The two cars will move together immediately after the collision at a speed of = 23 m/s
For solving this question, firstly we need to know the formula for Linear momentum,
⇒ Linear Momentum (p) = mass x velocity
⇒ p = m x v
m = body mass
v = velocity
NOTE- both cars are moving in the same direction
Car 1 weighs 2100 kg and was moving with a velocity of 25 m/s
⇒ Momentum = 2100 x 25
⇒ Momentum = 52500 kg-m/s
Car 2 weighs 1650 kg and was moving with a velocity of 21 m/s
⇒ Momentum = 1650 x 21
⇒ Momentum = 34650 kg-m/s
Total momentum before collision = 52500 + 34650
= 87150 kg-m/s
Momentum after collision = (2100 + 1650)v
= 3750v
By the law of conservation of linear momentum,
⇒ Momentum before collision = Momentum after collision
⇒ 87150 = 3750v
⇒ v = [tex]\frac{87150}{3750}[/tex]
⇒ v = 23 m/s
Therefore, The two cars will move together immediately after the collision at a speed of = 23 m/s
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A person stands 101010 meters east of an intersection and watches a car driving towards the intersection from the north at 131313 meters per second. At a certain instant, the car is 242424 meters from the intersection. What is the rate of change of the distance between the car and the person at that instant (in meters per second)?.
The rate of change of the distance between the car and the person at that instant is 12m/sec.
We have given that a person is standing 10 meters east from junction or intersection point. Now, we have given that rate of change of car from north direction as 13m/sec.
So, let assume distance of intersection point from the final point is y meters and distance of a person from final point as x meters,
Therefore, using pythagoras theorem,we get
=>y² = x² +(10)²
=>y=√(x²+100)
Now we are given rate of change of x in form of dx/dt,so on differentiating we get
=>dy/ dt = [(1/2) × (1/√(x²+100))] × (2 × x × dx/dt)
=>dy / dt =( x /√(x²+100)) × dx/ dt
Now, we are given value of dx/dt= -13m/sec. Since, distance is decreasing with time therefore dx/dt = -13m/sec.
Now, putting value of dx/dt and x=24meters,we get
=>dy /dt = (24 / √[(24)²+100]) × (-13)
=>dy /dt = (24 / √(576+100)) × (-13)
=>dy /dt = (24/26)×(-13)
=>dy/dt = -24/2
=>dy/dt = -12m/sec
Hence, rate of change of the distance is 12m/sec.
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What is the change in momentum of a car weighing 1500kg when its speed increases from 36km h to 72km h uniformly?
The change in momentum of the car is 15000 kg m/s.
Momentum is the strength gained by a moving body. It is calculated as the product of mass and velocity. Momentum is a vector quantity, which means it has both magnitude and direction.
We get the formula for calculating force from momentum from newton's second law. According to this law, " The force is equal to the time rate of change in momentum."
i.e., Force = Final momentum - initial momentum/ time
In the given question, we have to find a change in momentum
i.e. Force = Final momentum - initial momentum/ time
In the given question, we have to find change in momentum
Δp = [tex]M_{2[/tex][tex]V_{2[/tex] - [tex]M_{1[/tex][tex]V_{1[/tex]
= M ( [tex]V_{2[/tex] - [tex]V_{1[/tex])\
= 1500 (72-36) ×5/18
= 1500×2×5
= 15000 kg m/s
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two metal spheres connected by a metal rod stand on plastic supports. initially the spheres and metal rod do not hold any charge. a charged plastic rod with q (q>0) is placed near the sphere on the right without touching it. then, the metal rod connecting the spheres is removed. finally, the initially charged plastic rod is taken away. at this point: a. spheres attract one another b. spheres repel one another c. spheres do not exert a force on one another d. not enough information
When two metal spheres joined by a metal rod stand on supports made of plastic, the spheres are drawn to one another.
Option a is correct
What occurs when a negatively charged rod comes into contact with a metal sphere?When a negative rod is introduced close to an uncharged metal sphere, the electrons in the sphere are forced to travel to the opposite side of the sphere from the side that is closest to the rod.
