3 to the power 2x+3 is subtracted by 9 which is equal to 2 times 9 to the power x+1 and is subtrcted by 6

Answer:

x = -0.5

Step-by-step explanation:

Here we have the sentence:

"3 to the power 2x+3 is subtracted by 9 which is equal to 2 times 9 to the power x+1 and is subtracted by 6"

The first part:

"3 to the power 2x+3 is subtracted by 9..."

This can be written as:

[tex]3^{2x + 3} - 9[/tex]

"... is equal to 2 times 9 to the power x+1 and is subtracted by 6"

[tex]3^{2x + 3} - 9 = 2*9^{x + 1} - 6[/tex]

Let's solve this for x.

First, we can add 9 in both sides:

[tex]3^{2x + 3} = 2*9^{x + 1} - 6 + 9 = 2*9^{x + 1} + 3[/tex]

We also know the relations:

[tex]a^n*a^b = a^{n + b}[/tex]

and

[tex](a^n)^m = a^{n*m}[/tex]

We can write the left part as:

[tex]3^{2x + 3} = 3^{2x}*3^3 = (3^2)^x*3^3 = 9^x*27[/tex]

And the right side as:

[tex]2*9^{x + 1} + 3 = 2*9^x*9 + 3 = 18*9^x + 3[/tex]

Then the equation becomes:

[tex]27*9^x = 18*9^x + 3[/tex]

Now let's move both terms with 9^x to the left side:

[tex]27*9^x - 18*9^x = 3\\[/tex]

[tex](27 - 18)*9^x = 3[/tex]

[tex]9*9^x = 3[/tex]

[tex]9^x = 3/9 = 1/3[/tex]

Now remember that:

Ln(a^b) = b*Ln(a)

Then if we apply the Ln( ) function to both sides, we get:

[tex]Ln(9^x) = Ln(1/3)[/tex]

[tex]x*Ln(9) = Ln(1/3)[/tex]

[tex]x = \frac{Ln(1/3)}{Ln(9)} = -0.5[/tex]

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