The given function is:
[tex]undefined[/tex]Find the length of the legs.(4,4)[](-2,-2)[?]Enter the number thatbelongs in the green boxEnter
We have a right triangle and we have to find the length of the legs.
We first analyse the hypotenuse.
It is a line that is defined by two points: (4,4) and (-2,-2).
The line passes through the center of coordinates, but we will check it:
The slope can be calculated as:
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{4-(-2)}{4-(-2)}=1[/tex]We can now write the slope-point equation as:
[tex]\begin{gathered} y-y_0=m(x-x_0) \\ y-4=1(x-4) \\ y-4=x-4 \\ y=x \end{gathered}[/tex]Then, we know that the equation of the line that defines the hypotenuse is y=x.
If the legs are parallel to the axis, we can find the angle that is defined by the hypotenuse and the horizontal leg as:
[tex]\begin{gathered} \tan (\theta)=m=1 \\ \theta=\arctan (1)=45\degree \end{gathered}[/tex]As we have an angle of 45 degree for one leg, the other has to have an equal angle, as 180-90-45=45 (Note: we are substracting from the sum of the 3 angles, 180 degrees, the already known angles, 90 and 45 degrees, so we are left with 45 degrees that correspond to the third angle).
If the two angles for the legs are equal, their lengths are equal too.
So we can start by calculating the length of the hypotenuse: it is the distance between (4,4) and (-2,-2).
[tex]\begin{gathered} D=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt[]{(4-(-2))^2+(4-(-2))^2} \\ D=\sqrt[]{6^2+6^2}=\sqrt[]{2\cdot6^2}=6\sqrt[]{2} \end{gathered}[/tex]Then, we can write the Pythagorean theorem as (a and b are the legs, and c is the hypotenuse):
[tex]\begin{gathered} a^2+b^2=c^2 \\ a=b\longrightarrow2a^2=c^2=(6\sqrt[]{2})^2=36\cdot2=72 \\ a^2=\frac{72}{2} \\ a^2=36 \\ a=\sqrt[]{36} \\ a=b=6 \end{gathered}[/tex]Answer: the length of the legs is 6 units.
For each triangle, check all that apply. 60° Triangle A 60° Scalene Isosceles O Equilateral 60° 5 Triangle B 11 7 O Scalene O Isosceles O Equilateral 60 triangles by side... Triangle C 30° Scalene Isosceles O Equilateral Triangle D 8 O Scalene O Isosceles O Equilateral
Given:
Four triangles A, B, C and D are given as below
Find:
we have to classify each triangle.
Explanation:
Triangle A:
Since, in the triangle A, all the three angles are equal to 60 degree.Therefore, all three sides of triangle A are equal.
So, Triangle A is Equilateral.
Triangle B:
In triangle B all the three sides are different.
Therefore, triangle B is Scalene.
Triangle C:
In triangle C, all the angles are diffrent, so all three sides are different.
Therefore, Triangle C is Scalene.
Triangle D:
In triangle D, two sides are equal.
Therefore, Triangle D is isosceles
12 more than the product of 5 and a number x
Answer: (5*x) + 12 or 5x + 12
Step-by-step explanation: differant sites let you do it defferent ways but if the multipaction sign in an "x" I would do the 2nd one :) Hope it's right, have a great day!
Find the derivative of the function y=(4x^ 3 -5x^ 2 )(3x^ 6 +2x^ 5 )10 two different ways. First, multiply the factors togethercollect like terms, then use the basic rules to find the derivative. Second, apply the Product Rule to the function as is currently written.
Given:
The given function is:
[tex]y=(4x^3-5x^2)(3x^6+2x^5)[/tex]First method: Multiplying factors and differentiating after arranging like terms together.
