Answer:
a. 6 moles of O₂
b. 4.06×10²⁴ molecules of O₂
c. 3.04 g of KCl
Explanation:
Reaction of decomposition is:
2KClO₃ → 2KCl + 3O₂
a. See stoichiometry value
2 moles of potassium chlorate can decompose to 2 moles of potassium chloride and 3 moles of oxygen. Ratio is 2:3
If 2 moles of KClO₃ can decompose to 3 moles of O₂
Then 4 moles, may decompose to (4 . 3)/2 = 6 moles of O₂
b. In this case, the stoichiometry is the same.
Per 2 moles of KClO₃, I produce 2 moles of KCl
Then, 4.5 moles of KCl, were produced by 4.5 moles of KClO₃
We apply, the last relation:
(4.5 . 3) /2 = 6.75 moles of O₂ are also produced.
How many molecules are in 6.75 moles?
6.75 mol . 6.02×10²³ molecules/mol = 4.06×10²⁴ molecules of O₂
c. First of all, we convert the mass to moles:
5g . 1mol /122.55g = 0.0408 moles of salt
As ratio is 2:2, 0.0408 moles of salt, decompose to 0.0408 moles of KCl
We convert the moles to mass: 0.0408 mol . 74.55g /mol = 3.04g
Laura can use a toy car to demonstrate the force of gravity by doing which of these?
Letting the toy car roll down a ramp
Placing the toy car on the floor
Lifting the toy car onto a shelf
Pushing the toy car across a table
Answer:
letting the car fall down the ramp i got that right.
Explanation:
A chemist needs to know the mass of a sample of to significant digits. He puts the sample on a digital scale. This is what the scale shows:
0
0
0
7
6
.
3
g
If this measurement is precise enough for the chemist, round it to significant digits.
Otherwise, press the "No solution" button.
What is produced when concentrated aqueous sodium chloride is electrolysed?
2 CH3OH + 3 02 2 CO2 + 4H2O
What is the mass of oxygen (O2) that is required to produce 579 g of carbon dioxide (CO2)?
. Your answer should have three significant figures.
Answer:
632 g
Explanation:
2CH₃OH + 3O₂ → 2CO₂ + 4H₂OFirst we convert 579 g of CO₂ into moles, using its molar mass:
579 g CO₂ ÷ 44 g/mol = 13.16 mol CO₂Then we convert CO₂ moles into O₂ moles, using the stoichiometric coefficients:
13.16 mol CO₂ * [tex]\frac{3molO_2}{2molCO_2}[/tex] = 19.74 mol O₂Finally we convert O₂ moles into grams, using its molar mass:
19.74 mol O₂ * 32 g/mol = 632 gnumber of molecules in lithium oxide
4li2O
Answer:
Explanation:
Lithium is in group 1 so there's 1 outermost shell electron.
Oxygen is in group 6 so there's 6 outermost shell electron.
To react lithium with oxygen, we need 2 lithium and 1 oxygen
Each lithium transfer 1 electron to the oxygen and oxygen gain 2 electrons.
[tex]Li_{2}O\\[/tex] formed.
If there's 4 lithium oxide, 4 molecules will be there.
If you mean how many ATOMS are there, there will be 3×4=12 atoms.
Answer all the following questions by putting a circle around a letter A.B.C or D
1. Air contains about
A. 3% carbon (IV) oxide.
B. 4%noble gases.
C. 21%oxygen
D. 69% nitrogen
Answer:
C. 21%oxygen
Explanation:
Dry air contains 78.09% nitrogen, 20.95%oxygen, 0.93% argon, 0.04% carbon dioxide, and small amounts of other gases.
Which element, when combined with fluorine, would most likely form an
ionic compound?
A. phosphorus
B. lithium
C. carbon
D. chlorine
Help help help !!!!!!
Answer:
3. 116.5 V
4. 119.6 V
Explanation:
3. Determination of the voltage.
Resistance (R) = 25 Ω
Current (I) = 4.66 A
Voltage (V) =?
V = IR
V = 4.66 × 25
V = 116.5 V
Thus, the voltage is 116.5 V
4. Determination of the voltage.
Current (I) = 9.80 A
Resistance (R) = 12.2 Ω
Voltage (V) =?