What happens if two metallic spheres come in contact?When the two conducting spheres are brought close enough to contact, it appears as though they merge into a single, large conductor, and the combined charge of the two spheres is distributed evenly throughout their whole surface. until the spheres have been separated once more.
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how does the difference between the ranges of the strong nuclear force and the coulomb force affect the makeup of each atom’s nucleus?
Because the coulomb force has a wider field of influence and heavier atoms have more neutrons than protons.
Strong nuclear force :
The strong nuclear force is represented by the force that holds protons and neutrons in atoms' nuclei. the things that are heavier than an atom of hydrogen. the center of the fusion of hydrogen and helium in the sun. The strong interaction, commonly referred to as the strong nuclear force, constrains quarks into proton, neutron, and other hadron particles. Neutrons and protons are held together to form atomic nuclei by the nuclear force, often known as the strong interaction. Heavier atoms have more neutrons than protons because the Coulomb force's range is larger. Protons and neutrons are joined together to form atomic nuclei by the nuclear force, also referred to as the strong interaction.
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what force does the water exert (in addition to that due to the atmospheric pressure) on a submarine
The water that is displaced produces buoyancy, an upward force. As opposed to gravity, which would pull the ship downward, buoyancy acts in the opposite manner.
When the mass of water that the submarine displaces (pushes out of the way) equals the mass of the boat, the submarine (or any boat) can float. The deeper surface is under more pressure. The important thing to keep in mind is that regardless of the depth of the submerged submarine is at, the pressure differential between higher and lower surfaces is always the same since water is incompressible (for all practical purposes here). You mentioned a push, and that contributes to the net buoyancy. To overcome its buoyancy, the submarine must allow water into its ballast chambers. The submarine will need to make modifications while below, adding or "blowing" ballast water to make up for changes in the water's density brought on by temperature or salinity changes, in order to maintain constant depth.
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which 'energy system' is utilized during very high intensity, shorter exercise, like sprinting a 400 m?
The energy system utilized during high intensity sprint is glycogen stored in muscles.
Sprinting burns a ton of calories, improves cardiovascular fitness, develops muscle, and increases speed and power. To step up your training, incorporate them into your program.
Additionally, sprint exercises save a lot of time. Even though up to 60 minutes of moderate exercise should be performed three times each week, most people don't get that much exercise for a variety of reasons, including a lack of time.
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what is the rest energy of an electron, given its mass is 9.11 x 10-31 kg? give your answer in joules and mev. (1 mev
The rest mass of the electron is 8.199 x 10⁻¹⁴ Joules or 0.511 MeV.
What is relativistic kinetic energy?The relativistic kinetic energy equation demonstrates how an object's energy increases as its velocity approaches the speed of light. In order to accelerate an object across this boundary is therefore impossible. The mass-energy equivalence formula is Erest=E0=mc2, which is derived from calculations of kinetic energy.
Relativistic kinetic Energy:
The relativistic energy of a particle with mass m, can be found using the following equation
Krel= (γ-1) mc²
It is given that the mass of the electrons is 9.11 x 10⁻³¹kg, thus we have
m = 9.11 x 10⁻³¹kg
it is required to find the rest mass of the electron,
mc² = ?
Knowing the mass of the electron, we can find the rest mass of the electron,
as follows
mc² = 9.11 × 10⁻³¹ × (3 × 10⁸) ²
mc² = 8.199 x 10⁻¹⁴Joules
And, to convert from energy units of joule to eV, we divide by the electron charge, thus we have = 8.199 x 10⁻⁴/1.6 x 10⁻¹⁹= 511741.376 eV
511741.376 eV ≈ 0.511 MeV
Thus, the rest mass of the electron is 8.199 x 10⁻¹⁴ Joules or 0.511 MeV.
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a 550 kg satellite is in a circular orbit at an altitude of 400 km above the earth's surface. because of air friction, the satellite eventually falls to the earth's surface, where it hits the ground with a speed of 2.20 km/s. how much energy was transformed into internal energy by means of air friction?
