75.7% C  

8.80 H atoms x 100% = 8.80% H

15.5 O atoms x 100% = 15.5% O  

Thus, ibuprofen has 13 carbon atoms, 8 hydrogen atoms, and 15 oxygen atoms.

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First, we write our reaction:

Al + Cl2 ==> AlCl3

To balance a reaction similar to this one, we must focus on having the same number of atoms on each side, I mean on the left side and on the right side of the reaction.

As we can see, we have 2 Cl on the left and 3 on the right, therefore we try to have the same number of this atom, multiplying by a pair number and an odd number respectively e.g. by 3 and 2.

Al + 3 Cl2 ==> 2 AlCl3

After that, we have 6 Cl on both sides. Then, we must go on with Al, and the only thing we should do is multiply on the left by 2 because we already have 2 Al on the right side.

2 Al + 3 Cl2 ==> 2 AlCl3

With this, we will have 2 Al and 6 Cl in total

Answer: 2 Al + 3 Cl2 ==> 2 AlCl3