[tex]\begin{gathered} y=(4x^3-5x^2)(3x^6+2x^5) \\ =4x^3(3x^6+2x^5)-5x^2(3x^6+2x^5) \\ =12x^9+8x^8-15x^8-10x^7 \\ =12x^9-7x^{8^{}}-10x^7 \end{gathered}[/tex]Now we will differentiate y with respect to x by basic rules:
[tex]y^{\prime}=12(9)x^{9-1}-7(8)x^{8-1}-10(7)x^{7-1}[/tex]Solving further,
[tex]y^{\prime}=108x^8-56x^7-70x^6[/tex](b) Second method: Apply product rule to find the derivative:
Again,
[tex]y=(4x^3-5x^2)(3x^6+2x^5)[/tex]The product rule states:
[tex](uv)^{\prime}=u^{\prime}v+v^{\prime}u[/tex]Where u and v are the two factors multiplied.
So here we have:
[tex]\begin{gathered} u=4x^3-5x^2 \\ v=3x^6+2x^5 \end{gathered}[/tex]Finding the derivatives:
[tex]\begin{gathered} u^{\prime}=4(3)x^{3-1}-5(2)x^{2-1} \\ =12x^2-10x \end{gathered}[/tex]Similarly,
[tex]\begin{gathered} v^{\prime}=3(6)x^{6-1}+2(5)x^{5-1} \\ =18x^5+10x^4 \end{gathered}[/tex]Now put the values in the product rule,
[tex]\begin{gathered} y^{\prime}=(uv)^{\prime} \\ =u^{\prime}v+v^{\prime}u \\ =(12x^2-10x)(3x^6+2x^5)+(18x^5+10x^4)(4x^3-5x^2) \end{gathered}[/tex]Simplifying further,
[tex]\begin{gathered} y^{\prime}=12x^2(3x^6+2x^5)-10x(3x^6+2x^5)+18x^5(4x^3-5x^2)+10x^4(4x^3-5x^2) \\ =36x^8+24x^7-30x^7-20x^6+72x^8-90x^7+40x^7-50x^6 \\ =108x^8-56x^7-70x^6 \end{gathered}[/tex]This is the derivative obtained.
From above two methods, we can see the derivative is same in both the cases.
You invested $28,000 in two accounts paying 7% and 9% annual interest, respectively. If the total interest earned for the year was $2180, how much was invested at each rate?
We are given the following information:
total of $28,000 invested in 2 accounts
7% and 9% interest rates for each account
total interest was $2,180
We are asked to calculate the amount invested at each rate.
To do this, let us first identify our variable and what it stands for. Let us use the variable x to represent the amount invest at 7%. That leaves us t
In how many months were there more than two days with thunderstorms? 1 3 5 7
To find how many months have more than 2 days look at the heights
of the bars
You need to count the bars which height more than 2
There are 5 bars that have a height of more than 2
The answer is 5
c. If x= 3 is specifically a hole (removable discontinuity) of f(x), then what would be true about g(3) and h(3)? Explain your reasoning.
Solution
We have the following function given:
f(x)= g(x)/h(x)
We have a point of discontinuity on x=3
c. If x= 3 is specifically a hole (removable discontinuity) of f(x), then what would be true about g(3) and h(3)? Explain your reasoning.
For this case we can conclude that g(3)/h(3) is not defined since f(3) is not defined for the function and that means that the function is not fully connected on x=3
two cylinders have the same volume the first cylinder has a diameter of 10 cm and a height of 30 cm The second cylinder has a diameter of 8 cm what is the height of the second cylinders the nearest tenth of a centimer
Solution
Given that two cylinders have the same volume but different dimension
For Cylinder 1
Diameter is 10 cm Height is 30 cm
For Cylinder 1
Diameter is 8 cm Height is h cm
The volume of a cylinder is given as;
[tex]V=\pi r^2h[/tex]Since the two cylinders have the same volume,
Since radius = Diameter/2
[tex]\begin{gathered} \pi\times(\frac{10}{2})^2\times30=\pi\times(\frac{8}{2})^2\times h \\ \Rightarrow5^2\times30=4^2\times h \\ \Rightarrow h=\frac{25\times30}{16}\approx46.9 \end{gathered}[/tex]Hence, the second cylinder the nearest tenth of a centimeter is 46.9 cm
Can someone please help me with my math ;( ?
Step 1:
copy and complete the table below by inputting the data provided.