The energy was transformed into internal energy by means of air friction is equal to 1.2789 × 10⁹J.
What is the law of conservation of energy?According to the law of conservation of energy, energy can be transformed from one to another but it is not possible to create or destroy it. Energy happens in nature in various forms such as heat, chemical energy, electricity, nuclear energy, and so on.
The sum of the potential energy and kinetic energy before and after are equal.
PE₁ + KE₁ = PE₂ + KE₂ + Qₙ
where Qₙ is the heat energy.
The kinetic energy at the initial stage is zero.
PE₁ = PE₂ + KE₂ + Qₙ
[tex]\displaystyle -(\fracGMm}{R+h} ) =-(\frac{GMm}{R} ) +\frac{1}{2}mv^2 +Q_f[/tex]
[tex]\displaystyle Q_f = (\frac{GMm}{R} ) - (\frac{GMm}{R+h} ) -\frac{1}{2}mv^2[/tex]
[tex]\displaystyle Q_f = {6.67\times 10^{-11}\times 5.98\times 10^{24}\times 550}[(\frac{1}{6.371 \times 10^6} ) - (\frac{1}{6.371 \times 10^6 +400\times 10^3} )] -\frac{1}{2}(550)(2200)^2[/tex]
Heat energy = 1.2789 × 10⁹J
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which electromagnetic radiation wavelength is efficiently observed using ground based telescopes?
Simply said, radio is a wavelength of electromagnetic radiation that is well suited for ground-based telescope observation.
How do you calculate wavelength?The distance between any two identical locations on adjacent waves may always be used to calculate the wavelength. When dealing with a longitudinal wave, the distance between one compression and the next or between one rarefaction and the next is used to calculate the wavelength.
Describe the wavelength.The distance between two identical points (adjacent crests) in consecutive cycles of a waveform signal's journey through space or over a wire is known as the wavelength. Wireless systems frequently use meters (m), centimeters (cm), or millimeters (mm) to represent this length (mm).
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in order to keep a small satellite from drifting into a nearby asteroid, it is placed in orbit with a period of 3.02 hours and radius of 2.0 km. what is the mass of the asteroid?
The mass of the asteroid is 4×10^13 kg.
What is orbital period?The amount of time it takes an astronomical object to complete one orbit around another object is known as the orbital period.
Given that orbital period: T = 3.02 hour
= 3.02*3600 second
= 10872 second.
Radius of orbit = 2.0 km = 2.0*1000 m.
Let the mass be M.
Again we know that: the relation among time period and radius of orbit is given by:
T² = 4π²R³/GM
M = 4π²R³/GT²
= { 4π²(2.0*1000)³/(6.67× 10^-11 × 10872²)}
= 4×10^13 kg.
Hence, the mass of is 4×10^13 kg.
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which method of measuring distances would you use if you wanted to measure the distance to stars in a nearby galaxy?
parallax To calculate the distances to nearby stars, astronomers employ a phenomenon known as parallax.A apparent relocation of an object due to a change in the writer's point of view is known as parallax.The closest star is Alpha Centauri.
How does NASA calculate the length of a spacecraft?Lightyears.A lightyear, or the distance light travels in a year (about 9.5 trillion km), is a unit of measurement used to describe distance in space.
Which of the following is the most effective way to calculate how far away a star is?Trigonometric parallax, also known as star parallax, is a technique used by astronomers to calculate the distances of nearby celestial objects.
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If the altitude of the North Star is 30º above the horizon, then what is the highest altitude that the Sun will reach during the Autumnal Equinox:
__________degrees
If the altitude of the North Star is 30º above the horizon, then the highest altitude that the Sun will reach during the Autumnal Equinox: is 60 degrees
What is the Autumnal Equinox?The sun shines squarely on the equator at the autumnal equinox, giving both the northern and southern hemispheres an equal quantity of sunlight.
The start of the fall season is signaled by the autumnal equinox, a natural occurrence that takes place in late September every year. The celestial equator coincides with the equator of Earth, such that day and night are of equal length.
