The object will be at rest if the resultant forces = 0
For the given object, a force of -5.5 Newtons applied to it
So, to be at rest we will add another force equal in magnitude and opposite in direction
So, the answer will be the required force = +5.5 newtons
24. Simplify x^2 + 7x + 12 x + 3
We reduce like terms:
[tex]\begin{gathered} x^2+7x+12x+3 \\ x^2+19x+3 \end{gathered}[/tex]therefore, the answer is x^2+19x+3
the lines are perpendicular if the slope of one line is 4/7 what is the slope of the other line
if two lines are perpendicular, it is true that:
[tex]\begin{gathered} m1\cdot m2=-1 \\ Let\colon \\ m1=\frac{4}{7} \\ m2=other_{\text{ }}line \\ \frac{4}{7}\cdot m2=-1 \\ solve_{\text{ }}for_{\text{ }}m2 \\ m2=-1\cdot\frac{7}{4} \\ m2=-\frac{7}{4} \end{gathered}[/tex]sin38° = ? (Write the Trigonometic ratio as a fraction)
Solution
The trigonometric ratio of sin 38 =
[tex]\begin{gathered} \sin \text{ 38 =}\frac{opposite}{hypothenus} \\ \text{opposite = a} \\ hypothenuse\text{ = c} \\ Sin\text{ 38 =}\frac{a}{c} \\ \end{gathered}[/tex][tex]Sin38^o\text{ = 0.6157= }\frac{6157}{10000}[/tex]Is the ordered pair (2, 7) a solution of the function f(x) = x + 5? *
The ordered pair (2, 7) is NOT a solution of the function
f(x) = x + 5
Explanation:If (2, 7) is a solution of the function f(x) = x + 5, then
f(2) = 7
f(2) = 2 + 2 = 4
Since this is not 7, we conclude that the ordered pair is NOT a solution of the function
Solve by completing the square. x2 - 8x + 5 = 0
Answer:
[tex]\begin{gathered} x_1=4+\sqrt[]{11} \\ x_2=4-\sqrt[]{11} \end{gathered}[/tex]Step-by-step explanation:
Solve the following quadratic completing the square:
[tex]x^2-8x+5=0[/tex]Keep x terms on the left and move the constant to the right side:
[tex]x^2-8x=-5[/tex]Then, take half of the x-term and square it.
[tex](-8\cdot\frac{1}{2})^2=16[/tex]Now, add this result to both sides of the equation:
[tex]x^2-8x+16=-5+16[/tex]Rewrite the perfect square on the left.
[tex]\begin{gathered} (x-4)^2=-5+16 \\ (x-4)^2=11 \end{gathered}[/tex]Take the square root of both sides:
[tex]\begin{gathered} \sqrt[]{(x-4)^2}=\pm\sqrt[]{11} \\ x-4=\pm\sqrt[]{11} \\ x=\pm\sqrt[]{11}+4 \end{gathered}[/tex]Hence, the two solutions of the equation are:
[tex]\begin{gathered} x_1=4+\sqrt[]{11} \\ x_2=4-\sqrt[]{11} \end{gathered}[/tex]Write an explicit formula for An, the n' term of the sequence 14, 10, 6,..
An explicit formula for the arithmetic sequence is aₙ = 14 - 4(n - 1).
How to write an explicit formula for the arithmetic sequence?Mathematically, the nth term of an arithmetic sequence can be calculated by using this mathematical expression:
aₙ = a₁ + (n - 1)d
Where:
d represents the common difference.a₁ represents the first term of an arithmetic sequence.n represents the total number of terms.From the information provided, we have the following parameters:
First term, a₁ = 14
Second term, a₂ = 10
Third term, a₃ = 6
Next, we would determine the common difference as follows:
Common difference, d = a₂ - a₁
Common difference, d = 10 - 14
Common difference, d = -4
Substituting the parameters into the mathematical expression, we have;
aₙ = 14 + (n - 1)(-4)
aₙ = 14 - 4(n - 1).
