To write in standard form;
568,319,000,000,000,000,000,000,000
Move the decimal point backward till you reach the last number
Multiply by ten raise to the number of times you move the decimal point
That is;
568,319,000,000,000,000,000,000,000 = 5.68319 x 10^26
[tex]5.68319\text{ }\times10^{26}[/tex]In the rectangle below, SU= 4x – 2, RT = 5x-10, and m Z VSR=26°.Find RV and m ZVTS.Rm
SU and RT are the diagonals of the rectangle and are thus equal.
We the equate them to find x
SU = RT = 4x - 2 = 5x - 10
subtracting 4x from both sides gives:
4x - 2 - 4x = 5x - 10 - 4x
-2 = x - 10
Adding 10 to both sides give:
10 - 2 = x - 10 + 10
x = 8
RV is half of RT
where = RT = 4(8) - 2 = 32 - 2 = 40
Therefore, RV = 40/2 = 20
To calculate angle VTS, we consider that it is in an isosceles triangle with its angle equal to angle VST. Same angle VST is complementary with angle VSR
Therefore, angle VTS = VST = 90 - 26 = 64 degrees (sum of angles in a right angle)
VTS = 64 degrees
Solve for y.2x – 8y = 24
Answer:
[tex]y=\frac{1}{4}x-3[/tex]Explanation:
Given the equation:
[tex]2x-8y=24[/tex]To solve for y, we follow the steps below:
Step 1: Rearrange to Isolate the term containing y.
[tex]8y=2x-24[/tex]Step 2: Divide both sides by 8.
[tex]\begin{gathered} \frac{8y}{8}=\frac{2x-24}{8} \\ y=\frac{2x-24}{8} \end{gathered}[/tex]Step 3: Simplify
[tex]\begin{gathered} y=\frac{2x}{8}-\frac{24}{8} \\ y=\frac{1}{4}x-3 \end{gathered}[/tex]This is all the information I was given. O. 2.5.
The equation of a line in the slope-intercept form is y = mx + b, where m is the slope and b the y-intercept.
If it is known:
- The equation of a parallel line
- One point of the equation
To find the equation of the line, follow the steps:
1. Parallel lines have the same slope. So, use the slope of the parallel line to find the slope of the line.
2. Substitute the point in the equation to find b.
3. Since m and b are known, you found the equation of the line.
The birth weights of the 908 babies born at Valley Hospital in 2019 were normally
distributed with a mean of 7.2 pounds with a standard deviation of 1.5. Use the Z-
Score Table from the book to determine the number of babies that weighed more
than 10 pounds.
The number of babies that weighed more than 10 pounds is 43 using Z-
Score Table.
What is normal distribution?
A probability distribution that is symmetric about the mean is the normal distribution, sometimes referred to as the Gaussian distribution. It demonstrates that data that are close to the mean occur more frequently than data that are far from the mean. The normal distribution is depicted graphically as a "bell curve."
Given that total number of babies is 908.
The mean of the normal distribution is 7.2 pound.
The standard deviation of the normal distribution is 1.5 pound.
The formula of z score is z = (x - μ)/σ
In the given question x = 10, μ = 1.5, σ = 7.2
z score = (10 - 7.2)/1.5 = 1.86667
P-value from Z-Table:
P(x<10) = 0.96903
P(x>10) = 1 - P(x<10) = 0.030974
The number of babies that weighed more than 10 pounds is ( 0.030974 × 908) = 43.39 = 43 (approx.)
To learn more about normal distribution, click on below link:
https://brainly.com/question/15103234
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Find the slope between the points:(1,7)(-2,3)
Using the formula,
[tex]m=\frac{7-3}{1-(-2)}\rightarrow m=\frac{4}{1+2}\rightarrow m=\frac{4}{3}[/tex]Answer:
slope = [tex]\frac{4}{3}[/tex]
Step-by-step explanation:
calculate the slope m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (1, 7 ) and (x₂, y₂ ) = (- 2, 3 )
m = [tex]\frac{3-7}{-2-1}[/tex] = [tex]\frac{-4}{-3}[/tex] = [tex]\frac{4}{3}[/tex]
Solve: -2y ≥ 10y ≤ -5y ≤ 5y ≥ -5y ≥ 5
Given
[tex]-2y\ge10[/tex]Solution
Recall: Dividing by a negative number means you reverse the inequality symbol
[tex]\begin{gathered} -2y\ge10 \\ divide\text{ both sides by -2} \\ -\frac{2y}{-2}\ge\frac{10}{-2} \\ \\ y\leq-5 \end{gathered}[/tex]The final answer
[tex]y\leq-5[/tex]Use the graph of the function F shown here to find f(1), f(2), f(3).
The value of f(x) is reflected over the y-axis.
Obtain f(1) as follows,
Draw a vertical line at x=1 to intersect the curve.