It would be 30 degrees north latitude if you could see Polaris at 30 degrees above the horizon. Now, if a star reaches its highest point at a place below the observer's zenith, its latitude is equal to 90 - star altitude.
90 - 30 = 60 degrees
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a structure containing a central atom surrounded by three electron groups will have a planar arrangement in which the ideal bond angle is °.
Trigonal, 120 degree, the ideal bond angles are 120° when there are three electron domains encircling an atom.
What are the optimal bond angles surrounding an atom with a three electron group in the center?The ideal bond angles are 120° when there are three electron domains encircling an atom, which results in trigonal planar electron domain geometry. An atom's surrounding electron domain geometry is tetrahedral if there are four of them.One way to visualize the trigonal bipyramidal shape is as a set of three bonds in a trigonal planar arrangement separated by bond angles of 120° (the equatorial positions), and two additional bonds at an angle of 90° to this plane (the axial positions):To learn more about Ideal bond angles refer to:
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suppose a particle called a kaon is created by cosmic radiation striking the atmosphere. it moves by you at 0.980c and it lives 1.24 x 10-8 s when at rest relative to an observer. how long does it live as you observe it?
In relation to an observer, it takes 2.3727*10^-8 seconds at rest. to exist as you see it. Because cosmic radiation that strikes the atmosphere produces a particle known as a kaon.
Radiation from space is one natural source of radiation. High-energy charged particles, x-rays, and gamma rays are all components of cosmic radiation, which are created in space. The earth receives secondary radiation that is created when charged particles interact with the atmosphere. The stars, including our own sun, emit cosmic radiation. A particle is a small, localized item that can have many physical or chemical qualities, such as volume, density, or mass. The term particle—or corpuscule in older texts—is used in the physical sciences. The size or number of them varies widely.
T = t/(1-(v^2/c^2)
^1/2 = 1.375*10^-8/0.5795
T = 2.3727*10^-8sec
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two ice skaters of equal mass grab hands and spin in a circle once every four seconds. their arms are 0.76 m long, and they each have a mass of 55.0 kg. how hard are they pulling on one another?
The force applied to pull on one another is 102.48 N.
Mass of skaters = m = 55 Kg
Length of arms = r = 0.76 m
Time period = 4 s
Force applied to pull one another is = F =
= F = centripetal force
= F = (m X v²) / r
The centripetal force exerts on a body at the time of circular path, which acts towards the centre of a circular path, and It is inverse of radius as more radius has the least centripetal force.
First, the velocity of the skaters is = v =
= v = distance / time
= v = ( 2 X π X r ) / t
= v = ( 2 X π X 0.76 ) / 4
= v = 1.19 m/s
Now,
Force applied to pull one another is = F =
= F = centripetal force
= F = (m X v²) / r
= F = ( 55 X 1.19²) / 0.76
= F = 102.48 N
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a 70-kg person rides in a 30-kg cart moving at 12 m/s at the top of a hill that is in the shape of an arc of a circle with a radius of 40 m. (a) what is the apparent weight of the person as the cart passes over the top of the hill? (b) determine the maximum speed that the cart may travel at the top of the hill without losing contact with the surface. does your answer depend on the mass of the cart or the mass of the person? explain.
The apparent weight of the person as the cart passes over the top of the fill for question A is 470N.
The maximum speed that the cart may travel at the top of the hill without losing contact with the surface from question B is 19.8 m/s.
Based from the question above, we will approach using centripetal force to answer question A, and centripetal acceleration to answer question B.
It is a force that makes a body follow a curved path. Its direction is always orthogonal to the motion of the body and towards the fixed point of the instantaneous center of curvature of the path.
Now, let's calculate question A about the apparent weight of the person as the cart passes over the top of the hill.
Given from the question
mass of the person = 70kg
weight of the person will be = mass * earth gravity
= 70 * 9.8
= 686N
Radius of the circle of which the arc is a part = r = 40m
speed of the cart = 12 m/s
The centripetal force on the person =
Fc = mass * ((cart speed (v))^2 / radius of the circle (r))
= 75 * (12^2/50)
= 216N
from here, apparent weight can be calculate below :
R (apparent weight) = weight - centripetal force (Fc)
= 686 - 216
= 470N
Therefore, the answer of question A, the apparent weight of the person as the cart passes over the top of the hill is 470N
Now, moving on to question B. The person can have a maximum speed when the centripetal acceleration is equal to the acceleration due to gravity.