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I got x > 12 for my answer, but when I checked it, it didn't work. Please help me solve and check!
What is the midpoint of the line segment graphed below?10-(5,9)-10-10-(2,-1)10
Step 1
The midpoint formula is given as;
[tex]\begin{gathered} \frac{x_1+x_2}{2},\frac{y_1+y_2}{2} \\ =\frac{5+2}{2},\frac{9-1}{2} \\ =3.5,4 \end{gathered}[/tex]Answer;
[tex](\frac{7}{2},4)[/tex]Hello can you please tell me if this is right please Simplify expressions by distributing
distribute the fraction into all the terms inside the parentheses
[tex]8\cdot\frac{1}{2}-4g\cdot\frac{1}{2}[/tex]solve the product
[tex]\frac{8}{2}-\frac{4g}{2}[/tex]simplify the fractions
[tex]4-2g[/tex]A triangle has two sides of length 3 and 3. What value could the length of thethird side be? Check all that apply.A. 6B. 12C. 5D. 8E4F. 2
To find out the length of the third segments of the triangle, we can use this formula.
[tex]\begin{gathered} a^2=b^2+c^2 \\ a^2=3^2+3^2 \\ a^2=9+9 \\ a^2=18 \\ a=4.25 \end{gathered}[/tex]The, third length is very close to the 4. thus, the option (E) is correct.
A random number generator is programmed to produce numbers with a Unif (−7,7) distribution. Find the probability that the absolute value of the generated number is greater than or equal to 1.5.
We are given the following uniform distribution:
The probability that the absolute value of the number is in the following interval:
[tex]\begin{gathered} -7The probability is the area under the curve of the distribution. Therefore, we need to add both areas. The height of the distribution is:[tex]H=\frac{1}{b-a}[/tex]Where:
[tex]\begin{gathered} a=-7 \\ b=7 \end{gathered}[/tex]Substituting we get:
[tex]H=\frac{1}{7-(-7)}=\frac{1}{14}[/tex]Therefore, the areas are:
[tex]P(\lvert x\rvert>1.5)=(-1.5-(-7))(\frac{1}{14})+(7-1.5)(\frac{1}{14})[/tex]Simplifying we get:
[tex]P(\lvert x\rvert>1.5)=2(7-1.5)(\frac{1}{14})[/tex]Solving the operations:
[tex]P(\lvert x\rvert>1.5)=0.7857[/tex]Therefore, the probability is 0.7857 or 78.57%.
Verify algebratically if each function is odd, even, or neither. For question #5 only
Answer:
[tex]\text{ odd}[/tex]Explanation:
Here, we want to check if the given function is even or odd
To do that, we find g(x) and g(-x)
If g(x) equals g(-x), the the function is even. Otherwise, the function is odd
We find the functions as follows:
[tex]\begin{gathered} g(x)=7x^3\text{ - x} \\ g(-x)=7(-x)^3-(-x) \\ g(-x)=-7x^3\text{ + x} \end{gathered}[/tex]Finally:
[tex]\begin{gathered} \text{ since g(x) }\ne\text{ g(-x) } \\ \text{Function g(x) is odd} \end{gathered}[/tex]What are the magnitude and direction of w = ❬–10, –12❭? Round your answer to the thousandths place.
The direction of a vector is the orientation of the vector, that is, the angle it makes with the x-axis.
The magnitude of a vector is its length.