From this point of intersection, draw a horizontal line to intersect the y-axis at y=3.
Therefore, the value of f(1) is 3.
Obtain f(2) as follows,
Draw a vertical line at x=2 to intersect the curve.
From this point of intersection, draw a horizontal line to intersect the y-axis at y=8.
Therefore, the value of f(2) is 8.
Obtain f(3) as follows,
Draw a vertical line at x=3 to intersect the curve.
From this point of intersection, draw a horizontal line to intersect the y-axis at y=7.
Therefore, the value of f(3) is 7.
What is the perimeter of the composite figure?6 cm9 cm2 cm10 cm
As the given figure can be considered as two rectangles,
Consider the first rectangle,
The length is, 9-2 = 7 cm,
The width is, 10-6 = 4 cm.
Therefore, the perimeter is,
[tex]P=2(l+w)=2(7+4)=22\text{ cm}[/tex]For the second rectangle,
[tex]P=2(l+w)=2(10+2)=24\text{ cm}[/tex]Therefore, the total perimeter is,
22 cm + 24 cm = 46 cm.
What is the solution to the system of equationsy = 3x - 2 and y = g(x) where g(x) is defined bythe function below?y=g(x)
we need to write the equation of the graph
it is a parable then the general form is
[tex]y=(x+a)^2+b[/tex]where a move the parable horizontally from the origin (a=negative move to right and a=positive move to left)
and b move the parable vertically from the origin (b=negative move to down and b=positive move to up)
this parable was moving from the origin to the right 2 units and any vertically
then a is -2 and b 0
[tex]y=(x-2)^2[/tex]now we have the system of equations
[tex]\begin{gathered} y=3x-2 \\ y=(x-2)^2 \end{gathered}[/tex]we can replace the y of the first equation on the second and give us
[tex]3x-2=(x-2)^2[/tex]simplify
[tex]3x-2=x^2-4x+4[/tex]we need to solve x but we have terms sith x and x^2 then we can equal to 0 to factor
[tex]\begin{gathered} 3x-2-x^2+4x-4=0 \\ -x^2+7x-6=0 \end{gathered}[/tex]multiply on both sides to remove the negative sign on x^2
[tex]x^2-7x+6=0[/tex]now we use the quadratic formula
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]where a is 1, b is -7 and c is 6
[tex]\begin{gathered} x=\frac{-(-7)\pm\sqrt[]{(-7)^2-4(1)(6)}}{2(1)} \\ \\ x=\frac{7\pm\sqrt[]{49-24}}{2} \\ \\ x=\frac{7\pm\sqrt[]{25}}{2} \\ \\ x=\frac{7\pm5}{2} \end{gathered}[/tex]we have two solutions for x
[tex]\begin{gathered} x_1=\frac{7+5}{2}=6 \\ \\ x_2=\frac{7-5}{2}=1 \end{gathered}[/tex]now we replace the values of x on the first equation to find the corresponding values of y
[tex]y=3x-2[/tex]x=6
[tex]\begin{gathered} y=3(6)-2 \\ y=16 \end{gathered}[/tex]x=1
[tex]\begin{gathered} y=3(1)-2 \\ y=1 \end{gathered}[/tex]Then we have to pairs of solutions
[tex]\begin{gathered} (6,16) \\ (1,1) \end{gathered}[/tex]where green line is y=3x-2
and red points are the solutions (1,1)and(6,16)
how do u solve 6=×+3_2
To solve the equation, we should isolate x on one side and the numerical term on the other side
So we have to multiply both sides by 2 to cancel the denominator 2 from the right side
[tex]\begin{gathered} 6\times2=\frac{(x+3)}{2}\times2 \\ 12=x+3 \end{gathered}[/tex]Now want to move 3 from the right side to the left side
Subtract 3 from both sides
[tex]\begin{gathered} 12-3=x+3-3 \\ 9=x \end{gathered}[/tex]The solution is x = 9
choose correct word name for the number below. 51,104
To write the word name of a number, we start from left to right. in the thousands place, we have 51, so this is "fifty-one thousand". The rest is 104, we is "one hundred four". All together, we have:
"Fifty-one thousand one hundred four"
balloon 670 meters away angle 42degrees the higher balloon is 945 away angle 36 degrees how much higher is the balloon on the right than the left
Answer:
[tex]h1-h2=686.582689-603.2707097=83.31198832m[/tex]In a class of students, the following data table summarizes how many students playan instrument or a sport. What is the probability that a student chosen randomlyfrom the class does not play a sport?Plays an instrument Does not play an instrumentPlays a sport34Does not play a sport136
First, let's calculate the total number of students in the class:
[tex]3+4+13+6=26[/tex]Out of those 26 students we have
[tex]13+6=19[/tex]19 that do not play a sport.