Vmax = √r (radius) * g (gravity)
= √40 * 9.8
= √392
= 19.8 m/s (rounded)
Therefore, the maximum speed of the cart at the top of the hill without losing contact with the surface is 19.8m/s. This answer also depends on the radius of the circular path and velocity of the cart.
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consider position b, and then solve the following problem. assume the angle to the vertical line for position b is 45 degrees. now also assume that the main muscle that holds the arm in position is the deltoid muscle, represented by a red arrow. the angle of the deltoid muscle is 15 degrees and its distance to the center of rotation is 17 cm. if the cog for the arm is 38 cm from the center of rotation, and its weight is 35 n, what is the force that the deltoid muscle must exert to keep the arm stationary in 45 degrees position?
The amount of Force required by the deltoid muscle to maintain the arm still in the 45-degree position 131.33 N.
How much pressure is applied to the forearm by the biceps muscle?As a result, the weight being supported is 7.38 times heavier than the force being applied by the biceps. The angle between the forearm and upper arm in the biceps muscle illustration above is 90°.
Calculation:
Force = 35N
Distance = 17 m
degree of angle = 45
F = Mass × acceleration
35 N = Mass × 9.8
Mass = 35 / 9.8
Mass = 3.57
considering position b at angle 45W = F ×d × cos∅
W = 35 × 17 × cos45°
W = 35 ₓ 17ₓ 0.70
W = 416.5 joule
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What is the new orbital speed after friction from the earth's upper atmosphere has done −7. 5×109J of work on the satellite?
The new orbital speed after friction from the earth's upper atmosphere is 8674.15 m/s.
When the work done by a force does not depend on the choice of path, the force is called the conservative force. Some examples are a gravitational force, elastic spring force and electric force. On the other hand, when the work done by a force relies on the choice of the path of the motion, it is called non-conservative force.
The net work done by non-conservative force is W = ΔK + ΔP ----(1)
Given that, work done W = -7.5 * 10⁹ J
Change in kinetic energy = (Kf - Ki)
Final kinetic energy Kf = 1/2* m * Vf²
Initial kinetic energy Ki = 1/2* m * Vi²
Mass of the satellite m = 848 kg
Vf = Final speed
Vi = Initial speed = 9640 m/s
Change in gravitational potential energy ΔP = 0
Substituting the values in (1),
1/2* m (Vf² - Vi²) = W
1/2 * 848( Vf² -9640²) = W
Making Vf as subject,
Vf = √( 2W/m + Vi²)
⇒ √( -2* 7.5 * 10⁹/848 + 9640²)
⇒ 8674.15 m/s
Thus, the final speed decreases due to friction.
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in which case will more current flow through the battery: when three identical resistors are connected in series with the battery, or when the same three resistors are connected in parallel with the battery.
More current will flow through the battery when the same three resistors are connected in parallel.
Equivalent resistance when the three equal resistors are connected in parallel is R eq = R/3
We know that, according to ohm's law, V = i * R eq
where, V is the voltage
i is the current
R eq is the equivalent resistance
We know that, voltage is same across the circuit of three resistors connected in parallel.
Now, substituting R eq in the above equation, we have
i = V/ R eq = V/ (R/3) = 3* V/R
Thus, more current flows through the same three resistors which are connected in parallel.
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what type of vision allows the eyes to detect color? group of answer choices scotopic vision photopic vision both niether
The type of vision that allows the eyes to detect color is photopic because it contains rods which is sensitive to colors.