The formulas to find the magnitude and direction of a vector are:
[tex]\begin{gathered} u=❬x,y❭\Rightarrow\text{ Vector} \\ \mleft\Vert u|\mright|=\sqrt[]{x^2+y^2}\Rightarrow\text{ Magnitude} \\ \theta=\tan ^{-1}(\frac{y}{x})\Rightarrow\text{ Direction} \end{gathered}[/tex]In this case, we have:
• Magnitude
[tex]\begin{gathered} w=❬-10,-12❭ \\ \Vert w||=\sqrt[]{(-10)^2+(-12)^2} \\ \Vert w||=\sqrt[]{100+144} \\ \Vert w||=\sqrt[]{244} \\ \Vert w||\approx15.620\Rightarrow\text{ The symbol }\approx\text{ is read 'approximately'} \end{gathered}[/tex]• Direction
[tex]\begin{gathered} w=❬-10,-12❭ \\ \theta=\tan ^{-1}(\frac{-12}{-10}) \\ \theta=\tan ^{-1}(\frac{12}{10}) \\ \theta\approx50.194\text{\degree} \\ \text{ Add 180\degree} \\ \theta\approx50.194\text{\degree}+180\text{\degree} \\ \theta\approx230.194\text{\degree} \end{gathered}[/tex]Therefore, the magnitude and direction of the vector are:
[tex]\begin{gathered} \Vert w||\approx15.620 \\ \theta\approx230.194\text{\degree} \end{gathered}[/tex]Using a standard 52-card deck, Michelle will draw 6 cards with replacement. If Event A = drawing all hearts and Event B =drawing no face cards, which of the following best describes events A and B?
The described events can be classified as independent.
Mainly because the probability of one event won't change the probability of the other event.
Hence, the answer is independent.
Grocery store A is selling bananas for $9.75 for 1/2 pound .Grocery store B is selling 5 pounds of Bananas for $3.75 which store us offering the best unit rate
Grocery Store B ($1.33 per pound of bananas)
1) With these data we can write the following, and ,
Grocery Store A:
$ pounds
9.75 1/2
x--------------- 1
1/2x=9.75 x 2
x =19.5
Cross multiplying it:
Grocery Store B
$ pounds
5 3.75
y 1
3.75y=5
y=5/3.75
y=1.33
2) The best unit rate is at Grocery Store B ($1.33 per pound of bananas)
please help! so confused and every tutor keeps dropping my question
First of all, we see that this curve is indeed a function of x.
A function, by definition, assigns exactly one value (generally called y) for each x in the domain.
For a continuous domain like this, if we pass a vertical line through the graph, and this line touches exactly one point at a time, then this graph represents a function of x. And this happens for the given graph.
For the second part, we need to determine the domain and range of this function.
The domain consists of all the values of x for which the function is defined. When it has a filled ball at an ending point of the graph, this means the domain is closed in that point, that is, the x-coordinate of this ending point belongs in the domain.
In this case, for interval notation, we use square brackets to represent the domain - "[" or "[".
When we have a point with an empty ball, on the other hand, the x-coordinate of that point doesn't belong in the domain, and we use parentheses - "(" or ")".
Now, concerning the graph in this question, we see that both endings have filled balls. So, both -3 and 2 (the x-coordinates of these points) belong in the domain.
Therefore, in interval notation, the domain of this function is:
[-3, 2]
Finally, the range is formed by all values of y that are reached by the graph, from the smallest to the larger (global minimum and maximum of the function).
Therefore, the range of this function is:
[-3, 3]
Notice that we also use square brackets to represent the range, since both points with y-coordinates -3 and 3 belong in the graph.
