a 1.25 kg block is attached to a spring with spring constant 17.0 n/m . while the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 46.0 cm/s .The amplitude of the subsequent oscillations 48.13 cm/s
a 1.25 kilogram block is fastened to a spring with a 17.0 newtons per meter spring constant. Given that K is equal to 14 Newtons per meter and mass equals 10.5 kg. The block is then struck with a hammer by a student while it is at rest, giving it a speedo of 46.0 cm for a brief period of time. The required energy provided by the hammer, which is half mv squared, is transformed into potential energy as a result of the succeeding oscillations. This is because we know that energy is still available for consultation. So access the amplitude here from here. He will therefore be equal to and by. Consequently, the Newton's spring constant is 14 and the value is 10.5. The velocity multiplied by 0.49
Speed at X equals 0.35 into amplitude, or vice versa. At this point, the spirit will equal half of K X 1 squared plus half. Due to the fact that this is the overall energy, square is equivalent to half of a K square or an angry square. amplitude is 13 and half case 14 x one is 0.35. calculate that is equal to initial velocities of 49 squares and masses of 10.5. This will be divided in half and start at about 10.5 into the 49-square-minus-14. 13.42 into the entire square in 20.35. dividing by 10.5 and taking the square as a result. 231 6.9 Six centimeters per square second. 10.5 into 49 sq. 14. 2 into a 13.42 square entire. then subtract 10.5 from the result to get the square. So that is 48.13cm/s.
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This is incomplete question Complete Question is:
a 1.25 kg block is attached to a spring with spring constant 17.0 n/m . while the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 46.0 cm/s . what are The amplitude of the subsequent oscillations?
. unpolarized light is incident upon a smooth surface. when light reflected from this surface is totally polarized, the incident light angle is named the
Brewster's angle
When unpolarized light is incident at Brewster's angle on a smooth glass surface, the reflected light is totally polarized while the refracted light is partially polarized
Polarization:
Polarization is a assets making use of to transverse waves that specifies the geometrical orientation of the oscillations. In a transverse wave, the route of the oscillation is perpendicular to the direction of motion of the wave.In contrast, for longitudinal waves, such as sound waves in liquids or gases, the particles are always displaced in the direction of propagation during oscillation, so these waves have no polarization. Transverse waves that indicate polarization include electromagnetic waves such as light and radio waves, gravitational waves, and sound waves in solids (transverse waves).
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what pressure does light emitted uniformly in all directions from a 200-w incandescent light bulb exert on a mirror at a distance of 5.0 m?
The pressure exerted on the mirror by the light emitted from the 200-w incandescent light bulb is negligible. This is because the pressure exerted by light is proportional to the intensity of the light .
and the intensity of the light drops off as the square of the distance. At a distance of 5.0 m, the intensity of the light is extremely low, and thus the pressure is practically zero.
Step 1: Calculate the intensity of light:
We know that the power of the light bulb is 200 W, so the intensity of light is given by:
I = P/4πd2
Where P is the power of the light and d is the distance from the light to the mirror.
In this case, we have:
I = 200 W / 4π(5.0 m)2
I = 0.0025 W/m2
Step 2: Calculate the pressure exerted by the light on the mirror:
We know that the pressure exerted by the light on the mirror is given by:
P = I/c
Where I is the intensity of the light and c is the speed of light.
In this case, we have:
P = 0.0025 W/m2/3.00 x 108 m/s
P = 8.3 x 10-10 N/m2
Therefore, the pressure exerted by the light emitted from the 200-w incandescent light bulb on a mirror at a distance of 5.0 m is 8.3 x 10-10 N/m2.
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The magnitude, m, of an earthquake is represented by the equation m=23logee0 where e is the amount of energy released by the earthquake in joules and e0=104.4 is the assigned minimal measure released by an earthquake. which equation could be used to find the amount of energy released by an earthquake with a magnitude of 2.7?
An earthquake's energy output when it has a magnitude of 2.7 is 4.5 × [tex]10^{12}[/tex].