Because the prefix "tri" denotes three and the root "chroma" denotes colour, the term "trichromatic" describes something that has three colours. The retina has three different colour receptors, in accordance with the trichromatic hypothesis of colour vision. Color vision is provided by the cones in the retina.The cones are sensitive to the shades of green, blue, and red, according to this theory. When these colours are blended, eyes can distinguish between millions of different colours. The original proponents of this idea were Thomas Young and Hermann von Helmholtz. Thomas Young was the first to propose that the human eye contains three colour receptors: short, medium, and long, each of which is sensitive to a different range of light wavelengths.
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a mass m at the end of a spring oscillates with a frequency of 0.83 hz. when an additional 680-g mass is added to m, the frequency is 0.60 hz. what is the value of m? .
The value of m, which is a mass at the end of a spring that oscillates with a frequency of 0.83Hz, that been added with 680g to the mass with frequency 0.60Hz is 0.74 kg.
What is oscillation?It is a repetitive or periodic variation, typically in time, of some measure about a central value or between two or more different states. As an example, swinging pendulum and alternating current are represents oscillation.
let's use the relation between frequency and mass.
f = 1 / 2π * √k/m
where f = frequency
m = mass
k = spring constant
(2πf)^2 = (√k/m)^2
(4 * π^2 * f^2) * m = (k/m) * m
divided both side with 4 * π^2
m * f^2 = k / 4 * π^2
because k / 4 * π^2 is constant, we will leave that out from the equation
Now, let's try to answer the value of m
m * f1 ^2 = m * f2^2
m * 0.83^2 = (m + 0.68) * 0.6^2
0.6889m = 0.36m + 0.2448
0.3289m = 0.2448
m = 0.74kg
Therefore, the mass m at the end of a spring that oscillates with a frequency of 0.83Hz is 0.74kg.
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describe a series circuit. include in your description the current path and the magnitude of the current in each load
A series circuit is a closed circuit in which the current follows one path. Current path is a path by which the electrical current flows. Magnitude load is P is for a force acting on a position, along a line, or across an area. M is for bending moments acting on a position or along a line.
Which describes a series circuit?The fact that the same current flows through every component in a series circuit is what distinguishes it from other types of circuits. The current can only move in one direction.
Every component in a series receives the same amount of current. The sum of all resistances constitutes the total resistance. The total applied voltage is equal to the sum of all voltage drops.
A series circuit's overall current equals the current flowing through any resistance in the circuit. Through every circuit resistor, the overall circuit current would stay constant.
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a 100-turn loop antenna of radius 20 cm operating at 10 mhz in air is to give a 50 mv/m field strength at a distance 3 m from the loop. determine (a) the current that must be fed to the antenna (b) the average power radiated by the antenna
a) I₀ = 90.71 μA
b) Prad = 0.25mW
a) To find the current that must be fed to the antenna,
λ = c/f
λ = 3 X 10 ⁸/ 100 X 10 ⁶
λ = 3 m
Emax = ηπI₀S/ r λ²
I₀ = Emax r λ²/ ηπS
I₀ = 50 X 10 ⁻³X 3 X3²/ 120 η (0.2) ² X 100
I₀ = 90.71μA
b) The average power radiated by antenna,
Rrad = 320π⁴S/ λ⁴
= 60.77 KΩ
Prad = 1/2 I₀Rrad
Prad = 0.25mW
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if you know all of the forces acting on an object and you know the mass of that object, what quantities can you figure out from that information?
When we are aware of all the forces operating on an object and its mass, we can use those two pieces of knowledge to calculate the object's acceleration.
Newton's first law of motion and the second law of motion are closely related. The causal relationship between force and modifications in motion is expressed mathematically.
More quantitative, and frequently used to determine what happens when a force is applied, is Newton's second law of motion. We need to clarify a few concepts before we can write out Newton's second law as a straightforward equation expressing the precise relationship between force, mass, and acceleration.
a = Fnet / m
That is
Fnet = m • a
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Calculate the time t for the pencil to hit the ground, assuming that it falls from standing perfectly vertical and maintains this angular acceleration.
The angular acceleration when the pencil is 10° from the vertical is 17 rad/s². The time for the pencil to hit the ground is 0.43 s.