Therefore the probability that a student chosen randomly
from the class does not play a sport is:
[tex]\frac{19}{26}[/tex]The polar equation r=8sin(4θ) graphs as a rose.What is the length of the petals of this rose?
Polar equations of rose curves follow the pattern:
[tex]r=a\text{ }sin\text{ }n\theta\text{ }[/tex]where:
a = represents the length of the petals
n = represents the number of petals.
Based on the given polar equation, the value of "a" is 8. Since "a" represents the length of the petals, then the length of the petals of this rose is 8 units.
What is the value of sin E?Give your answer as a simplified fraction.
For this problem we first use the pythagorean theorem to find QH
[tex]\begin{gathered} QH^2+HE^2=QE^2 \\ QH^2=QE^2-HE^2=101^2-99^2=400 \\ QH=20 \end{gathered}[/tex]Then
[tex]\sin (E)\text{ =}\frac{QH}{QE}=\frac{20}{101}[/tex]9+9x=10x+2 Solve for x
This problem is about linear equations.
To solve it, we need to find the value of x.
[tex]9+9x=10x+2[/tex]First, we need to organize the equation, all terms without variables at the right side, and all terms with variables at the left side
[tex]9x-10x=2-9\text{ }\rightarrow-x=-7[/tex]Finally, we multiply the equation by -1 to get the proper answer
[tex]x=7[/tex]Therefore, the answer is 7.You have to deliver medicines 1 mile away. In order to do that, you have to which drone to use depending on the size of the blade in the drone. The equation that gives the relationship between the size of the blade (b) in inches and speed (miles/hour) is as follows: Speed = 50-2b In order to deliver the medicine in time, the drone must travel faster than 37 miles/hour. Check the box underneath the blade that you would like to use. Then write the speed of the drone using this blade.
From the information given,
The equation representing the relationship between the size of the blade (b) in inches and speed (miles/hour) is given as
Speed = 50-2b
Also, the required drone must travel faster than 37 miles/hour.
For the small blade, b = 4 inches
speed = 50 - 2 * 4 = 50 - 8
speed = 42 miles/hour
For the medium blade, b = 6 inches
speed = 50 - 2 * 6 = 50 - 12
speed = 38 miles per hour
For the large blade, b = 8
speed = 50 - 2 * 8 = 50 - 16
speed = 34 miles per hour
Since the speed of the drone with small blade is greater than 37 miles per hour and it is the greatest among the three drones,
The speed of the drone will be 42 miles per hour
Can I get an answer please?
the rule is reflextive
here(x, y) is changing into (x , -y)
the process is called translation
determine the solution to the system. Explain which method you used to determine your solution. 2x+y=-15y-6x=7
This is the system.
We will use the method of elimination to solve it.
So we will multiply the first equation by 3 and add it to the second one, this will gives us.
[tex]8y=4\rightarrow y=\frac{1}{2}[/tex][tex]2x+\frac{1}{2}=-1\rightarrow2x=-\frac{3}{2}\rightarrow x=-\frac{3}{4}[/tex]f(x) = log x + 2 and g(x) = log (1/x). Find (f – g) (x).log x -2 – log (1/x)22 log x + 2(2/log x) + 1
We have to find (f-g)(x) given that f(x) = log x + 2 and g(x) = log(1/x).
We can find it as:
[tex]\begin{gathered} (f-g)(x)=f(x)-g(x) \\ (f-g)(x)=\log x+2-\log(\frac{1}{x}) \\ (f-g)(x)=\log x+2-(\log1-\log x) \\ (f-g)(x)=\log x+2-0+\log x \\ (f-g)(x)=2\log x+2 \end{gathered}[/tex]Answer: 2log(x) + 2
experimental and theoretical
Spinning a three:
experimental = 11/50
theoretical = 1/5
Spinning an even number:
experimental = 21/50
theoretical = 2/5
Spinning an odd number:
experimental: 29/50
theoretical: 3/5
Spinning a number less than 5:
experimental: 21/25
theoretical: 4/5
A bus traveled on a level road for 6 hours at an average speed of 20 miles per hour faster than it traveled on a winding road. The time spent on the winding road was 2 hour find the average speed on the level road if the entire trip was 360 miles.
Given:
A bus traveled on a level road for 6 hours at an average speed of 20 miles per hour .
The distance is calculated as,
[tex]\begin{gathered} d_1=r\times t \\ d_1=6\times20 \\ d_1=120\text{ miles} \end{gathered}[/tex]The distance covered by bus on level road is faster than it raveled on a winding road.
The time spent on the winding road was 2 hour. So, the distance is,
[tex]\begin{gathered} d_2=r\times t \\ d_2=2r\text{ miles} \end{gathered}[/tex]The total distance was 360 miles.