The magnitude of an earthquake is the most common indicator of its size. It serves as a barometer for the size of an earthquake's single source. Because it is the same no matter where and how you see it, the following calculation may be done:
magnitude, M = 2 ÷ 3 log(E ÷ [tex]E_{0}[/tex])
Where E is the power generated in Joules and M is the lowest magnitude emitted by such an earthquake, [tex]E_{0} = 10^{4.4}[/tex].
Assuming 5.5, the same magnitude is provided when the preceding equation is used:
M = 2 ÷ 3 log(E ÷ [tex]E_{0}[/tex])
5.5 = 2 ÷ 3 log(E ÷ [tex]E_{0}[/tex])
8.25 = [tex]log(\frac{E}{10^{4.4}})[/tex]
[tex]10^{8.25}[/tex] = [tex]\frac{E}{10^{4.4}}[/tex]
E = [tex]10^{4.4}[/tex] × [tex]10^{8.25}[/tex]
E = 4.5 × [tex]10^{12}[/tex]
Therefore the final answer is 4.5 × [tex]10^{12}[/tex].
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a personal foul occurs when a player has unsportsmanlike conduct, illegal entry or excessive timeouts.
a. true
b. false
Answer:
true
Explanation:
basic sports knowlegde
an athlete at the gym holds a 3.0 kg steel ball in his hand. his bio arm is 70 cm long and has a mass of 4.0 kg. what is the magni- tude of the torque about his shoulder if he holds his arm a. straight out to his side, parallel to the floor?
The magnitude of the torque about an athlete shoulder is 48.02N-m if he is holding steel ball in his hand.
We know that torque is defined as the cross product of distance of point from applied point to the force applied by the external source at that point, in other words
Torque=distance × Force
=>τ = r × F
Total mass hold by the athlete is = 3+4=7kg.
Now, we need to focus on the force acting on an athlete. So we are assuming an athlete is standing on the surface, so acceleration due to gravity have some role to exert some amount of force on athlete.
Therefore, Force=mg
=>F=7×9.8
=>F=68.6Kg-m/sec²
Now, distance of force from applied point is 70cm=0.7m
Therefore, Torque=0.7×68.6
=>Torque= 48.02N-m
Hence, value of Torque is 48.02N-m.
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What is the change in internal energy AU for a reaction that gives off 65 J of heat and does 38 J of work?
The change in internal energy will be 27J when heat is released.
Every time a process occurs, it is usually accompanied by an energy shift. Energy comes in many forms, such as heat, light, and work.
The generation or absorption of energy in various processes dictates that each substance must be associated with a certain amount of energy. Its actual value depends on the nature of the material and the conditions of temperature, pressure, volume and composition.
The sum of various types of energy associated with atoms and molecules, such as electronic energy (Ee), nuclear energy (En), chemical bond energy (Ec), potential energy (Ep), and kinetic energy (Ek). Sum of translational energy (Et), vibrational state energy (Ev), and rotational energy (Er).
Represented by the symbol U or E.
U or E = Ee + En + Ec + Ep + Ek
The energy stored in matter in this way is called internal energy.
U=65-38=27J
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1. suppose a spaceship which is traveling at c/2 passes a light source. what is the velocity of light from the source in the reference frame of the spaceship?
The speed of light from the source in the spacecraft's frame of reference is given by the formula Ux = Ux+v/C2+2Uxv/C2. The pace at which an object's position changes in relation to a frame of reference.
And is a result of time. An object's speed and direction of motion are specified by its velocity. A crucial idea in kinematics is velocity. Two different categories of frame of reference are as follows: An object that is fixed or moving at a constant speed is said to have an inertial frame of reference. The First Law of Motion of Newton is directly relevant in this frame. The frame of reference refers to the context in which an observer is placed when recording data.
Ux = Ux+v/C^2+Uxv/C^2
here, c =c/2
Ux = Ux+v/C^2+2Uxv/C^2
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radio waves travel at a speed of 1.7x10^8 m/s through ice. A radio wave pulse sent into antarctic ice reflects off earth at the bottom and returns to the surface in 32.9x10^-6 s. how deep is the ice?