Look at the attachment for the complete question. The weight of the pencil is in the middle of it. When the pencil has an angle of 10.0° from the vertical
The force that applies is the weight force.When the pencil hit the ground
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a monochromatic light beam is incident on a barium target that has a work function of 2.50 ev. if a potential difference of 1.00 v is required to turn back all the ejected electrons, what is the wavelength of the light beam?
The wavelength of the monochromatic ligh beam in this case was found to be 497nm
what is monochromatic light ?
Monochromatic lights are single-wavelength lights, with mono denoting single and chroma denoting colour. Monochromatic lights are visible light with a small band of wavelengths. It has a wavelength in the short wavelength region. These lights are characterised by their intensity or brightness, colour, propagation direction, and polarisation condition.
Monochromatic Light's Source and Applications
The LASER is a well-known source of monochromatic light. The acronym LASER stands for Light Amplification By Stimulated Emission Of Radiation. A laser light is produced by a single atomic transition with a single wavelength, resulting in a monochromatic light beam.
work function = 2.50 eV
V0 = 1.00 eV (the stopping potential.)
Electron charge, e = 1.6 x 10^-19 C
Light speed, c = 3 x 10^8 m/s
h = 6.63 10^-34 Js = 4.14 10^-15 eVs (Planck's constant.
The photoelectric equation of Einstein is provided by:
= E - ϕ ——- (1) represents the greatest kinetic energy.
E is the absorbed photons' energy: E = hf
is the surface's work function: ϕ = hf₀
The potential difference necessary to return all expelled electrons is known as the Stopping Potential (V0).
——-
(2) is substituted for (1)
eV₀ = E - ϕ
1.6 x 10⁻¹⁹ x 1 = E - 2.50
E = 1.6 x 10⁻¹⁹ + 2.50
E = 2.50 eV
E = hf = hc/λ
λ = (4.14 × 10⁻¹⁵ × 3 x 10⁸) / 2.50
λ = 1240 × 10⁻⁹ / 2.50
λ = 496.8 × 10⁻⁹ m
λ = 497 × 10⁻⁹ m
λ = 497 nm
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find the binding energy of carbon-12 per nucleon. the mass of a proton is 1.007276 u, of a neutron 1.008665 u, and of carbon 11.996706 u.
Binding energy per nucleon of carbon 12 is 7.94 MeV
Carbon 12 contains 6 proton , 6 neutron and 6 electron hence, calculated atomic mass of carbon 12
= 6Mp+6Mn +6Me
=6 × 1.007 + 6 ×1.008 + 6× 0.00055
=12.102
∴ mass defect = 12.102 -12.000 = 0.102 amu
binding energy = 0.102 ×931 = 95.30 MeV
binding energy per nucleon = 95.30\12 = 7.94 MeV
What is the binding energy for each nucleon?
The least amount of energy necessary to separate or break down an atom’s nucleus into the subatomic particles that make it up is known as nuclear binding energy (which are protons and neutrons)
How is nuclear binding energy determined?
The nuclear binding energy can be determined once the mass defect is known by converting that mass to energy using the formula. E b = ( Δ m ) c 2. ...
Verify that the mass is expressed in kilogram's (kg).
Once the obtained energy is known, it can be scaled into amounts per nucleon and per mole.
What does it signify when a nucleon's binding energy is high?
Binding energy is required to keep nucleons together as a nucleus. One of the most stable elements is iron, which has a mass number of 56. We refer to iron as having a high nucleon-binding energy. Less stable elements are those with a lower and higher mass number per nucleon.
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A mass is connected to a spring and is allowed to move horizontally. The mass is at a position L when the spring is unstretched. The mass is then moved, stretching the spring, and released from rest. It then moves with simple harmonic motion.
1. At the instant that the mass passes through the position where the spring is unstretched, what can be said about its instantaneous acceleration?
2. At the instant that the mass passes through the position where the spring is unstretched, what can be said about its instantaneous speed?
