to finde the slope of the poins we use the formula
[tex]m=\frac{y2-y1}{x2-x1}[/tex]after replacing on the formula we obtain
[tex]\begin{gathered} m=\frac{-2-6}{-4-4} \\ m=\frac{-8}{-8} \\ m=1 \end{gathered}[/tex]the slope for the line will be 1
(x² + 5x - 2)-(3x²-x+4)
Given: (x² + 5x - 2)-(3x²-x+4)
Remove the parentheses:
[tex]=x^2+5x-2-3x^2+x-4[/tex]Add like terms:
[tex]\begin{gathered} =x^2-3x^2+5x+x-2-4 \\ =-2x^2+6x-6 \end{gathered}[/tex]Answer:
[tex]\begin{equation*} -2x^2+6x-6 \end{equation*}[/tex]What is an obtuse angle?A) Angle COAB) Angle BOAC) Angle DOBD) Angle DOA
An obtuse angle is an angle that measures more than 90° but not eauql or greater than 180°.
COA is the sum of COB and BOA, which is 90°, so COA is not obtuse.
BOA is 60°, so it is not obtuse.
DOA is a straight line, so it is 180°, so not obtuse.
DOB is COD plus COB. Since COA is 90°, DOC is also 90°, so DOC ples COB is 120°, which is between 90° and 180°, so DOB is obtuse and the correct alternative is C.
Giving a test to a group of students, the grades and gender are summarized below A B C TotalMale214 4 20Female1018 13 41Total1232 17 61If one student is chosen at random,Find the probability that the student did NOT get an "C". Round your answer to 3 decimal places_____.
Given:
⇒There are 61 students in total.
⇒12 of them got an A while 32 of them got a B.
⇒In total, 44 students did not get a C.
⇒So, 44 out of 61 students did not get a C.
Convert 44/61 into decimal form.
[tex]\frac{44}{61}=44\div61=0.721311\approx0.721[/tex]Answer:
The probability that a randomly chosen student did not get a C is 0.721 approximately.
y = x2 + 5x - 10y=-x² + 2x + 10
Since in both given equations, the variable y is already clear, then you can equal the two equations and then solve for x. So, you have
[tex]\begin{cases}y=x^2+5x-10\text{ (1)} \\ y=-x^{2}+2x+10\text{ (2)}\end{cases}[/tex][tex]\begin{gathered} x^2+5x-10=-x^2+2x+10 \\ \text{ Add }x^2\text{ to both sides of the equation} \\ \text{ Subtract 2x to both sides of the equation} \\ \text{ Subtract 10 to both sides of the equation} \\ x^2+5x-10+x^2-2x-10=-x^2+2x+10+x^2-2x-10 \\ 2x^2+3x-20=0 \end{gathered}[/tex]To solve for x you can use the quadratic formula, that is,
[tex]\begin{gathered} \text{ For }ax^2+bx+c=0\text{ where a}\ne0 \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}[/tex]In this case
a=2
b=3
c=-20
So,
[tex]\begin{gathered} x=\frac{-3\pm\sqrt[]{(3)^2-4(2)(-20)}}{2\cdot2} \\ x=\frac{-3\pm\sqrt[]{9+160}}{4} \\ x=\frac{-3\pm\sqrt[]{169}}{4} \\ x=\frac{-3\pm13}{4} \\ x_1=\frac{-3+13}{4}=\frac{10}{4}=\frac{5}{2}=2.5 \\ x_2=\frac{-3-13}{4}=\frac{-16}{4}=-4 \end{gathered}[/tex]Now you can plug in the solutions found in any of the given equations to find their respective y-coordinates.
