3. The results of the primary election are shown. Smith 15% Goron 35% Other 10% Fishman 40% (a) Order the popularity of the choices from greatest to least. (b) It was estimated that 280 people were going to vote. If this was true, how many people would have voted for Goron? Show your work. (c) 40 people voted for "Other." Was the estimate of total voters from Part (b) accurate? Explain. Answer: I C Focus 33

Answers

Answer 1

a) The order is;

Fishman

Goron

Smith

Other

b) 98 people would have voted for Goron if the estimation was true

c) The estimate was not correct as the actual value obtained (40) is not same as what was estimated (28)

a) We want to order the popularity of choices from greatest to least

What we have to know and understand here is that the higher the percentage, the greater the popularity

Thus, we have it that;

Fishman

Goron

Smith

Other

b) As we can see from the data presented, Goron had 35% of the votes

So, the number of people that voted for Goron will be;

[tex]\begin{gathered} 35\text{ \% of 280} \\ =\text{ }\frac{35}{100}\times280\text{ = 98} \end{gathered}[/tex]

98 people would have voted for Goron if the estimation was true

c) Here, we want to evaluate if the total we had from part B was correct

What we have to do here is get the number that would have been correct if at all 280 people voted

We have this as;

[tex]\begin{gathered} 10\text{ \% of 280} \\ =\text{ }\frac{10}{100}\times280\text{ = 28} \end{gathered}[/tex]

The estimate was not correct as the actual value obtained (40) is not same as what was estimated (28)


Related Questions

express in scientific notation (9.3 x 10^7) ÷ 23,000 = ? (round to the nearest tenth.)

Answers

Given:

[tex]\frac{9.3\times10^7}{23000}[/tex]

Let's perform the division and express the quotient in scientific notation.

We have:

[tex]\frac{9.3\times10^7}{23000}=\frac{9.3\times10000000}{23000}=\frac{93000000}{23000}=4043.478261[/tex]

Express 4043.478261 in scientific notation:

[tex]undefined[/tex]

which of the following is the correct factorization of the polynomial below?27x^3+1000

Answers

The polynomial is given to be:

[tex]27x^3+1000[/tex]

We can rewrite this expression by applying the knowledge of exponents:

[tex]\Rightarrow(3x)^3+10^3[/tex]

Apply the sum of cubes formula:

[tex]x^3+y^3=\left(x+y\right)\left(x^2-xy+y^2\right)[/tex]

Therefore, we have:

[tex]\left(3x\right)^3+10^3=\left(3x+10\right)\left(3^2x^2-10\cdot \:3x+10^2\right)[/tex]

Hence, we can simplify the expression to give the answer:

[tex]27x^3+1000=\left(3x+10\right)\left(9x^2-30x+100\right)[/tex]

The correct option is OPTION B.

Given the system of equations: 8x + 14y = 4 and -6x - 7y = - 10, what would youmultiply the bottom equation by to eliminate y when adding the two equationstogether?

Answers

We need to multiply the second equation by 2 to eliminate y when adding the two equations

Use a system of equations to solve the following problem.The sum of three integers is 244. The sum of the first and second integers exceeds the third by 48. The third integer is 36 less than the first Findthe three integersAnswer How to enter your answer topens in new windon 5 PointsKeypadKeyboard Shartofirst integer =second integer =third integer =

Answers

Given:

The sum of three integers is 244. The sum of the first and second integers exceeds the third by 48. The third integer is 36 less than the first.

Aim:

We need to find the values of all three integers.

Explanation:

Let x be the first integer.

Let y be the second integer.

Let z be the third interger.

The sum of three integers is 244.

[tex]x+y+z=244[/tex]

The sum of the first and second integers exceeds the third by 48.

[tex]x+y=z+48[/tex]

The third integer is 36 less than the first.

[tex]z=x-36[/tex]

Substitute z=x-36 in the equation x+y=z-48 .

[tex]x+y=x-36+48[/tex]

[tex]x+y=x+12[/tex]

Subtract x from both sides of the equation.

[tex]x+y-x=x+12-x[/tex][tex]y=12[/tex]

Substitute z=x-36 and y=12 in the equation x+y+z=244.