3. At the instant that the spring is compressed the most, what can be said about the magnitude of its instantaneous velocity?
a) Acceleration is zero
b) Speed is zero
a) The equation of the simple harmonic motion is
x = A cos (wt +φ)
where
A = amplitude of the movement,
w= angular velocity and
φ = phase
Body acceleration is
a = d²x / dt²
dx / dt = - A w sin (wt + φ)
a = d²x / dt² = - A w² cos (wt + φ)
when it is not stretched x = 0
The spring is released at maximum elongation, φ = 0
0 = A cos wt
Cos wt = 0
wt = π / 2
a = -A w² cos π/2 = 0
Acceleration is zero
c) When the spring is compressed x = A
Speed (v) = dx / dt
v = - A w sin wt
A = A cos wt
cos wt = 1
wt = 0, π
v = -A w sin 0 = 0
Speed is zero
Complete question:
A mass is connected to a spring and is allowed to move horizontally. The mass is at a position L when the spring is unstretched. The mass is then moved, stretching the spring, and released from rest. It then moves with simple harmonic motion. (a) At the instant that the mass passes through the position where the spring is unstretched, what can be said about its instantaneous acceleration? Grade Summary It is maximum. OIt is zero It is non-zero but not maximum Potential per attempt) Hint I give up 1% -ム33%Part (b) At the instant that the spring is compressed the most, what can be said about the magnitude of its instantaneous velocity?
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a mass is connected to a spring and is allowed to move horizontally. the mass is at a position l when the spring is unstretched. the mass is then moved, stretching the spring, and released from rest. it then moves with simple harmonic motion.
The instantaneous acceleration is zero when the mass passes through the position where the spring is unstretched.
What is acceleration?The equation that governs simple harmonic motion is as follows:
x = A cos (wt +φφ)
Where A is the movement's amplitude, w is the angular velocity, and the initial phase φ is determined by the initial condition.
The body accelerates.
a = d²x / dt²
Look for the derivatives.
dx / dt = - A w sin (wt + φ)
a = d²x / dt² = - A w² cos (wt + φ)
When it is not stretched, x equals 0.
When the spring is at its maximum elongation, φ = 0
0 = A cos wt
Cos wt = 0 wt = π / 2
This angle accepts acceleration.
a = -A w² cos π/2 = 0
Therefore acceleration is zero
x = A when the spring is compressed
Then the speed is
v = dx / dt
v = - A w sin wt
We are looking for time.
A = A cos wt
cos wt = 1 wt = 0, π
For this period, the quick vouchers
v = -A w sin 0 = 0
The speed is zero.
The complete question:
" A mass is connected to a spring and is allowed to move horizontally. The mass is at a position L when the spring is unstretched. The mass is then moved, stretching the spring, and released from rest. It then moves with simple harmonic motion. (a) At the instant that the mass passes through the position where the spring is unstretched, what can be said about its instantaneous acceleration? Grade Summary It is maximum. OIt is zero It is non-zero but not maximum Potential per attempt) Hint I give up. Part (b) At the instant that the mass asses through the position where the spring is unstretched, what can be said about its instantaneouPart (c) At the instant that the spring is compressed the most, what can be said about the magnitude of its instantaneous velocity?"
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an electromagnetic wave with a peak magnetic field magnitude of 1.50 10-7 t has an associated peak electric field of what magnitude?
45 V/m is the corresponding maximum component of the related peak electric field.
Given:
Electromagnetic pulse with a maximum magnetic field strength of [tex]1.5 * 10^{-7}[/tex]T
The following is the relationship between the magnetic and electric fields:
E = B × c,
where c = [tex]3 * 10^{8}[/tex] m/s.
[tex]E = (1.5 * 10^{-7}) * (3 * 10^{8})[/tex]
= 45 V/m
Electric fields are created by magnetic fields that are changing and electric charges.
With an electric charge or a collection of charges, an electric field will also exist. Any charged object placed in this field will experience an electrostatic attraction as a result of the field's interactions with the charge of the object. Field lines show the force that would act on a positively charged particle at that instant if it were within the field.
In the end, charge transport results in the development of magnetic fields. The magnetic field surrounding the straight wire may be seen as electricity passes across it. Motors and even computer data storage are also powered by this phenomenon.
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