Then the depth of the ice is 26.55 x 10¹² m
Let speed of the radio wave be represented as 'v'
Let frequency of the radio wave be represented as 'f'
Let distance of the radio wave be represented as 's'
Let time period of the radio wave be represented as 't'
From the formula for distance:
v=s/t
v= s x 1/t
Frequency is the inverse of time period. So, 1/t in the above formula can be replaced by f.
v = s x f
putting values in the above equation
t = 32.9 x 10⁻⁶ s
v = 1.7 x 10⁸ m/s
The, f = 1/t
f = 1/3.2 x 10⁻⁶ s⁻,
So,
s = 1.7 x 10⁸ x 1/3.2 x 10⁻⁶
= 1.7/3.2 x 10⁸⁺⁶
= 0.531 x 10¹⁴
= 53.1 x 10¹²
Then the depth of the ice would be s/2 as the distance is covered twice by the wave in the given time frame.
Depth of ice = 53.1 x 10¹²/2
Depth of ice = 26.55 x 10¹² m
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Some students were on a tour exploring the inside of a cave. While the students were in the cave, they realized they heard an echo every time that they spoke. Which MOST likely caused the echo to occur?
A. the accumulation of the sound waves
B. the diffraction of the sound waves
C. the refraction of the sound waves
D. the reflection of the sound waves
A group of kids were taking a tour and looking inside a cave. The pupils in the cave soon learned that every time they spoke, there was an echo. i.e. (D). the reflection of the sound waves is correct option.
Acoustic waves are reflected by solid surfaces like walls and fences as well as by mountains. Reflection can be attributed to a break in the propagation medium. This can be heard when the reflection returns with sufficient magnitude and lag to be audible. The term "reverberation" refers to an echo that has experienced many reflections from various surfaces.The human ear cannot distinguish between the echo and the original direct sound if the delay is less than 1/10 of a second. The sound speed in dry air is approximately 343 m/s at 25 °C.As a result, the reflecting object must be farther away for an echo to be audible to someone standing close to the sound source.
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Kara less was applying her makeup when she drove into south's busy parking lot last friday morning. Unaware that lisa ford was stopped in her lane 30 feet ahead, kara rear-ended lisa's rented taurus. Kara's 1300-kg car was moving at 11 m/s and stopped in 0. 14 seconds.
The momentum of Kara's car before the collision, given that it was moving with a velocity of 11 m/s is 14300 Kg.m/s
Momentum of an object is simply defined as the product of mass and velocity. Mathematically it is expressed as:
Momentum = mass × velocity
Using the above formula, we can obtain the momentum of Kara's car before the collision as follow::
Mass of Kara's car = 1300 Kg
Velocity of Kara's car = 11 m/s
Momentum of Kara's car =?
Momentum = mass × velocity
= 1300 Kg × 11 m/s
= 14300 Kg.m/s
Thus, the momentum of Kara's car is 14300 Kg.m/s
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Use the information from the graph to answer the
question.
What is the acceleration of the object?
The magnitude of the velocity change increases with lengthier acceleration. When acceleration is constant, the change in velocity is directly proportional to time.
What change in acceleration due to linear velocity?The rate at which the velocity of any moving object changes is measured by acceleration. The velocity change divided by the time represents the acceleration. Both the magnitude and the direction of acceleration are present.
Therefore, An object's motion can be depicted by a velocity-time (or speed-time) graph if it moves in a straight line. The line's gradient is equal to the object's acceleration.
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Nancy is knitting a scarf. It takes her 0. 2 of an hour to knit each inch of the scarf. She wants the length of the scarf to be 60 inches. How many hours will it take her to make the scarf?.
Nancy is hard at work on a scarf. She spends twenty seconds on every inch of the scarf she knits. Her desired scarf length is sixty inches. Given, It takes 0.2 of an hour to knit a single inch of the scarf. Here, 0.2 of an hour refers to 12 minutes. Therefore, It takes 12 minutes to knit an inch of a scarf.
Since Nancy takes 12 mins to knit an inch of a scarf, then for 60 inches, it would be,
1 inch -> 12 minutes
60 inches -> 12 * 60 minutes = 720 mins to knit 60 inches of a scarf.