[tex]x+12+x-36=244[/tex]

Add 24 to both sides of the equation.

[tex]2x-24+24=244+24[/tex]

[tex]2x=268[/tex]

Divide both sides by 2.

[tex]\frac{2x}{2}=\frac{268}{2}[/tex][tex]x=134[/tex]

Substitute x=134 in the equation z=x-36

[tex]z=134-36[/tex][tex]z=98[/tex]

We get x=128, y=12 and z =98.

Final answer:

first integer = 128

second integer =`12

third integer = 98.

The parent tangent function is horizontally compressed by a factor of 1/2 and reflected over the x-axis. Which equation could represent function g.the result of this transformation?OA. g(x) = -tan(2x)O B. g(x) = tan(-1/2x)OC. g(x) = tan(-2x)OD. g(x) = -tan(1/2x)

Answers

Given :

The parent tangent function is horizontally compressed by a factor of 1/2 and reflected over the x-axis.

Explanation :

To find the equation of g.

The tangent function is

[tex]f(x)=\tan x[/tex]

It is horizontally compressed by a factor of 1/2.

Then the function becomes

[tex]g(x)=\tan (\frac{1}{2}x)[/tex]

After that it is reflected over x-axis.

[tex]g(x)=-\tan (\frac{1}{2}x)[/tex]

Answer :

Hence the result of the transformation is

[tex]g(x)=-\tan (\frac{1}{2}x)[/tex]

The correct option is D.

The diameter of a bicycle wheel is 26 inches. What is its circumference? (Round to the nearest inch.)

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

Bicycle wheel:

diameter = 26 in

circumference = ?

Step 02:

Circumference

C = π d

C = π * (26 in) = 81.68 in

The answer is:

C = 82 in

Answer:

82 inches.

Step-by-step explanation:

diameter = 26 inches

radius = 13 inches

circumference = 2πr

π = 22÷7 or 3.142

... 2 × 22÷7 × 13 = 81.714

(to nearest inch) = 82inches.

A correlation cannot have the value:A) 0.0B) 0.4C) -1.01D) -0.5E) 0.99

Answers

The possible range of values for the correlation coefficient is -1.0 to 1.0. In other words, the values cannot exceed 1.0 or be less than -1.0. A correlation of -1.0 indicates a perfect negative correlation, and a correlation of 1.0 indicates a perfect positive correlation.

Therefore, the value that is not within the range -1.0 to 1.0 is -1.01

Answer: C)

Let f(x) = 9 - x, g (x) = x*2 + 2x - 8, and h (x) = x - 4

Answers

Solution

We are given the following functions

[tex]\begin{gathered} f(x)=9-x \\ g(x)=x^2+2x-8 \\ h(x)=x-4 \end{gathered}[/tex]

g(x) + f(x)

[tex]\begin{gathered} g(x)+f(x)=(x^2+2x-8)+(9-x) \\ \\ g(x)+f(x)=x^2+2x-8+9-x \\ \\ g(x)+f(x)=x^2+x+1 \end{gathered}[/tex]

h(x) - f(x)

[tex]\begin{gathered} h(x)-f(x)=(x-4)-(9-x) \\ \\ h(x)-f(x)=x-4-9+x \\ \\ h(x)-f(x)=2x-13 \end{gathered}[/tex]

f o h(10)

[tex]\begin{gathered} First \\ h(x)=x-4 \\ h(10)=10-4 \\ h(10)=6 \\ and \\ f(x)=9-x \\ f(6)=9-6 \\ f(6)=3 \\ Now,\text{ to solve} \\ foh(10)=f(h(10)) \\ foh(10)=f(6) \\ \\ foh(10)=3 \end{gathered}[/tex]

3 * g(-1)

[tex]\begin{gathered} First, \\ g(x)=x^2+2x-8 \\ g(-1)=(-1)^2+2(-1)-8 \\ \\ g(-1)=1-2-8 \\ \\ g(-1)=-9 \\ Now\text{ to solve} \\ 3g(-1)=3\times g(-1) \\ \\ 3g(-1)=3\times-9 \\ \\ 3g(-1)=-27 \end{gathered}[/tex]

h(x) * h(x)

[tex]\begin{gathered} h(x)=x-4 \\ Now, \\ h(x)*h(x)=(x-4)(x-4) \\ \\ h(x)*h(x)=x^2-8x+16 \end{gathered}[/tex]

g(x)/h(x)

[tex]\frac{g(x)}{h(x)}=\frac{x^2+2x-8}{x-4},\text{ }x\ne4[/tex]

Find an equation of the line through (1,8) and parallel to y = 4x + 8.y=(Type your answer in slope-intercept form.)