The marginal frequency numbers are the numbers at the edges of the table except for the number at the bottom right-most corner.
B) Marginal relative frequency is the ratio of the sum of the joint relative frequency in a row or column and the total number of data values
Hence,
[tex]\text{ the lowest marginal frequency }=\frac{107}{232}=0.461[/tex]Joint relative frequency the ratio of the frequency in a particular category and the total number of data values
Therefore,
[tex]\text{ the largest joint frequency }=\frac{63}{111}=0.568[/tex]C)For the circled number, the preferred style is Gothic given that the member is male and the percentage is 0.57
D) The total number of males surveyed = 111
the total number of members surveyed = 232
Hence, the percentage of the total number of choir students surveyed that were males are:
[tex]\frac{111}{232}=0.48[/tex]O DATA ANALYSIS AND STATISTICSFinding the mode and range of a data setEach day, Susan records the number of news articles she reads. Here are her results for the last eight days.3, 6, 6, 9, 1, 6, 9,6Find the range and the mode for the data.
We are given the following data set:
[tex]3,6,6,9,1,6,9,6[/tex]We are asked to determine the range. To do that we will arrange the data from smallest to greatest values, like this:
[tex]1,3,6,6,6,6,9,9[/tex]Now, the range is the difference between the smallest and greatest value, therefore:
[tex]\text{Rage}=9-1=8[/tex]Therefore, the range is 8
Now, the mode is the value that repeats the most. In this case, we have that the value "6" is repeated 4 times, therefore, the mode is:
[tex]\mod e=6[/tex]Decide whether the given orderd pair is a solution to the stystem of equations?I don’t know how to to the bottom equation.
Given:
[tex]\begin{gathered} y=2x-6 \\ x+y=8 \end{gathered}[/tex]solve the equation for x and y then
[tex]\begin{gathered} x+y=8 \\ \text{put the value of y} \\ x+2x-6=8 \\ 3x=8+6 \\ 3x=14 \\ x=\frac{14}{3} \end{gathered}[/tex]so value of y is:
[tex]undefined[/tex]graph f(x)=(x-4)^3-2
Explanation:
Before we plot the graph, you need to understand the transformation process of the parent function x³
x - 4 inside the parenthesis talks about the horizontal shift of the graph. -4 means that the graph will move to the right by 4.
The constant value outside the parenthesis talks about the graph movement. The constant -2 shows that the graph moves downward by 2.
Find the graph of the function below:
A student is taking a test in which items of type A are worth 8 points and items of type B are worth 12 points. It takes 3 min to complete each item of type A and 6 min to complete each item of type B. The total time allowed is 60 min and Anna answers exactly 16 questions. How many questions of each type did she complete? Assuming that all her answers were correct, what was her score? She completed questions of type A.
Type A questions are worth 8 points each.
Type B questions are worth 12 points each.
it takes 3 minutes to answer a Type A question
it takes 6 minutes to answer a Type B question.
total time allowed = 60 minutes
She answered a total of 16 questions.
let
number of question answer on type A = x
number of question answered on type B = y
Therefore,
3x + 6y = 60
x + y = 16
then,
[tex]\begin{gathered} 3x+6y=60 \\ x+y=16 \\ x=16-y \\ 3(16-y)+6y=60 \\ 48-3y+6y=60 \\ 3y=60-48 \\ 3y=12 \\ y=\frac{12}{3} \\ y=4 \\ x=16-4 \\ x=12 \end{gathered}[/tex]She answered 12 questions on type A and 4 questions on type B.
If all her answer is correct her score can be computed below
[tex]undefined[/tex]Solve the equation for A: 2*Cos A + 2 = 3.
Answer:
A=60 degrees
Explanation:
Given the equation:
[tex]2\cos A+2=3[/tex]Subtract 2 from both sides of the equation.
[tex]\begin{gathered} 2\cos A+2-2=3-2 \\ 2\cos A=1 \end{gathered}[/tex]Divide both sides by 2:
[tex]\begin{gathered} \frac{2\cos A}{2}=\frac{1}{2} \\ \cos A=\frac{1}{2} \end{gathered}[/tex]Finally, solve for A.