Find the surface area and volume of the sphere. Round your answers to the nearest whole number.C = 4 in.The surface area is aboutsquare inchesThe volume is aboutcubic inches
The circumference of a sphere with radius r is given by the following formula:
[tex]C=2\pi r[/tex]Isolate r from the equation and substitute the value of C to find the raius of the sphere:
[tex]\begin{gathered} \Rightarrow r=\frac{C}{2\pi} \\ \Rightarrow r=\frac{4\pi\text{ in}}{2\pi} \\ \Rightarrow r=2\text{ in} \end{gathered}[/tex]The surface area of a sphere with radius r is given by:
[tex]S=4\pi r^2[/tex]The volume of a sphere with radius r is given by:
[tex]V=\frac{4}{3}\pi r^3[/tex]Substitute r=2 in on each formula to find the volume and surface area of the sphere:
[tex]\begin{gathered} S=4\pi(2in)^2 \\ =4\pi\cdot4in^2 \\ =16\pi in^2 \\ =50.26\ldots in^2 \\ \approx50in^2 \end{gathered}[/tex][tex]undefined[/tex]If {an) is an arithmetic sequence where a1=-23 and the common difference is 6, find a79
Given:
The first term
[tex]a_1=-23[/tex]The common difference, d=6
To find
[tex]a_{79}[/tex]Using the nth term formula,
[tex]\begin{gathered} a_n=a+(n-1)d \\ a_{79}=-23+(79-1)6 \\ =-23+(78)6 \\ =-23+468 \\ =445 \end{gathered}[/tex]Hence, the answer is,
[tex]a_n=445[/tex]The Elkhart Athletic Departments sells T-shirts and Hats at a big game to raise money. They sale the T-shirts for $12 and the Hats for $5. At the last football game they sold a total of 32 items and raised $265. How many T-shirts and Hats were sold at the game?
Let x represent the number of T shirts that they sold
Let y represent the number of hats that they sold
They sold the T-shirts for $12 and the Hats for $5. This means that the cost of x T shirts and y hats would be
12 * x + 5 * y
= 12x + 5y
The total amount raised was $265. It means that
12x + 5y = 265 equation 1
Also, the total number of t shirts and hats sold was 32. It means that
x + y = 32
x = 32 - y
Substituting x = 32 - y into equation 1, it becomes
12(32 - y) + 5y = 265
384 - 12y + 5y = 265
- 12y + 5y = 265 - 384
7y = 119
y = 119/7
y = 17
x = 32 - y = 32 - 17
x = 15
15 T shirts and 17 hats
I will show the answer options later because I can’t add two pictures
We will have the following:
* If Kristin does not decrease the price of her cakes, her projected weekly revenue from cake sales will be $2500.
*If Kristin decreases the price of her cakes, her projected weekly revalue will be $2520.
*Kristin will obtain the same revenue if she sells the cakes for $24 or $21.
if I make 9.75 hour and work 30 hours a week. how much I make in a week? how much I make in a month? how much in a year?
Since you make $9.75 per hour and you work 30 hours a week that means that you make:
[tex]9.75\cdot30=292.5[/tex]Therefore you make $292.5 in a week.
A month has 4 1/3 weeks, then per month you earn:
[tex]292.5\cdot4\frac{1}{3}=1267.5[/tex]Therefore you earn $1267.5 in a month.
Finally since each year has 12 month you earn:
[tex]1267.5\cdot12=15210[/tex]Therefore you earn $15210 in a year.
Two mechanics worked on a car. The first mechanic charged $105 per hour, and the second mechanic charged $120 per hour. The mechanics worked for a combined total of 20 hours, and together they charged a total of $2175. How long did each mechanic work?
Solution
The first mechanic charged $105 per hour.
The second mechanic charged $120 per hour.
The mechanics worked for a combined total of 20 hours
Let the first mechanic work for x hours
Then
[tex]\begin{gathered} 105x+(20-x)120\text{ =2175} \\ 105x+2400-120x=2175 \\ \text{collect like terms} \\ 105x-120x=2175-2400 \\ -15x=-225 \\ \\ \text{Divide both sides by -15} \\ \frac{\text{-15x}}{\text{-15}}=-\frac{225}{\text{-15}} \\ \\ x=15 \end{gathered}[/tex]The first mechanic work for x hours which 15hours
The second mechanic work for (20-x ) hours which is 20-15=5hours
.