For the first solution, you have
[tex]\begin{gathered} x_1=\frac{5}{2} \\ y_{}=-x^2+2x+10\text{ (2)} \\ y_1=-(\frac{5}{2})^2+2(\frac{5}{2})+10 \\ y_1=-\frac{25}{4}+5+10 \\ y_1=\frac{35}{4} \\ y_1=8.75 \\ \text{ Then} \\ (2.5,8.75) \end{gathered}[/tex]For the second solution, you have
[tex]\begin{gathered} x_2=-4 \\ y=-x^2+2x+10\text{ (2)} \\ y_2=-(-4)^2+2(-4)+10 \\ y_2=-16-8+10 \\ y_2=-14 \\ \text{Then} \\ (-4,-14) \end{gathered}[/tex]Therefore, the solution set of the given system of equations is
[tex]\mleft\lbrace(-4,-14),(2.5,8.75)\mright\rbrace[/tex](7 x 10^-5) x (5 * 10^-8)= ?x 10^
1) Let's calculate that. Start by multiplying the factors 7, and 5.
[tex]\begin{gathered} 7\cdot10^{-5}\text{ x 5 }\cdot10^{-8}= \\ 35\cdot10^{-13} \end{gathered}[/tex]After that, we use the property of the exponents when multiplying. Repeat the base and then add the exponents -8 + (-5) = -8 -5 = -13.
Parallelogram ABCD is below. m
The consecutive angles of a parallelogram are supplementary. therefore:
[tex]\begin{gathered} m\angle A+m\angle B=180 \\ 41+x+8.5=180 \\ x+49.5=180 \\ solve_{\text{ }}for_{\text{ }}x\colon \\ x=180-49.5 \\ x=130.5 \\ x\approx131 \end{gathered}[/tex]Multiply the pair conjugates using the Product of Conjugates Pattern (simplify) (rs-2/5)(rs+2/5)
In order to calculate the product of a pair of conjugate terms, we can use the pattern below:
[tex](a+b)(a-b)=a^2-b^2[/tex]So we have:
[tex]\begin{gathered} (rs-\frac{2}{5})(rs+\frac{2}{5}) \\ =(rs)^2-(\frac{2}{5})^2 \\ =r^2s^2-\frac{4}{25} \end{gathered}[/tex]Enter an algebrak expression for the word expression. twice a number, minus 19 The expression is ?
x is an unknown number
twice a number means: 2x
and twice a number minus 19 means: 2x - 19
Use the formula P(B\A)=n(A and B)÷n(A) to find the probability P(kinglface card) when a single. card is drawn from a standard 52 card deck. P(king face card)=
In a deck of 52 cards, there 4 faces of Kings. These are the King of Hearts, King of Diamonds, King of Spades, and King of Clubs. Therefore, the chance of drawing a king face card in a deck of cards would be 4 out of 52 or 1 out of 13.
Answer: P(king face card) = 1/13
Graph the solution to the following system of inequalities.ys-2x-3y> 4x + 710-8-4-Х?10
Explanation
[tex]\begin{gathered} y\leq-2x-3 \\ y>4x+7 \end{gathered}[/tex]Step 1
First, graph the inequality 1
[tex]y\leq-2x-3[/tex]the related equation is
[tex]y=-2x-3[/tex]now, get 2 coordinates of the line
a) when x=1
[tex]\begin{gathered} y=-2x-3 \\ y=-2(1)-3 \\ y=-2-3 \\ y=-5 \\ so,\text{ the coordinate is (1,-5)} \end{gathered}[/tex]b)when x=0
[tex]\begin{gathered} y=-2x-3 \\ y=-2\cdot0-3 \\ y=0-3 \\ y=-3 \\ \text{coordinate P2}\Rightarrow(0,-3) \end{gathered}[/tex]now, draw a line that pases trought the coordinates we found.
Since the inequality is ≤ , not a strict one, the border line is solid
Step 2
Now, do the same for inequality 2
so
[tex]y>4x+7[/tex]the related equation is
[tex]y=4x+7[/tex]find 2 coordinates of the line
a)when x=0
[tex]\begin{gathered} y=4x+7 \\ y=4\cdot0+7 \\ y=0+7 \\ y=7 \\ so,\text{ the coordinate 3 is (0,7)} \end{gathered}[/tex]b) when x=-2
[tex]\begin{gathered} y=4x+7 \\ y=4\cdot-2+7 \\ y=-8+7 \\ y=-1 \\ so,\text{ the coordinate 4 is (-2},-1) \end{gathered}[/tex]now, draw the line 2, this lines passes trougth the coordiantes 3 and 4
Since the inequality is >, a strict one, the border line is dotted
Step 3
Graph:
in inequality (1) we need the values smaller r than -2x-3, it measn all values under the line,
and in Inequality 2 we need the values greater than 4x+7, it means all values over the line
so, the solution is the dark purple zone
I hope this helps you
I need to write and simplify an algebraic expression for the perimeter of each shape.please help!