Answers

First of all, remember that parallel lines are those with equivalent slope. So, the given line is

[tex]y=4x+8[/tex]

If the new line we have to find is parallel to this one, that means the slope is

[tex]m=4[/tex]

Because the coefficient of x is always the slope.

Now, we know that the new line must pass through (1,8) and it must have a slope of 4. We can use the point-slope formula

[tex]y-y_1=m(x-x_1)[/tex]

Replacing the point and the slope, we have

[tex]y-8=4(x-1)[/tex]

Then, we solve for y

[tex]y=4x-4+8\rightarrow y=4x+4[/tex]

Therefore, the new parallel line is

[tex]y=4x+4[/tex]

Consider the following linear equation.2y = -1-ainStep 2 of 2: Graph the line.

Answers

As given by the question

There are given that the equation

[tex]y=-1-\frac{2}{5}x[/tex]

Now,

The graph of the line is given below:

Two trees are leaning on each other in the forest. One tree is 19 feet long and makes a 32° angle with the ground. The second tree is 16 feet long.What is the approximate angle, x, that the second tree makes with the ground?

Answers

39º

1) Considering what's been given we can sketch this out:

From these trees leaning on each other, we can visualize a triangle (in black).

2) So now, since we need to find the other angle, then we need to apply the Law of Sines to find out the missing angle:

[tex]\begin{gathered} \frac{a}{\sin(A)}=\frac{b}{\sin (B)} \\ \frac{16}{\sin(32)}=\frac{19}{\sin (X)} \\ 16\cdot\sin (x)=19\cdot\sin (32) \\ \frac{16\sin(X)}{16}=\frac{19\sin (32)}{16} \\ \sin (X)=\frac{19\sin(32)}{16} \\ \end{gathered}[/tex]

As we need the measure of the angle, (not any leg) then we need to use the arcsine of that quotient:

[tex]\begin{gathered} X=\sin ^{-1}(\frac{19\cdot\sin (32)}{16}) \\ X=38.996\approx39 \end{gathered}[/tex]

3) Hence, the approximate measure of that angle X is 39º

Help me with math and explain it in a short solution

Answers

The perimeter is the sum of all the sides of a geometric figure. Since it is a parallelogram, then its opposite sides are equal, so

[tex]\begin{gathered} QR=TS \\ \text{and} \\ QT=RS \end{gathered}[/tex]

In the graph, we can see that the distance between points Q and R is 7 units. To find the distance between points Q and T we can use the formula of the distance between two points in the plane, that is,

[tex]\begin{gathered} d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ \text{ Where} \\ (x_1,y_1)\text{ and }(x_2,y_2)\text{ are the coordinates of the points } \end{gathered}[/tex]

Then, we have

[tex]\begin{gathered} Q(-3,3) \\ T(-5,-3) \\ d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ \text{ Replace} \\ d=\sqrt[]{(-5-(-3))^2+(-3-3)^2} \\ d=\sqrt[]{(-5+3)^2+(-3-3)^2} \\ d=\sqrt[]{(-2)^2+(-6)^2} \\ d=\sqrt[]{4+36} \\ d=\sqrt[]{40} \end{gathered}[/tex]

Finally, we have

[tex]\begin{gathered} \text{ Perimeter }=QR+RS+TS+QT \\ \text{ Perimeter }=7+\sqrt[]{40}+7+\sqrt[]{40} \\ \text{ Perimeter }=26.65 \end{gathered}[/tex]

Therefore, the perimeter of parallelogram QRST is 26.65 units and the correct answer is option B.