Now, convert the minutes into hours,
720 mins -> 720 / 60 = 12 hours.
Therefore, it takes 12 hours to knit 60 inches of a scarf.
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20 kj of heat is added to a cup containing 1-kg of water at 20 c. what is the final temperature of the water? answer in c, and assume water has a specific heat of 4186 j/(kg c). answer in celsius.
The final temperature of the water is equal to 24.77 °C.
What is the specific heat capacity?The specific heat capacity can be explained as the amount of heat needed to increase the temperature of one unit of material by one degree Celsius. The specific heat capacity depends upon the nature of the material.
The mathematical equation is used to calculate the specific heat is equal to:
Q = mCΔT
Given, the mass of the water, m = 1 Kg
The initial temperature of the water, T₁ = 20°C
The specific heat capacity of water, C = 4186 J/(kg °C)
The heat added to the cup, Q = 20,000 J
The final temperature of the water can be determined as:
20000 = 4186 × 1 × (T₂ - 20)
T₂ - 20 = 4.77
T₂ = 24.77 °C
Therefore, the final temperature of the water is 24.77 °C.
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In a two-slit interference pattern, the intensity at the peak of the central maximum is I_0.
Â
a. At a point in the pattern where the phase difference between the waves from the two slits is 62.0 degrees, what is the intensity? Give your answer as a fraction of I_0. (I/I_0 =)
Â
b. What is the path difference for light with a wavelength of 473 nm from the two slits at a point where the phase angle is 62.0 degrees?
The centre maximum's peak intensity in a two-slit interferogram is 0.75 I 0I intense.
What are some instances of intensity?The degree, volume, or quantity of a phenomenon, such as fire, passion, weather, work, or passion, is known as its intensity. The word "intensity" has been linked to passion, fire, and murder in the past. When describing the intensity of something like a flame or possibly a love affair, it is utilized.
What is the scientific definition of intensity?Energy density times wave speed equals intensity, which is the amount of energy a wave transports over a surface of a given area in a unit of time. Watts per sq.m are the most common units used to measure it. The strength or amplitude of a wave will determine its intensity.
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suppose that you want to take a photograph of yourself as you look at your image in a mirror 3.1 m away. for what distance should the camera lens be focused?
The camera should be focused for 6.2 m.
In addition, we already know that the main use of plane mirrors is to observe an object's reflection. Periscopes and kaleidoscopes, vehicles, shaving mirrors, dental mirrors, torch lights, solar cookers, and security-related uses are just a few of the many functions and applications of a plane mirror.
As we're standing 3.1 m away from the mirror so our image is also formed 3.1 away from the mirror as the mirrors used for this purpose are plane mirrors. So the camera should be focused for twice the distance at which we're standing from the mirror i.e 3.1 * 2 = 6.2 m
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What is energy associated with motion called?
The energy associated with motion is called kinetic energy.
Your body doesn't just have energy when you're in motion. When an object is in motion it has a finite amount of kinetic energy. However, when not in motion, the body can store energy in the form of potential energy.
The body can also have a certain internal energy. This can be explained as follows. Energy is basically the ability of any body to do work. Suppose you are sitting ideally in your room and suddenly you realize that someone has changed the position of your study desk and you want to change it. So I pushed the table and moved it to where it suited me. This means that we have applied a finite force that causes displacement, i.e. we have done some work. So you had the ability to work properly. This means that you had energy in the form of internal energy.
[tex]mgh+\frac{mV^2}{2}=Energy \\\\m[gh+V^2/2]=E[/tex]
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A piece of clay was thrown so that it has a momentum of 34 kg·m/s. It hits a 0.25 kg motionless cart and sticks to it. What is the momentum of the clay and cart combined? (ignore friction)
The momentum of the clay and the cart is 34 kgm/s.
What is momentum?Momentum can be defined as the product of mass and velocity.
To calculate the momentum of the clay and the cart, we use the formula below.