For the square, we have that each side's length is 2p, since the perimeter is the sum of the length of all sides of a geometric figure, this means that we have to add all the lengths of the square like this:
[tex]\begin{gathered} P=2p+2p+2p+2p_{} \\ \Rightarrow P=8p \end{gathered}[/tex]And we can do the same with the 3 sides of the triangle:
[tex]\begin{gathered} P=2x+2x+3x+1 \\ \Rightarrow P=7x+1 \end{gathered}[/tex]If $163,300 is invested in an account earning 3.75% annual interest compounded semi-annually, how much interest is accrued in the first 4 years? Round to the nearest cent?
Solution:
An amount compounded is given as;
[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ \text{Where;} \\ P=\text{ amount invested;} \\ r=\text{ interest rate;} \\ n=\text{ number of times interest applied per time period;} \\ t=\text{ number of time period elapsed.} \end{gathered}[/tex]Given that;
[tex]\begin{gathered} P=163,300 \\ r=0.0375 \\ n=2 \\ t=4 \end{gathered}[/tex]Thus, we have;
[tex]\begin{gathered} A=163300(1+\frac{0.0375}{2})^{2\times4} \\ A=163300(1.01875)^8 \\ A=189464.20 \end{gathered}[/tex]Thus, the interest accrued in the first 4 years is;
[tex]\begin{gathered} I=A-P \\ I=189464.20-163300 \\ I=26164.20 \end{gathered}[/tex]FINAL ANSWER: $26,164.20
2. The following is a graph of the function f(x) = 2^x. Graph thetransformation f(x+3) on the blank coordinate axis.yy
Explanation:
The transformation f(x+3) indicates that we have to translate the graph of f(x) 3 units to the left.
In the graph of f(x) the y-intercept is at y = 1. For f(x+3) this point is moved 3 units to the left, so it is (-3, 1).
Answer:
The graph of f(x+3) is
TWO-Variable SystemsThe two lines graphed below are parallel. How many solutions are there to thesystem of equations?O A. TwoO B. ZeroO C. OneO D. Infinitely manyPREVIOUS
Answer:
B. Zero
Explanation:
The solutions of a system of equations are the points where the graphs intersect. If the lines are parallel, the lines will not intersect, so there will be no solutions to the system.
Therefore, the solutions to the system of two parallel lines are
B. Zero
ВС: Round your answer to the nearest hundredth. B 2 7
opposite to angle 65 = BC
adjacent to angle 65 = 7
[tex]\tan \text{ }\theta\text{ = }\frac{\text{opposite }}{\text{adjacent}}[/tex][tex]\tan \text{ 65 =}\frac{BC}{7}[/tex][tex]\begin{gathered} BC\text{ = 7 x tan 65} \\ =\text{ 7 x 2.1445} \\ BC\text{ = 15.0115} \\ BC\text{ }\approx\text{ 15.01 (nearest hundreth)} \end{gathered}[/tex]what is the reference angle for four radians rounded to two decimal places?
