A bowling ball is dropped from the top of a building that has a height of h = 159 m.a) Assuming air resistance is negligible, what is the ball's speed, vf in m/s, when it strikes the ground? b) If drag produces an opposing force of 10 N while the ball's falling, what is the ball's speed, vf in m/s, when it strikes the ground? Assume the ball has a mass of 5 kg.c) A different ball was dropped and the final speed was measured to be vf = 6.5 m/s while the drag force was measured to be 50 Newtons. What is the mass of this ball in kg?

Answers

Answer 1

ANSWER:

a) 55.82 m/s

b) 49.8 m/s

c) 5.17 kg

STEP-BY-STEP EXPLANATION:

Given:

Height (h) = 159 m

Initial speed (vi) = 0 m/s

a)

We calculate the final speed using the following formula:

[tex]\begin{gathered} (v_f)^2=(v_i)^2+2gh \\ \\ \text{ we replacing:} \\ \\ (v_f)^2=(0)^2+2(9.8)(159) \\ \\ v_f=\sqrt{3116.4} \\ \\ v_f=55.82\text{ m/s} \end{gathered}[/tex][tex]\begin{gathered} (v_f)^2=(v_i)^2+2gh \\ \\ \text{ we replacing:} \\ \\ (v_f)^2=(0)^2+2(9.8)(159) \\ \\ v_f=\sqrt{3116.4} \\ \\ v_f=55.82\text{ m/s} \end{gathered}[/tex]

b)

To determine the final velocity with the opposing force, we have to determine the net force and then calculate the acceleration that would be used to calculate the velocity, like this:

[tex]\begin{gathered} F_n=mg-10 \\ \\ \text{ we replacing} \\ \\ F_n=5\cdot9.8-10 \\ \\ F_n=49-10=39\text{ N} \\ \\ F=m\cdot a \\ \\ a=\frac{F}{m}=\frac{39}{5} \\ \\ a=7.8\text{ m/s^^b2} \\ \\ \text{ Therefore:} \\ \\ (v_f)^2=(v_i)^2+2ah \\ \\ \text{ we replacing:} \\ \\ (v_f)^2=(0)^2+2(7.8)(159) \\ \\ v_f=\sqrt{2480.4} \\ \\ v_f=49.8\text{ m/s} \end{gathered}[/tex]

c)

We can calculate the mass in the following way, first, we must calculate the acceleration to be able to determine the mass:

[tex]\begin{gathered} (v_{f})^{2}=(v_{i})^{2}+2ah \\ \\ \text{ we replacing:} \\ \\ 6.5^2=0^2+2\cdot a\cdot(159) \\ \\ 318a=42.25 \\ \\ a=\frac{42.25}{318} \\ \\ a=0.133\text{ m/s^^b2} \\ \\ \text{ Now we can calculate the mass using the force balance:} \\ \\ ma=mg-50 \\ \\ a=g-\frac{50}{m} \\ \\ \text{ we replacing:} \\ \\ 0.133=9.8-\frac{50}{m} \\ \\ 1.333-9.8=-\frac{50}{m} \\ \\ -9.667m=-50 \\ \\ m=\frac{-50}{-9.667} \\ \\ m=5.17\text{ kg} \end{gathered}[/tex]


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See correct question below

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A)generator

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Answer:

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Answers

Given,

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On rearranging the equation,

[tex]a=\frac{v^2-u^2}{2d}[/tex]

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On rearranging the above equation,

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On substituting the known values,

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As per the rules, the power to 10 is always a total number of digits less than 1.

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Answers

Answer:

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Answers

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Answer:

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Explanation:

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Answer:

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G

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The SI unit of velocity is metre per/sec (m/s). as an alternative, the speed magnitude can also be expressed in centimetres per 2nd (cm/s).

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When the cell needs energy, ATP can be taken out and used to fuel reactions or stored for use in later ones.

Animals use ATP to store the energy released during food digestion. Similar to this, plants use ATP molecules to store the energy they obtain from light during photosynthesis.

The usable source of the energy that a cell uses for the synthesis of materials is ATP.

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Radio waves travel at the speed of light, 300,000 km/s (3x10^8 m/s). Determine the wavelength of a radio wave that is received at 200 megahertz.

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A wave's frequency and wavelength are connected to the wave's speed by the... The following formula can be used to determine the radio wave's wavelength.

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Write out the wave function in the form to determine a sinusoidal wave's amplitude, wavelength, period, and frequency.

How is the energy of sound determined?

Your sound will be more strong the more your sound wave oscillates.

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You swing a weight attached to a string in a vertical circle. at the top of the circle the string just barely goes slack for an instant. part a choose the correct statement for the the centripetal acceleration of the weight.

Answers

If the ball isn't travelling as swiftly as the force is pushing itself to keep it moving (in a circular motion), it will fall because gravity and tension pull downward at the top of the swing.

Speed is calculated using the distance travelled and the time needed to cover that distance. Speed is a scalar number because it just has a vector and no magnitude.You can determine something's average speed if you know how far it has travelled and how long it took to get there. One can determine speed by simply dividing by the amount of time. Stride length and cadence both affect running pace. The stride cadence is the frequency of steps taken per second, and the stride length is the distance covered by each step. Combining these factors yields a precise mathematical description of running.

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IMA=Fr’/ Fe

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a. how long will you have take to stop
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Answers

Answer:

a. 3.75 s b. 28.125 m

Explanation:

Data

Vi = 15 m/s

Vf = 0 m/s

a = -4 m/s²

i) t = ?

ii) S = ?

Solution

i) Using Newton's 1st Eq of Motion

Vf = Vi + at

t = (Vf - Vi) / a

t = (0 - 15) / -4

t = 3.75 s

ii) Using Newton's 3rd Eq of Motion

2aS = Vf² - Vi²

S = (Vf² - Vi²) / 2a

S = (0² - 15²) / 2 x -4

S = 28.125 m

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Answers

Answer:

0.36 m

Explanation:

The moment of inertial of a wheel can be calculated as

[tex]I=mr^2[/tex]

Where r is the radius of the wheel and m is its mass.

Solving the equation for r, we get

[tex]r=\sqrt[]{\frac{I}{m}}[/tex]

So, replacing I by 0.13 kg m2 and m by 0.98 kg, we get

[tex]r=\sqrt[]{\frac{0.13\operatorname{kg}\cdot m^2}{0.98\operatorname{kg}}}=0.36\text{ m}[/tex]

Therefore, the radius of the wheel is 0.36 m

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Answers

In general terms, efficiency is output/input.

For a lever, the effort is the input and load is the output.

Thus, option C is not a means to determine efficiency as effort is the input and load is the output.

In 45 seconds a car accelerates 10 m/sec? to 110 m/sec. How fast was the car going before it accelerated?

Answers

The acceleration of the car is 2.22m/s²

Acceleration is the rate at which an object's velocity with respect to time changes. They are vector quantities, accelerations.

We are given that,

The average speed of the car = V = Vf -Vi = 110m/s - 10m/s = 100m/s

The rate of car to accelerate = t = 45sec

Therefore, the acceleration of the car can be calculated as,

a =  (Vf -Vi)/t

a = (100m/s)/45sec

a = 2.22m/s²

Thus ,the acceleration of the car would be 2.22m/s².

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The Jamaican bobsled team hit the brakes on their sled so that it decelerates at
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Answer: c) all of these

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