Allison stated that 48/90 is a terminating decimal equal to 0.53. Why is she true or why is she wrong.

Answers

Answer:

She was Wrong, because it is not a terminating decimal

Explanation:

Given the fraction;

[tex]\frac{48}{90}[/tex]

Let us reduce the fraction to its least form, then convert it to decimal.

[tex]\frac{48}{90}=\frac{8}{15}[/tex]

converting to decimal we have;

The decimal form of the given fraction is;

[tex]\begin{gathered} 0.533\ldots \\ =0.53\ldots \end{gathered}[/tex]

Which is not a terminating decimal, because it has an unending, repeatitive decimal.

Therefore, she was Wrong, because it is not a terminating decimal

Image courtesy of NASAWhich of New Zealand's physical features is circled by number 2 on the map above?A. the Northern PeninsulaB. the Southern AlpsC. the Canterbury PlainsD. the Eastern HillsPlease select the best answer from the choices providedABOeCD

Answers

C) Canterbury Plains

Simplify 310x + 16y + 310x + 56y ( i need help)

Answers

Answer:

[tex]620x+72y[/tex]

Step-by-step explanation:

[tex]310x+16y+310x+56y \\ \\ =310x+310x+16y+56y \\ \\ =620x+72y[/tex]

A single die is rolled 4 times. Find the probability of getting at least one 6.

Answers

When a dice is rolled the probability of getting one 6 is,

[tex]P(\text{Getting one 6) = }\frac{1}{6}[/tex]

The probability of not getting 6 when a dice is rolled is ,

[tex]P(\text{Not getting 6) = }\frac{5}{6}[/tex]

The probability of getting 6 is independent on how many times the dice is rolled.

The probability of not getting 6 is given as,

[tex]P(\text{ getting atleast one 6) = 1 - P(Not getting 6)}[/tex]

Therefore the probability of getting atleast one 6 when a dice is rolled 4 times is calculated as,

[tex]\begin{gathered} P(\text{Getting 6) = 1 - (}\frac{5}{6})^4 \\ P(\text{Getting 6) = 1 - }\frac{625}{1296} \\ P(\text{Getting 6) = }0.5177 \\ \end{gathered}[/tex]

Thus the probability of getting atleast one 6 when a dice is rolled 4 times is 0.5177 .

Question 8: What is the measure of Angle C?*c525°47°43°1330

Answers

SOLUTION

Angle C is 133 degrees

From the image , angle c is the same as angle a, reason been that they are vertically opposite angles and they are always equal.. let us call angle c and a = x

Angle b = 47 degrees, because they are both vertically opposite angles, and they are always equal.

Angle c + angle a + angle b + 47 = 360 ( sum of angles at a point)

x + x + 47 + 47 = 360

2x + 94 =360

2x = 360-94

2x =266

x= 266/2

x=133 degrees

So angle C is 133 degrees

Option D

Could I please get help with this. I can’t seem to figure out the answers to each of the figures after multiple tries.

Answers

Explanation:

Two figures are congruent when they have the same size and shape and two figures are similar when they have the same shape but not necessarily the same size. In similar figures, the ratio of the corresponding sides is constant.

Answer:

Then, for each pair, we get:

|x-2|-3 >or equal to 2

Answers

By solving the linear inequation it is obtained that  [tex]x \leq -3[/tex] or [tex]x \geq 7[/tex].

What is linear inequation?

Expressions with linear inequalities compare any two values using inequality symbols like ‘<’, ‘>’, ‘≤’ or ‘≥’. These values could be either numerical, algebraic, or both. Examples of numerical inequalities include 1011 and 20>17, while algebraic inequalities include x>y, y19-x, and x z > 11 (also called literal inequalities). Here is a lesson on linear inequalities for class 11. Inequality in mathematics, linear inequalities, graphing of linear inequalities, as well as detailed examples are all covered in this article.