The reference angle can be calculated 4 radians is in the third quadrant, of the coordinate
reference angle=angle - 3.14
reference angle=4-3.14
the reference angle of 4 radians is 0.8584 rounded to two decimal places is 0.86 radians
Find the distance between vertices A and C of a regular hexagon whose sides are 20 cm each angle of the hexagon is 120 degrees
Use cosine law to find b:
[tex]b^2=a^2+b^2-2ac*cosB[/tex][tex]\begin{gathered} b^2=(20cm)^2+(20cm)^2-2(20cm)(20cm)*cos120º \\ b^2=400cm^2+400cm^2-800cm^2*(-0.5) \\ b^2=400cm^2+400cm^2+400cm^2 \\ b^2=1200cm^2 \\ b=\sqrt{1200cm^2} \\ b=20\sqrt{3}cm \\ b\approx34.64cm \end{gathered}[/tex]Then, the distance between A and C is 20√3 cm or approximately 34.64 cmif H & J equals 7 and 10s equals 10 find LK
The trapezoid HJKL has T and S as midpoints of the legs
The length of TS can be calculated as the mean or average of the lengths of HJ and LK, i.e.:
[tex]TS=\frac{HJ+LK}{2}[/tex]We are given the lengths HJ=14, LK=42, thus:
[tex]TS=\frac{14+42}{2}=\frac{56}{2}=28[/tex]Now if we have HJ=7 and TS=10, we can find LK by solving the equation for LK
[tex]LK=2TS-HJ[/tex][tex]LK=2*10-7=20-7=13[/tex]The length of LK is 13
Help meeee please!!!!
The coordinates of B' are (1, 0) after transforming the parallelogram down 4 units and right 3 units.
What are coordinates?Coordinates are distances or angles, represented by numbers, that uniquely identify points on surfaces of two dimensions or in space of three dimensions. These are the set of values that shows the exact position. Coordinates are the set of points, or numbers, that locates a point on a line, on a plane, or in space. The points at the coordinates are called coordinate points. The coordinate plane has two axes. Those are horizontal and vertical axes. The two axes intersect each other at a point called the origin. Coordinate axes are one of the fixed reference lines of a coordinate system. It is a two-dimensional number line. It is used to locate the position of any point.
From the graph, the coordinates of B are (-2, 4).
Translating 4 units down means the value of the y-axis is changing. Therefore, new coordinates will be
(-2-0, 4-4)
=(-2, 0)
Then the parallelogram is translated to 3 units to the right. So, the x-axis is changing to a positive end.
The coordinates of B' will be
(-2+3, 0+0)
= (1,0)
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is 0.5 a integer but not a whole number
...
Natural Numbers are the numbers 1 through infinity.
Whole numbers.
So, they start from 1 and go on...
1, 2, 3, 4, .....
Now, Whole numbers are very same just that they start from 0, so it would be:
0, 1, 2, 3, ....
Integers would include the negatives fo the naturals and 0, so they would be:
...-2, -1, 0 , 1, 2, ....
We want a number NOT natural but integer, that would be 0.
So,
Natural Numbers = 1, 2, 3, 4, 5, ....
Whole Numbers = 0, 1, 2, 3, 4, 5, .....
Integers = ...-5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, ...
which is the better buy and provide the unit price for your answer! $5.28 for 6 candy bars or $12.75 for 15 candy bars?
Answer:
Explanation:
Given:
$5.28 for 6 candy bars
$12.75 for 15 candy bars
To determine the better buy, we simplify each option first:
For $5.28 for 6 candy bars:
5.28/6 = $0.88 per candy bar
For $12.75 for 15 candy bars:
12.75/15 = $0.85 per candy bar
Therefore,
A car travels at a steady speed of 40 mph. How far will it go in 15 minutes?
The distance travelled by the car in 15 minutes can be determined as,
[tex]\begin{gathered} D=s\times t \\ D=40\text{ mph}\times15\text{ min}\times\frac{1\text{ h}}{60\text{ min}} \\ D=10\text{ miles} \end{gathered}[/tex]Thus, the required distance is 10 miles.
Use the intercepts to graph the equation. y = -6 x-intercept: Enter as a coordinate: such as (a, b). If there is no x-intercept, enter DNE. Enter as a coordinate: such as (a, b). If y-intercept: there is no y-intercept, enter DNE. 8 6 5 4 ربا
Answer:
x -intercept: DNE
y-intercept: (-6, 0)
Explanation:
The x-intercept is the point where the line intersects the x-axis.
The y-intercept is the point where the line intersects the y-axis.