[tex]\begin{gathered} A=\arccos (\frac{1}{2}) \\ A=60\degree \end{gathered}[/tex]Each of the four graphs below represents a function.Which function has an inverse that is also a function?
For the given question, we will choose the function that has an inverse that will be a function
So, the function must be a one-to-one function
We will use the horizontal line test to check if the function is a one-to-one function or not
the horizontal line will intersect with the graph of the function at only one point
So, the answer will be option 4 as shown in the following figure:
What is the remainder when j(x)=x4+2x3−5x2+2x+4 is divided by x+3
From the problem, we have a function :
[tex]j(x)=x^4+2x^3-5x^2+2x+4[/tex]The remainder when j(x) is divided by x + 3 is the value of the function when x = -3
x = -3 comes from :
x + 3 = 0
x = -3
Substitute x = -3 to the function,
[tex]\begin{gathered} j(-3)=(-3)^4+2(-3)^3-5(-3)^2+2(-3)+4 \\ j(-3)=81-54-45-6+4 \\ j(-3)=-20 \end{gathered}[/tex]The answer is -20
Solve for h by using the inverse (opposite) operations. −5.3+h5=−19.4
Given:
The given term is -5.3+h/5=-19.4.
The objective is to find the value of h using inverse operation.
Inverse operation states that, if a term is in addition operation with another term, then it will change to subtraction operation while shifting to other side of the equation.
If a term is in multiplication operation, then it change to division operation while shifting to other side of the equation.
The value of h can be calculated as,
[tex]\begin{gathered} -5.3+\frac{h}{5}=-19.4 \\ \frac{h}{5}=-19.4+5.3 \\ \frac{h}{5}=-14.1 \\ h=-14.1(5) \\ h=-70.5 \end{gathered}[/tex]Thus, the value of h is -70.5.
Hence, option (c) is the correct answer.
what digit is in the
The number given in the statement is
2.113 pints.
To write in word form,
Two and one hundred thirteen thousandths.
As in the number from last we have thousand , hundred, tens and ones.
So, we can write the given number in word form.
Two and one hundred thirteen thousandths.
Hence the correct option is c.
A certain car is rated to get 24 miles per gallon. How far can it travel on 14.5 gallons of gas?
348 miles
Explanation
Step 1
[tex]\text{rate}=24\text{ }\frac{miles\text{ }}{\text{gallon}}[/tex]
it indicates that for every gallon the car can travel 24 miles, Now to know the total miles it can travel with 14.5 gallons of gas, just multiply the rate by the numbers of gallons
so
let
[tex]\begin{gathered} \text{rate}=24\text{ }\frac{miles\text{ }}{\text{gallon}} \\ gallons=14.5 \end{gathered}[/tex]make the product
[tex]\begin{gathered} \text{distace}=\text{rate}\cdot Number\text{ of gallons} \\ \text{replace} \\ \text{distance}=24\frac{miles\text{ }}{\text{gallon}}\cdot14.5\text{ gallons} \\ \text{distance}=348\text{ miles} \end{gathered}[/tex]therefore, the answer is 348 miles
I hope this helps you.
hi can someone help me solve this thank you!!
For the given inequality, the smallest value of x is a whole number which is exactly divisible by both 2 and 5.
As given in the question,
Given inequality :
[tex]4x/5 - 1x/2 > 18[/tex]
[tex][2(4x) + 5(-x)]/5.2 > 18[/tex]
[tex](2.4x - 5x) / 5.2 > 18[/tex]
[tex](8x-5x)/10 > 18[/tex]
[tex]3x/10 > 18[/tex]
[tex]3x > 180 \\3x/3 > 180/3\\x > 60\\[/tex]
x ∈ (60, ∞)
∵ Since 60 is whole number and divisible by 2 and 5 both.
therefore answer is option e.
Therefore, for the given inequality, the smallest value of x is a whole number which is exactly divisible by both 2 and 5.