[tex]\begin{gathered} d_1+d_2=360 \\ 120+2r=360 \\ 2r=360-120 \\ 2r=240 \\ r=120 \end{gathered}[/tex]Answer: the average speed on the level road is 120 mph
Find the 10th term of the geometric sequence whose common ratio is 3/2 and whose first term is 3.
ANSWER:
59049/512
EXPLANATION:
Given:
Common ratio(r) = 3/2
First term(a) = 3
Number of terms(n) = 10
To find:
The 10th term of the geometric sequence
We can go ahead and determine the 10th term of the sequence using the below formula and substituting the given values into it and evaluate;
[tex]\begin{gathered} a_n=ar^{n-1} \\ \\ a_{10}=3(\frac{3}{2})^{10-1} \\ \\ a_{10}=3(\frac{3}{2})^9 \\ \\ a_{10}=3(\frac{19683}{512}) \\ \\ a_{10}=\frac{59049}{512} \end{gathered}[/tex]Therefore, the 10th term of the sequence is 59049/512
For each equation state the number of complex roots, the possible number of positive real roots,and the possible rational roots x^4+8x^2+2=0
The given equation is,
[tex]x^4+8x^2+2=0[/tex]Fundamental Theorem of Algebra says that a polynomial will have exactly as many roots as its degree (the degree is the highest exponent of the polynomial). A straightforward corollary of this (often stated as part of the FTOA) is that a polynomial of degree n with Complex (possibly Real) coefficients has exactly n Complex (possibly Real) zeros counting multiplicity.
Therefore, the equation will have 4 roots.
Descartes’s rule of signs says the number of positive roots is equal to changes in sign of f(x), therefore, the given equation does not have positive real roots.
Therefore, the equation will have 4 complex rooots.
match the property to the correct step in the problemA.) addition property of equality. B.) subtraction property of equalityC.) distributive property
In the first step
It is distributive property because we multiplied 10 by 2x and 10 by 4
1. C
In the second step
We add 6x to both sides, then
It is addition property of equality
2. A
In the third step
We subtract 40 from both sides, then
It is the subtraction property of equality
3. B
Cindy is riding her bicycle six miles ahead of Tamira. Cindy is traveling at an average rate of 2 miles per hour. Tamira is traveling at an average rate of 4 miles perhour. Let a represent the number of hours since Tamira started riding her bicycleWhen will Tamira be ahead of Cindy? Write an inequality to represent thissituation
Given:
Cindy is riding her bicycle six miles ahead of Tamira at an average rate of 2 miles per hour.
Let 'a' represents the number of hours.
Distance travellled by Tamira in a hours = 4a
Distance travelled by Cindy in a hours=2a
[tex]4a>2a+6[/tex]For a given set of rectangles, the length is inversely proportional to the width. In one
of these rectangles, the length is 25 and the width is 3. For this set of rectangles,
calculate the width of a rectangle whose length is 5.
Answer:
Step-by-step explanation:
Answer:
The width is 8 units
Step-by-step explanation:
This is a variation problem we are to work with.
Length is inversely proportional to width, let length be l and width be w
modeling the statement mathematically, we have lw = k where k is the proportionality constant
Now let’s get k from l = 12 and w = 6
k = 12 * 6 = 72
Now for the second rectangle also;
lw = k given l = 9
9w = 72
w = 72/9
w = 8
given : f(x) = x2 - 5 and g(x) = 3x - 1 Find 2g (f(-5))
The given functions are
f(x) = x^2 - 5
g(x) = 3x - 1
To find 2g(f(- 5)), we would first find f(- 5)
To find f(- 5), we would substitute x = - 5 into f(x) = x2 - 5. It becomes
f(- 5) = (- 5)^2 - 5
f(- 5) = 25 - 5
f(- 5) = 20
Then, we would substitute f(- 5) = 20 into g(x) = 3x - 1
Thus,
g(f(- 5) = 3*20 - 1
g(f(- 5) = 60 - 1
g(f(- 5) = 59
Therefore,
2g(f(- 5)) = 2 * 59 = 118
when you compare the 2016-2017 season with the 2017-2018 season, what was the percent increase in the number of games that the Lakers won ? show your work.
In order to calculate the percent increase in the number of games that the Lakers won from the 2016-2017 season with the 2017-2018 season we would have to make the following calculation:
percentage of increase=100* (games won 2017-2018-games won 2016-2017)/ (games won 2016-2017)
percentage of increase=100*(35-26)/(26)
percentage of increase=100*0.34615
percentage of increase=34.615%
The percent increase in the number of games that the Lakers won from the 2016-2017 season with the 2017-2018 was 34.615%
QuestionThe width of a rectangle is 6 less than the length, let L represent the length of the rectangle, Write an expression for thewidth of the rectangle
Since L represents the length and the width is 6 less the length, if w denotes the width, we have
[tex]w=L-6[/tex]that is, the width measures L-6