Formula:
M' = M+mu..............................Equation 1Where:
M' = Momentum of the clay and the cartM = Momentum of the claym = Mass of the cartu = Initial velocity of the cartFrom the question,
Given:
M = 34 kgm/sm = 0.25 kgu = 0 m/s (motionless)Substitute these values into equation 1
M' = 34+(0.25×0)M' = 34 kgm/sHence, their momentum is 34 kgm/s.
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Element x has two isotopes. If 72. 0% of the element has an isotopic mass of 84. 9 amu and 28. 0% has an isotopic mass of 87. 0 amu, the average atomic mass of element x is numerically equal to.
The average atomic mass of element X is numerically equal to 85.48 amu.
Isotopes can be defined as the variants of chemical elements that possess the same number of protons and electrons, but a different number of neutrons. In other words, isotopes are variants of elements that differ in their nucleon ( The total number of protons and neutrons) numbers due to a difference in the total number of neutrons in their respective nuclei. i.e. same atomic number but different masses.Given , Percentage of isotope 1 = 72%
Percentage of isotope 2 = 28%
Mass of isotope 1 = 84.9 amu
Mass of isotope 2 = 87 amu
i.e.
Average atomic mass = (0.72 * 84.9) + (0.28 * 87) = 85.48 amu
So the average atomic mass of element X is numerically equal to 85.48 amu.
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order the structures that a pressure wave passes through in the cochlea, beginning from the oval window and ending at the round window.
The cochlea is the organ responsible for hearing, and it is composed of several interconnected structures through which a pressure wave passes. Beginning at the oval window, the pressure wave then moves through:
Scala vestibuliReissner's membrane Scala tympaniBasilar membraneAnd finally exits through the round window.
The Structures of the Cochlea: A Journey from the Oval Window to the Round WindowOrder the structures that a pressure wave passes through in the cochlea:
Oval windowScala vestibuliReissner's membraneScala tympaniBasilar membraneRound windowThis chain of structures creates a pathway that allows the pressure wave to pass through the cochlea, converting sound waves into signals that are then sent to the brain and interpreted as sound.
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what is the total number of unique ways to distribute two identical objects in three separate containers when there is no limit on the number of objects that can be in a container?
There are 6 unique ways to distribute two identical objects in three separate containers.
Unique ways are the different ways in which the objects can be separately placed in the containers.
Number of ways are:
Container 1: both Object ; Container 2: 0 object ; Container 3: 0 objectContainer 1: 0 Object ; Container 2: both object ; Container 3: 0 objectContainer 1: 0 Object ; Container 2: 0 object ; Container 3: both objectContainer 1: 1 Object ; Container 2: 1 object ; Container 3: 0 objectContainer 1: 0 Object ; Container 2: 1 object ; Container 3: 1 objectContainer 1: 1 Object ; Container 2: 0 object ; Container 3: 1 objectThese are the 6 ways to distribute two identical objects in three separate containers.
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you are lying on your back on the slope of a grassy hill, watching the clouds go by overhead. which is the best statement about the force of friction exerted on you by the ground in this situation?
The best statement about the force of friction exerted on you by the ground is that a force of static friction pointing up the hill, parallel to the surface of the hill is applied to you by the ground.
Static friction is define as the force that is exerted so as to keep the object at rest. The friction experienced when individuals try to move a stationary object on a surface, without actually triggering any relative motion between the body and the surface on which it is on.
Following, the Newton's Third law of Force, every action has equal and opposite reaction. Hence, to neutralize the force acting on the ground due to you, a parallel force exerted by the ground acts on on you.
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Calculate the speed of a horse that travels 512 m in 450 seconds.
It is an exercise of uniform rectilinear movement.
Uniform rectilinear motion is one in which an object moves in a straight line, in one direction, with a constant speed.
When we speak of constant speed, we mean that the movement maintains the same speed; That is, the object does not move faster or slower, always at the same speed.
Calculate the speed of a horse that travels 512 m in 450 seconds.Data:
V = ?
d = 512 m
t = 450 s
The uniform motion formula is: V=d/t
We clear, but in this case it is not necessary, since we want to calculate the velocity.
V = d/t V = 512 m/450 s V = 1.14 m/sThe speed of a horse that covers 512 m in 450 seconds is 1.14 m/s.