Consider the line . 7x-8y=-1Find the equation of the line that is parallel to this line and passes through the point . (-3,-6)Find the equation of the line that is perpendicular to this line and passes through the point . (-3.-6)
we have the line
7x-8y=-1
Find out the slope of the given line
isolate the variable y
8y=7x+1
y=(7/8)x+1/8
the slope is m=7/8
Part a
Find the equation of the line that is parallel to this line and passes through the point . (-3,-6)
Remember that
If two lines are parallel, then their slopes are equal
so
The slope of the parallel line is m=7/8 too
Find out the equation of the line in slope-intercept form
y=mx+b
we have
m=7/8
point (-3,-6)
substitute and solve for b
-6=(7/8)(-3)+b
b=-6+(21/8)
b=-27/8
therefore
The equation is
y=(7/8)x-27/8Part b
Find the equation of the line that is perpendicular to this line and passes through the point . (-3.-6)
Remember that
If two lines are perpendicular, then their slopes are negative reciprocal
so
The slope of the perpendicular line is m=-8/7
Find out the equation of the line in slope-intercept form
y=mx+b
we have
m=-8/7
point (-3,-6)
substitute and solve for b
-6=-(8/7)(-3)+b
b=-6-(24/7)
b=-66/7
therefore
the equation is
y=-(8/7)x-66/7I need quick answers please, is due soon. i need assistance finding 5 points. 2 to the left of vertex, i need the vertex, and 2 to the right of the vertex. the graph only goes up to 14. thank you!
We have to find 5 points of the parabola:
[tex]y=x^2+8x+11[/tex]and then graph it.
We can find the vertex by completing the square:
[tex]\begin{gathered} y=x^2+8x+11 \\ y=x^2+2\cdot4x+16-16+11 \\ y=(x+4)^2-5 \end{gathered}[/tex]As we now have the vertex form of the parabola, we can see that the vertex is at (x,y) = (-4,-5).
We can now calculate two points to the right of the parabola by giving values to x as x = 0 and x = -2:
[tex]y=0^2+8\cdot0+11=11[/tex][tex]\begin{gathered} y=(-2)^2+8\cdot(-2)+11 \\ y=4-16+11 \\ y=-1 \end{gathered}[/tex]We now know two points to the right of the parabola: (0, 11) and (-2, -1).
As the line x = -4 is the axis of symmetry, we will have the same value for y when the values of x are at the same distance from this line.
Then, we can write:
[tex]\begin{gathered} y(0)=y(-8)=11 \\ y(-2)=y(-6)=-1 \end{gathered}[/tex]Then, we have two points to the left: (-8, 11) and (-6, -1).
We can graph the parabola as:
If the measure of one complementary angle is 30° more than twice the other angle measure, writean equation and find the measure of each angle.
For this problem we kow that the measure of one complementary angle is 30º more than twice the other angle measure
If our original angle is xthe complement would be 90-xº. then using the statement we can write the following equation:
[tex]x=2(30+90-x)[/tex]And from this equation we can solve for x like this:
[tex]x=240-2x[/tex]Adding 2x in both sides we got:
[tex]3x=240[/tex]And dividing both sides by 3 we got:
[tex]x=\frac{240}{3}=80º[/tex]And the final answer for this case would be 80º
Given the graph given I need help with questions A - D
Using the graph and the table we can infer that the value of the premium for the insurance amount of $50,000 is $28.29 .
From the given table we can see that the function f(x) represents the insurance amount and the premium for the male population.
therefore we can simply substitute the values from the table.
a)f(50000) = $ 28.29
f(25,000) = $ 14.15
b)From the given table we can see that the function g(x) represents the insurance amount for the female population.
g(75000) = $ 19.25
g(25000) = $ 6.42
c) at f(x) = 14.15 the value of x is $25000
d) From the graph let us compare each values for f(x) and g(x).
f(20000)>f(20000)
f(25000)>g(25000)
f(50000)>g(50000)
f(75000)>g(75000)
f(100000)>g(100000)
One party will promise another party reimbursement in the event with a specific loss, damage, or injury in exchange for a fee in order to protect oneself from financial loss. It is a risk management technique used primarily to guard against the risk of a potential loss.