Now when we draw the line y = -6, we get
We see that the red line does not intersects the x-axis at any point; thereffore, the x-intercept does not exist.
x -intercept: DNE
The red line intersects the y-axis at y = -6; therefore, the y-intercept is the point (0, -6)
Glven: Circle P with center at (-2, 3) and a radius of 23. Identify the equation that could represent circle P. (3 – 2) + (y - 3)2 = 23 (2+2) + (y + 3)' = 23 (2 – 2)2 + (y + 3) = 23 (2+2)² + (y – 3)2 =23
The correct option is:
[tex](x+2)^2+(y-3)^2=23[/tex]Because we need to remember that the equation for a circumference centered in (h,k) and with radius r is:
Given the standard restricted domains, which of the following relationships does not hold for x=-1? (Assume angles are in radians.)
Answer:
[tex]D:\text{ arccos\lparen cos\lparen-1\rparen\rparen= 1}[/tex]Explanation:
From the restricted domain, we want to check for the relationship that does not hold
All we have to do here is to substitute the value -1 for x, after which we evaluate each of the given equations
We proceed as follows:
[tex]\begin{gathered} a)\text{ sin\lparen}\sin^{-1}(-1))\text{ = -1} \\ b)\text{ arcsin\lparen sin\lparen-1\rparen\rparen = -1} \\ c)\text{ cos\lparen arc cos \lparen-1\rparen\rparen = -1} \\ d)\text{ arc cos\lparen cos\lparen-1\rparen\rparen = 1} \\ e)\text{ tan\lparen arc tan\lparen-1\rparen\rparen = -1} \\ f)\text{ arctan\lparen tan\lparen-1\rparen\rparen = -1} \end{gathered}[/tex]The correct option is thus D
3 batteries cost $5r and 8 folders cost $2r. Jason bought6 batteries and 4 folders. How much does he pay?Give your answer in terms of the
We are asked to determine the total amount paid for 6 batteries and 4 folders. To do that we need to determine the unit price of each item. We do that by dividing the amount spent by the number of items that were bought. That is:
[tex]\begin{gathered} n_b=\frac{5\text{ dollars}}{3\text{ batteries}} \\ \\ n_f=\frac{2\text{ dollars}}{8\text{ folders}} \end{gathered}[/tex]Now we multiply the desired number of items by each of the corresponding unit prices:
[tex]N=\frac{5}{3}\times6+\frac{2}{8}\times4[/tex]Solving the operations:
[tex]\begin{gathered} N=10+1 \\ N=11 \end{gathered}[/tex]Therefore, the total amount paid is $11.
Find the 55th term of the arithmetic sequence -7, -5, -3,
The given numbers are -7,-5,-3.
The common differen
The average amount of water used per person each day in a country is 45 gallons. How much water does the average person use in one year?
Proportions
It's assumed the amount of water consumed by one person is proportional to the time.
The contant of proportionality is given as 45 gal/day.
Since one normal year has 365 days, then we use the same proportion to calculate the water used in one year as follows:
Water used = 45 * 365 = 16,425 gallons.
The average person uses 16,425 gallons.of water in one year
Find the diameter of a circle with a circumference of 28.26 centimeters. Use 3.14 for π.
Answer:
The diameter of the circle is 9.0 cm.
[tex]d=9.0\text{ cm}[/tex]Explanation:
Given that the circumference of the circle is 28.26 centimeters.
[tex]C=28.26\text{ cm}[/tex]Recall that the formula for the circumference of a circle is;
[tex]\begin{gathered} C=2\pi r=\pi d \\ d=\frac{C}{\pi} \end{gathered}[/tex]Substituting the given values;
[tex]\begin{gathered} d=\frac{28.26\text{ cm}}{3.14} \\ d=9.0\text{ cm} \end{gathered}[/tex]Therefore, the diameter of the circle is 9.0 cm.
[tex]d=9.0\text{ cm}[/tex]what is 7/8 - 3 1/5? i cant firgure it out
Answer:
-93/40 or -2 13/40
Step-by-step explanation:
7/8 - 16/5
Adjust based on the LCM
35/40 - 128/40
35-128/40