Here,

The given linear inequation is

[tex]|x - 2| - 3 \geq 2[/tex]

Now,

[tex]|x -2| - 3 \geq 2\\|x - 2| \geq 2+3\\|x-2| \geq 5\\[/tex]

For [tex]x \geq 2\\[/tex]

[tex]x - 2 \geq 5\\x \geq 2 + 5\\x\geq 7[/tex]

For [tex]x < 2[/tex]

[tex]2 - x \geq 5\\x \leq 2 - 5\\x \leq -3[/tex]

So the solution set is [tex]x \leq -3[/tex] or [tex]x \geq 7[/tex]

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consider all of the 4 digit numbers that can be made from the digits 0 to 9 (assume that the numbers cannot start with 0) . What is the probability of choosing a random number from this group that is less than or equal to 8000? Enter a fraction or round your answer to 4 decimal places, if necessary.

Answers

First, we need to determine the total amount of numbers fulfilling the conditions:

- 4 digits

- Not starting with 0

For the first digit, we have then 9 possible numbers: 1, 2, 3, 4, 5, 6, 7, 8 and 9.

For the second, third and fourth, we have 10 possible numbers 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9.

Then, to determine the amount of numbers available we just need to multiply the possibilities for each digit:

[tex]9\cdot10\cdot10\cdot10=9000[/tex]

Then, randomly choosing one of the given numbers, we have 9000 possible outcomes. Those will be numbers from 1000 to 9999.

Now we just need to determine how many numbers among those 9000 are lower than or equal to 8000.

As the numbers start in 1000, we have 7001 cases where the randomly selected number is lower than or equal to 8000.

We obtain 7001 since 8000 - 1000 = 7000 but we need to consider also the number 1000.

The probability will be then:

[tex]\frac{7001}{9000}\approx0.7779[/tex]

Find the equation of the linear function represented by the table below in slope-intercept form.X1234y691215******

Answers

Given:

Given a table.

Required:

To find the equation of the linear function.

Explanation:

From the table

[tex]\begin{gathered} (x1,y1)=(1,6) \\ (x2,y2)=(2,9) \end{gathered}[/tex]

The general form of equation is

[tex]y=mx+b[/tex]

Here the slope is

[tex]\begin{gathered} m=\frac{y2-y1}{x2-x2} \\ \\ =\frac{9-6}{2-1} \\ \\ =\frac{3}{1} \\ \\ =3 \end{gathered}[/tex]

So

[tex]y=3x+b[/tex]

Now we have to find the value of b, by using the point (1,6)

[tex]\begin{gathered} 6=3(1)+b \\ \\ 6-3=b \\ \\ b=3 \end{gathered}[/tex]

Now

[tex]y=3x+3[/tex]

Final Answer:

The linear equation is

[tex]y=3x+3[/tex]

find the odds of an event occurring given the probability of the event 6/7

Answers

Odds is the ratio of favourable outcomes to non-favourable outcomes:

Let:

P = probability of an event occurring = 6/7

Q = probability of the event not occurring = 1 - P = 1 - 6/7 = 1/7

Therefore, the odds will be:

[tex]\frac{P}{Q}=\frac{\frac{6}{7}}{\frac{1}{7}}=6[/tex]

which is equal to 73.5÷by 15

Answers

The answer to this division is 4.9.

You can also multiply the numerator (dividend) and the denominator (divisor) by 10, so you can have the equivalent division:

[tex]\frac{73.5}{15}\cdot\frac{10}{10}=\frac{735}{150}=4.9[/tex]

And proceed as before. The result will be the same.

Graph the function. Label the vertex and axis of symmetry. 1. f(x)=(x-2)^2

Answers

We have the following:

Solve for v.37+1=-2v-8v-4

Answers

[tex]\begin{gathered} \Rightarrow\frac{-3}{2v-8}+1=\frac{-7}{v-4} \\ \Rightarrow\frac{-3+2v-8}{2v-8}=\frac{-7}{v-4} \\ \Rightarrow\frac{-3+2v-8}{2(v-4)}=\frac{-7}{v-4} \\ \Rightarrow\frac{-3+2v-8}{2}=-7 \\ \Rightarrow-3+2v-8=-14 \\ \Rightarrow2v=-14+8+3 \\ \Rightarrow v=\frac{-3}{2} \end{gathered}[/tex]

1 ptsQuestion 5Jane started jogging 5 miles from home, at a rate of 2 mph. Write the slope-intercept form of an equation for Jane's position relative to home.