Answer: The speed registered by the horse is 1.13 seconds.
Step by step explanation:
¿Calculate the speed of a horse that travels 512 m in 450 seconds?
Data:
V = ?D = 512mT = 450 secondsTo calculate the speed of the horse, first we are going to divide but for this it is necessary to calculate its speed.
V = D/TV = 512 m/450 sV = 1,13 seconds.Rpt: The speed registered by the horse is 1.13 seconds.
a tall tree is growing across a river from you. you would like to know the distance between yourself and the tree,as well as its height, but are unable to make the measurements directly. however, by using a mirror to form an image of the tree and then measuring the image distance and the image height, you can calculate the distance to the tree as well as its height. suppose that this mirror produces an image of the sun, and the image is 0.8501 m from the mirror. the same mirror is then used to produce an image of the tree. the image of the tree is 0.9605 m from the mirror. (a) how far away is the tree? (b) the image height of the tree has a magnitude of o. 14 m. how tall is the tree?
a)how far the tree was found to be 0.9605 m
b) the height of the tree was found to be 0.14m
What exactly is object distance?
Object Distance, denoted by s, is the distance between an object and an optical element.
What are the qualities of a mirror image?
• The image obtained is fictitious.
•The picture is flipped laterally.
• The picture is upright.
• The picture has the same dimensions as the thing.
• The distance between the image acquired from the mirror and the item gained from the mirror is the same.
As a result, the distance between the tree and the mirror is the same as the distance between the picture and the mirror, i.e. 0.9605 m, and the height of the tree is the same as the height of the image, which is 0.14 m.
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a)how far the tree was found to be 0.9605 m
b) the height of the tree was found to be 0.14m
What exactly is object distance?
Object Distance, denoted by s, is the distance between an object and an optical element.
What are the qualities of a mirror image?
• The image obtained is fictitious.
•The picture is flipped laterally.
• The picture is upright.
• The picture has the same dimensions as the thing.• The distance between the image acquired from the mirror and the item gained from the mirror is the same?
As a result, the distance between the tree and the mirror is the same as the distance between the picture and the mirror, i.e. 0.9605 m, and the height of the tree is the same as the height of the image, which is 0.14 m.
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The specific gravity of an material is defined as the ratio of the density of the material to the density of water. The specific gravity of ice is 0.917, whereas that of seawater is 1.025.
What fraction of an iceberg is above the surface of the water?
\frac{V_{above}}{V_{total}} = ____________
The fraction of the iceberg that is above the surface of the water is 8.3 %.
The specific gravity of any material is defined as the ratio of the density of the material to the density of water.
Mathematically, the formula for specific gravity of materials =
= S.G = density of the material / density of water
Specific gravity of the iceberg = 0.917
Specific gravity of the seawater = 1.025
The fraction of the iceberg submerged in the seawater =
= 0.917 = 0.917 x 100 %
= 91.7 %
The fraction of the iceberg that is above the surface of the water =
= 1 - 0.917
= 0.083
= 0.083 x 100 %
= 8.3 %
Thus, the fraction of the iceberg submerged in the water is a function of the specific gravity of the iceberg.
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If a 65-kilogram astronaut exerts a force with a magnitude of 50. Newtons on a satellite that she is repairing, the magnitude of the force that the satellite exerts on her is.
The magnitude of force ( 50 N ) which satellite exerts on her but in opposite direction.
We will apply the Newton's Third Law of motion for solving this problem, which says that, "To each activity, there is an equivalent and inverse response". And that implies if any article (say object 1) apply some power on another article (say object 2), then, at that point, the item 2 will likewise apply same greatness of power on object 1, yet it will be in inverse heading.
So, we have amount of force exerted by a 65-kg astronaut on satellite which is 50N.
To balance that force, satellite will apply same amount of force on astronaut but in just opposite direction .
F' = - F
or F' = - 50 N.
Here, negative sign shows that the direction of force is opposite.
Hence, required value of force is 50N.