Hence we can infer that for all values of x , f(x)>g(x).
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Twelve students in mrs.taylors class want to start band. Seven students each made a drum.The rest of the students made 2 shakers each. How many shakers were made? Use the bar model. Need help have to show work on this whole page.
Solution
What do I need to find?
Number of shakers
what information do I need to use?
12 students
7 made a drum each
The remain students made 2 shakers each
how I will use the information?
We need to find the number of students who made shakers and then multiply by 2
Solve the problem
12-7 = 5 students
5* 2= 10 shakers
Then the final answer would be:
10 shakers in total
A university student is selecting courses for his next semester. He can choose from 8 science courses and 4 humanities courses. In how many ways can he choose 4 courses if more than 2 must be science courses
The number of ways which he can choose 4 courses if more than 2 must be science is; 224 ways.
Combination of outcomes;
He can choose from 4 humanities courses and 8 science courses.
If the condition requires that he chooses more than 2 science courses, it follows that;
He can only choose three science courses and only 1 humanities courses.
8C3 x 4C1 = 56x 4 = 224
On this note, the number of ways he can choose the required 4 courses is; 224 ways.
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The admission fee at an amusement park is $1.50 for children and $4 for adults. On a certain day, 277 people entered the park, and the admission fees collected totaled 828.00 dollars. How many children and how many adults were admitted?
Given:
Let x be the number of children.
Let y be the number of adults.
In total, there were 277 people.
So,
[tex]x+y=277\ldots\ldots\ldots(1)[/tex]According to the question, the fee of $1.50 for children and $4 for adults and the total fees collected is $828.
So,
[tex]1.5x+4y=828\ldots\ldots\ldots(2)[/tex]Multiply by 4 in equation (1),
[tex]4x+4y=1108\ldots\ldots\ldots(3)[/tex]Subtracting the equation (2) from (3), we get
[tex]\begin{gathered} 2.5x=280_{} \\ x=112 \end{gathered}[/tex]Substitute x=112 in equation (1), we get
[tex]\begin{gathered} 112+y=277 \\ y=165 \end{gathered}[/tex]Thus,
• The number of children is x = 112.
,• The number of adults is y = 165.
18#Suppose that 303 out of a random sample of 375 letters mailed in the United States were delivered the day after they were mailed. Based on this, compute a 90% confidence interval for the proportion of all letters mailed in the United States that were delivered the day after they were mailed. Then find the lower limit and upper limit of the 90% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. (If necessary, consult a list of formulas.)Lower limit:Upper limit:
ANSWER:
Lower limit: 0.77
Upper limit: 0.84
STEP-BY-STEP EXPLANATION:
Given:
x = 303
n = 375
We calculate the value of the proportion in the following way:
[tex]\begin{gathered} p=\frac{x}{n}=\frac{303}{375} \\ \\ p=0.808 \end{gathered}[/tex]For a 90% confidence interval we have the following:
[tex]\begin{gathered} \alpha=100\%-90\%=10\%=0.1 \\ \\ \alpha\text{/2}=0.1=0.05 \\ \\ \text{ For the normal table this corresponds to:} \\ \\ Z_{\alpha\text{/2}}=1.645 \end{gathered}[/tex]We calculate the limits of the 90% confidence interval using the following formula:
[tex]\begin{gathered} \text{ Lower limit: }p-Z_{\alpha\text{/2}}\cdot\sqrt{\frac{p\cdot(1-p)}{n}}=\:0.808-1.645\cdot\sqrt{\frac{0.808\cdot\left(1-0.808\right)}{375}}\:=0.77 \\ \\ \:\text{Upper limit: }p-Z_{\alpha\text{/2}}\cdot\sqrt{\frac{p\cdot\left(1-p\right)}{n}}\:=0.808+1.645\cdot\sqrt{\frac{0.808\cdot\left(1-0.808\right)}{375}}=0.84 \end{gathered}[/tex]