Answers

Answer

[tex]y=2x+5[/tex]

SOLUTION

Problem Statement

The question wants us to model the distance Jane is from her home given her initial starting point (5 miles from home) and her speed (2 mph)

Explanation

To solve the question, we simply need to model her jogging using the equation of a line.

The general equation of a line is given as:

[tex]\begin{gathered} y=mx+c \\ \text{where,} \\ m=\text{slope}=\text{this represents Jane's speed} \\ c=y-\text{intercept}=\text{this represents her initial position from her home} \\ x=\text{time taken for Jane to move} \\ y=\text{Jane's final position after moving for time, x} \end{gathered}[/tex]

We have been told that her speed is 2 mph. Thus, m = 2. We have also been given her initial position from her house to be 5 miles.

Jane starts jogging 5 miles from her home, thus, her position relative to her home will continue to increase as she jogs on at 2 mph. Thus, c = 5 and NOT -5.

This means we can write the equation for her position is:

[tex]\begin{gathered} m=2,c=5 \\ \therefore y=2x+5 \end{gathered}[/tex]

Final Answer

[tex]y=2x+5[/tex]

can you please help me

Answers

AB = 3x + 4

BC = 7x + 9

AB + BC = AC

AC = 143

Let us add AB and BC then equate their sum by 143

[tex]AC=AB+BC=3x+4+7x+9=(3x+7x)+(4+9)[/tex]

First, step add the like terms

[tex]AC=10x+13[/tex]

Equate AC by its length 143

[tex]10x+13=143[/tex]

Now we have an equation to solve it

To solve the equation let us move 13 from the left side to the right side by subtracting 13 from both sides

[tex]\begin{gathered} 10x+13-13=143-13 \\ 10x=130 \end{gathered}[/tex]

To find x divide both sides by 10 to move 10 from the left side to the right side

[tex]\begin{gathered} \frac{10x}{10}=\frac{130}{10} \\ x=13 \end{gathered}[/tex]

Now let us find AB and BC

Substitute x by 13 in each expression

AB = 3(13) + 4 = 39 + 4 = 43

BC = 7(13) + 9 = 91 + 9 = 100

The length of AB is 43 units

The length of BC is 100 units

How many men and women should the sample include. What were the steps you took to solve?

Answers

We are asked to determine the sample size to determine the difference in the proportion of men and women who own smartphones with a confidence of 99% and an error of no more than 0.03. If we assume that both samples are equal then we can use the following formula:

[tex]n=\frac{Z^2_{\frac{\alpha}{2}}}{2E^2}[/tex]

Where Z is the confidence and E is the error. Replacing the values we get:

[tex]n=\frac{(0.99)^2}{2(0.03)^2}[/tex]

Solving the operations we get:

[tex]n=544.5\cong545[/tex]

Therefore, each sample of men and women should be of 545.

In the rectangle below, B D = 4x – 2, AC = 5x-11, and m ZAED = 82º.Find AE and m ZECB.BEAE =m ZECB =DС

Answers

Given :

[tex]\begin{gathered} BD\text{ = 4x + 2} \\ AC\text{ = 5x - 11} \\ \angle AED=82^0 \end{gathered}[/tex]

Required :

[tex]AE\text{ , }\angle\text{ ECB}[/tex]

Recall from the properties of a rectangle that

[tex]\text{The diagonals have the same length}[/tex]

Hence :

[tex]\begin{gathered} AC\text{ = BD} \\ 5x\text{ - 11 = 4x -2 } \\ \text{collect like terms} \\ 5x\text{ - 4x = 11 - 2} \\ x\text{ = 9} \end{gathered}[/tex]

the function is shaped like a u what is the standard form or basic function.

Answers

The function shaped like a U is in the form of a basic quadratic equation and is represented as a parabola.

The graph of a quadratic function is a U-shaped curve called a parabola. An important feature of graphs is that they have extreme points called vertices.

When the parabola opens upwards, the vertex represents the lowest point of the graph, or the minimum value of the quadratic function. When the parabola opens downwards, the vertex represents the highest point or maximum of the graph.