Learn more about inequality here
brainly.com/question/28823603
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you have two fractions 2/5 and 3/10 and you want to rewrite them so that they have the same denominator what numbers could you use for the denominator is it A 20 or B 10 or C5 or D 15
By definition, a fraction has the following form:
[tex]\frac{a}{b}[/tex]When "a" is the numerator and "b" is the denominator.
In this case you have the following fractions:
[tex]\begin{gathered} \frac{2}{5} \\ \\ \frac{3}{10} \end{gathered}[/tex]Notice that the denominator of the first fraction is 5 and the denominator of the second fraction is 10.
The steps to find the a Common denominator are shown below:
1. Descompose 5 and 10 into their Prime factors:
[tex]\begin{gathered} 5=5 \\ 10=2\cdot5 \end{gathered}[/tex]2. In this case, you need to choose 5, because it is the common one. It will be the Common denominator of the fractions.
3. Divide the original denominator of the first fraction by the Common denominator 5. Multiply the the numerator by the result. Then:
[tex]\frac{2}{5}=\frac{2\cdot1}{5}=\frac{2}{5}[/tex]4. Apply the procedure explained in step 3 to the second fraction:
[tex]\frac{3}{10}=\frac{3\cdot2}{5}=\frac{6}{5}[/tex]5. You can identify that you can also get a common denominator multiplying the denominators and the numerators of both fractions by
The answer is: Option C.
Write a system of equations to describe the situation below, solve using any method, and fill in the blanks. The volleyball team and the wrestling team at Brookfield High School are having a joint car wash today, and they are splitting the revenues. The volleyball team gets $2 per car. In addition, they have already brought in $92 from past fundraisers. The wrestling team has raised $16 in the past, and they are making $4 per car today. After washing a certain number of cars together, each team will have raised the same amount in total. What will that total be? How many cars will that take?
Data:
Volleyball team: V
Wrestling team: W
x: number of cars
V: $2 per car. Initial $92
W: $4 per car. Initial $16
You have the next equations:
[tex]\begin{gathered} V=2x+92 \\ W=4x+16 \end{gathered}[/tex]To find the total amount you have the next equation:
As each team have raised the same amount:
[tex]\begin{gathered} V=W \\ \\ 2x+92=4x+16 \end{gathered}[/tex]You solve x to find the number of cars each team wash in total:
[tex]\begin{gathered} 2x-4x+92=4x-4x+16 \\ -2x+92=16 \\ \\ -2x+92-92=16-92 \\ -2x=-76 \\ \\ \frac{-2}{-2}x=\frac{-76}{-2} \\ x=38 \end{gathered}[/tex]You use that value of x to find the final amount of each team:
[tex]\begin{gathered} V=2(38)+92=76+92=168 \\ \\ W=4(38)+12=152+12=168 \end{gathered}[/tex]Then, (the total of each team is $168) Total $336, (each team wash 38 cars) The total number of cars 76f(x) = -x2 + 7x - 13 Find f(-3)
Given the function :
[tex]f(x)=-x^2+7x-13[/tex]To find f(-3) , substitute with x = -3 , into the given function:
So,
[tex]\begin{gathered} f(-3)=-(-3)^2+7\cdot-3-13 \\ \\ f(-3)=-9-21-13 \\ \\ f(-3)=-43 \end{gathered}[/tex]
true or false18. In the circle: x^2+(y-2)^2=12, the radius is 12
The general equation of a circle is:
[tex](x-h)^2+(y-k)^2=r^2[/tex]where (h,k) is the center and r is the radius of the circle.