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question what would cause a backpack sitting on the floor of the school bus to suddenly fly forward? responses the bus makes a hard turn to the left. the bus makes a hard turn to the left. the bus is going forward and suddenly stops. the bus is going forward and suddenly stops. the bus is going backward and suddenly stops. the bus is going backward and suddenly stops. the bus makes a hard turn to the right.
Answer:
Below
Explanation:
Going forward and stops .....the backpack wants to keep going forward due to its inertia.
while on mars, you drop your martian detector while climbing out of the rover. if you're standing on a platform 8 meters from the ground and the acceleration due to gravity on mars is -3.8 m/s^2, how long does it take for the martian detector to hit the ground? report an error 1.3 s 9.9 s 2.1 s 13 s 21 s
It take 1.45s to the Martian detector to hit the ground.
We are know that,
Acceleration = a = - 3.8 m/s²
Distance = r = 8m
Final velocity = v = 0 (The rock's velocity is zero at its maximum height.)
Time = ?
Thus to calculate the hitting time of the Mars ground we can use the formula,
acceleration = change in velocity / time
First of all we have to calculate the initial velocity (u) of the Martian i.e.
a = u²/r
u² = a.r
u² = (-3.8m/s²)× 8m
u² = -30.4m²/s²
u = - 5.51 m/s
Putting the value of initial velocity in the above equation we can get the hitting time,
-3.8 m/s² = 0 - (5.51m/s)/t
t = (-5.51m/s)/(-3.8m/s²)
t = 1.45s
The Martian detector hits the ground in 1.45 seconds.
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Starting from rest, an object rolls freely down a 10. -meter long incline in 2. 0 seconds. The acceleration of the object is.
The acceleration of this object is 5 m/s².
Initial velocity = 0 m/s (since the object starts from rest).
Distance = 10 meters
Time = 2 seconds.
To find the acceleration of the object, we would use the second equation of motion:
Mathematically, the second equation of motion is given by the formula;
= s = ut + (1/2)at²
Where;
S represents the distance covered.
u is the initial velocity.
a represents the acceleration.
t is the time measured in seconds.
Substituting the parameters into the formula, we have;
= 10 = 0 + (1/2)a(2)²
= a = 10/2
= a = 5 m/s²
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a spring stretches by 21.0 cm when a 135 n object is attached. what is the weight of a fish that would stretch the spring by 31.0 cm?
The weight is 200 N of a fish that would stretch the spring by 31.0 cm.
We can use Hooke's Law to solve this problem. Hooke's Law states that the force (F) needed to stretch a spring is proportional to the amount of stretch (x). The mathematical expression for Hooke's Law is:
F = kx
where k is the spring constant.
We can rearrange this equation to solve for k:
k = F/x
We can substitute the given values for F (135 N) and x (21 cm) to calculate the spring constant:
k = 135 N/21 cm
k = 6.43 N/cm
Now that we know the spring constant, we can use Hooke's Law to calculate the force needed to stretch the spring by 31 cm.
F = kx
F = 6.43 N/cm x 31 cm
F = 199.33 N
Finally, we can use the force to calculate the weight of a fish that would stretch the spring by 31 cm. Since weight is equal to force multiplied by the acceleration due to gravity (g = 9.8 m/s2), we can use the following equation:
Weight = F x g
Weight = 199.33 N x 9.8 m
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the range of visible light wavelengths is between 3.9 x 10 -7 m and 7.0 x 10 -7 m. what is the corresponding range of frequencies for visible light?
The range of visible light is from 7.69 * 10¹⁴ Hz.
Frequency is defined as the number of complete cycles a wave can complete in one second. We know that, the SI unit of frequency is Hertz (Hz).
We know the relation between speed of light, wavelength and frequency as
v = f * λ ----(1)
where, v is the speed of light in air
f is the frequency of visible light
λ is the wavelength of visible light
Making ' f ' as subject in the above equation as,
f = v / λ ----(2)
We know that speed of light in air is 3 * 10⁸ m/s
λ = from 3.9 * 10⁻⁷ m
Substituting the values in the above equation (2), we have
f = v / λ = (3 * 10⁸)/(3.9 * 10⁻⁷) = 0.769 * 10¹⁵ Hz = 7.69 * 10¹⁴ Hz
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