In both cases, the vertex is the inflection point of the graph. Graphs are also symmetrical about a vertical line through the vertices called the axis of symmetry.

The standard form or basic function for a parabola will be in the form of a quadratic function such as -

[tex]f(x)=a(x-h)^{2} +k[/tex]

where, [tex](h,k)[/tex] = vertex

Thus, the function shaped like a U is in the form of a basic quadratic equation and is represented as a parabola.

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NEED ANSWER ASAP Solve this system of equations:3x - 2y = - 8y= 3/2x - 2I NEED ALL THE STEPS (06.04)The line of best fit for a scatter plot is shown:A scatter plot and line of best fit are shown. Data points are located at 1 and 4, 2 and 6, 2 and 3, 4 and 3, 6 and 1, 4 and 5, 7 and 2, 0 and 6. A line of best fit passes through the y-axis at 6 and through the point 4 and 3.What is the equation of this line of best fit in slope-intercept form? (4 points)y = 6x + three fourthsy = 6x + three fourthsy = negative three fourthsx + 6y = three fourthsx + 6 can someone help me with this question Which of the following rational expressions has the domain restrictions X = -6 and x = 1? Convert the radical to exponential form. Assume variables represent positive real numbers. To reduce dangerous swelling in the brain, physician sometimes administer intravenous hypertonic saline, a 5.0%(w/v) Solution of salt (NaCI) In water. Calculate the volume of the solution that contains 0.50 g of NaCl. Be sure your answer has unit symbol and his rounded to the correct number of significant digits F (x)=x^2+4 what is f(-4) find the hight of a cone with a volume of 150 in 3 and a radius of 10 in. Simplify. Final answer should be in standard form NUMBER 18 The speed limit on a road is 50 mph. A car drives 19 miles in 22 minutes. Is the car breaking the speed limit? You must show your workings. For each ordered pair, determine whether it is a solution to the sytem of equations. 1. Add a subordinating conjunction and a 'when' and a 'where' to expand the following sentence: The bears were eating the berries. Graph: y = - 4x + 2Its just on a generic coordinate plane Graph AABC with A(4, 7), B(0,0), and C(8, 1).a. Which sides of AABC are congruent? How do you know?b. Construct the bisector of ZB. Mark the intersection of the ray and AC as D.c. What do you notice about AD and CD? Which of the following is NOT a method for living more sustainably on Earth?a) Repair products when it breaks or gets worn out. Many brand name companies including clothing and electronic stores offer repair services for you nowb) Reuse with refillable glass or stainless stell water bottles and by shopping with cloth bags at grocery and retail stores including malls.c) Refuse to use single-use products such as plastic grocery bags and takeout utensils including straws and condiments for ketchup and soy sauce.d) Recycle by using plastic shopping bags to dispose paper/plastics/bags/metals into blue bins and composting organic waste into green bins.e) Reduce by shopping only in-store (online shipping orders have escess packaging) and buying only essential costumer products (not the latest fashion in clothing or the newest model in electronics) or think about renting seasonal items rather than buying it. Resources used by the grasshopper would increase as the population___.a. remains steady c. decrease in size b. increase exponentially d.migrate B. A concrete tank has an external diameter of 10 m and an internal height of 3 m. If the walls and bottom of the tank are 30 cm thick, how many cubic meters of concrete are required to make the tank? 10 m 30 cm 3 m 30 cm 8Suppose Z follows the standard normal distribution. Use the calculator provided, or this table, to determine the value of c so that the following is true.p=(-c Z c ) =0.9127Carry your intermediate computations to at least four decimal places. Round your answer to two decimal places. One end of a thin rod is attached to a pivot about which it can rotate without friction. Air resistance is absent. The rod has a length of 0.48 m and is uniform. It is hanging vertically straight downward. The end of the rod nearest the floor is given a linear speed V so that the rod begins to rotate upward about the pivot. What must be the value of V such that the rod comes to a momentary halt in a straight up orientation, exactly opposite to its initial orientation? 9. Find the volume of the triangular pyramid. (2pts)-10 mI9 m16 m