Comparing the given equation of a circle and the above general equation we get:
[tex]r^2=12[/tex]Then, the radius of this circle is:
[tex]r=\sqrt[]{12}[/tex]In conclusion, the sentence is false.
what are the first five terms of the recursive sequence aₙ = 3aₙ₋₁ + 3 where a₁ = 9
The expression for the recursive sequence is :
[tex]a_n=3a_{n-1}+3[/tex]where a1 = 9
First term:
Since first term is already given:
[tex]a_1=9[/tex]Second Term :
Substitute n =2 in the recursive expression and simlify
[tex]\begin{gathered} a_n=3a_{n-1}+3 \\ a_2=3(a_{2-1})+3 \\ a_2=3(a_1)+3 \\ a_2=3(9)+3 \\ a_2=27+3 \\ a_2=30 \end{gathered}[/tex]Second Term : 30
Third Term:
Substitute n = 3 in the given recursive expression:
[tex]\begin{gathered} a_n=3a_{n-1}+3 \\ a_3=3(a_{3-1})+3 \\ a_3=3(a_2)+3 \\ a_3=3(30)+3 \\ a_3=90+3 \\ a_3=93 \end{gathered}[/tex]Third Term = 93
Fourth Term:
Substitute n = 4 in the given recursive expression:
[tex]\begin{gathered} a_n=3a_{n-1}+3 \\ a_2=3(a_{2-1})+3 \\ a_2=3(a_1)+3 \\ a_2=3(9)+3 \\ a_2=27+3 \\ a_2=30 \end{gathered}[/tex]
which equation shows x^2+6x-4=0 rewritten by completing the squarea) (x+3)^2=36b) (x+3)^2=4c) (x+3)^2=9d) (x+3)^2=13
Solution
Step 1
Write the equation:
[tex]x^2\text{ + 6x - 4 = 0}[/tex]Step 2:
Rewrite the equation:
[tex]x^2\text{ + 6x = 4}[/tex]Step 3
[tex]\begin{gathered} Add\text{ }\frac{b^2}{4a\text{ }}\text{ to both sides to get a perfect square.} \\ \text{a = 1, b = 6} \\ \frac{b^2}{4a}\text{ = }\frac{6^2}{4\times1}\text{ = }\frac{36}{4}\text{ = 9} \end{gathered}[/tex][tex]\begin{gathered} x^2\text{ + 6x + 9 = 4 + 9} \\ Add\text{ similar terms:} \\ (x\text{ + 3\rparen}^2\text{ = 13} \end{gathered}[/tex]Final answer
[tex]d)\text{ \lparen x + 3\rparen}^2\text{ = 13}[/tex]Graph triangle ABC with vertices A(0,5) B(4,3) and C(2,-1) and it’s image after a reflection in the line y=2
By reflecting the given points about y=2, the x-coordinates remain the same, then we have
[tex]\begin{gathered} (0,5)\longrightarrow(0,-1) \\ (4,3)\longrightarrow(4,1) \\ (2,-1))\longrightarrow(2,5) \end{gathered}[/tex]then, the new triangle is:
where the red line represents the line y=2. We found the new points by searching the points which are at the same distance of the original poinst to the line:
Then, the preimage and the image after the reflection are:
For the following figure, complete the statement for the specified pointsRS.199Points RT, S, and areboth collinear and coplanarcolinearcoplanarneither col near nor coplanar
From the figure, we can see that point R, T, S, Q are not on the same plane. Thus we can say they are neither colli coplanar
Jada and Priya are trying to solve the equation 2/3 + x = 4 Jada says I think we should multiply each side by 3/2 because that is the reciprocal of 2/3 Priya since I think we should add -2/3 to each side because that is the opposite of 2/3
The equation they are trying to solve is
[tex]\frac{2}{3}+x=4[/tex]In order to solve this equation, they need to add -2/3 on each side (the opposite of 2/3).
[tex]\begin{gathered} \frac{2}{3}-\frac{2}{3}+x=4-\frac{2}{3} \\ x=4-\frac{2}{3} \end{gathered}[/tex]Hence, Priya is correct because they need to use the opposite of 2/3, not the reciprocal.
An equation that can be solved using Jada's strategy is
[tex]\frac{2}{3}x=4[/tex]This equation would need to use a reciprocal, as Jada said.
The difference between an integer and its square root is 12. What is the integer?
ANSWER:
16
STEP-BY-STEP EXPLANATION:
From the statement we can establish the following equation (where x is the integer):
[tex]x\:-\:\sqrt{x}\:=\:12[/tex]We solve for x:
This means that the integer that satisfies the statement is 16