V = IR
V = 9.80 × 12.2
V = 119.6 V
Thus, the voltage is 119.6 V
help someone i need this
How many particles are in 9.58 x 1023 of potassium sulfate (K2SO4)? (5.77 x 1047 particles)
Answer:
[tex]5.77x10^{47}particles.[/tex]
Explanation:
Hello!
In this case, since we are given 9.58x10²³ moles of potassium sulfate, it is possible to compute the particles according to the Avogadro's number:
6.022x10²³
As shown below:
[tex]9.58x10^{23}mol*\frac{6.022x10^{23}}{1mol}\\\\5.77x10^{47}particles.[/tex]
Best regards!
I have an unknown initial volume of gas
held at a temperature of 115 K in a
container with a pressure of 6 atm. I
increase the temperature to 225 K and
decrease the pressure to 2,800 mmHg
and it causes the final volume of the gas
to be 29 L. What was the initial
volume?
Answer:
V₁ = 0.025 Liters = 25 ml
Explanation:
P₁ = 6 Atm P₂ = 7800mm/760mm/Atm = 0.01 Atm
V₁ = ? V₂ = 29 Liters
T₁ = 115 K T₂ = 225 K
P₁V₁/T₁ = P₂V₂/T₂ => V₁ = P₂V₂T₁/P₁T₂
V₁ = (0.01 Atm)(29L)(115K)/(6 Atm)(225K) = 0.025 Liters = 25ml
Which statement below best describes a volatile liquid?
Question 17 options:
1.A liquid that doesn't evaporate under atmospheric pressure
2.A liquid that evaporates slowly at low temperatures
3.A liquid that evaporates rapidly at low temperatures
4.A liquid that requires a large amount of energy to evaporate
Answer:
A liquid that evaporates rapidly at low temperatures
Explanation:
Answer:
A liquid that evaporates rapidly at low temperatures.
Explanation:
A volatile liquid such as gasoline evaporates easily. Its chemicals aren't held together as strongly, and room temperature is often enough to break intermolecular bonds and evaporate them.
PF
We obviously cannot wait for million years to determine the half-life of technetium, or even years to determine the half-life of plutonium. The half-life of a substance is determined using a Geiger counter, which is essentially a tube filled with an inert gas. When a particle decays and produces radiation, it briefly ionizes the gas and produces a detectable electric pulse, which is amplified and counted by a detector (before digital displays were available, you would hear clicks and see a needle register on a dial). Determine the formula for the half-life of a substance with an initial count of pulses and a count of pulses minutes later.
The question is incomplete, the complete question is;
We obviously cannot wait for 4 million years to determine the half-life of technetium, or even 87.7 years to determine the half-life of plutonium. The half-life of a substance is determined using a Geiger counter, which is essentially a tube filled with an inert gas. When a particle decays and produces radiation, it briefly ionizes the gas and produces a detectable electric pulse, which is amplified and counted by a detector (before digital displays were available, you would hear clicks and see a needle register on a dial). Determine the formula for the half-life of a substance with an initial count of No pulses and a count of N1 pulses M minutes later.
Answer:
M1/2 = 0.693/k
Explanation:
Given that the initial count rate is No pulses
The count rate after M minutes is N1
Then from;
A = Aoe^-kt
A= N1
Ao=No
I can now write;
N1 = Noe^-kM
The half life is the time taken for the activity of the radioactive nuclide to reach half its initial value. Hence;
N1/No =e^-kM = 1/2
Taking natural logarithm of both sides as shown below;
-kM1/2 = ln(1/2)
M1/2 = - (ln(1/2)/k)
M1/2 = 0.693/k
Please help ASAP! Please and thank you have a great and blessed day!,
How many grams of AlCl3 will be produced if 3.85 moles of Al react? Al + ___Cl2 → ___AlCl3
Answer:
513.975g
Explanation:
I'm assuming that the question has Aluminium and Chlorine as the question is not clear.
1. Balance the equation
2 Al + 3 Cl2 → 2AlCl3
2. Use the mole = mass/mr equation and molar ratio to find the mass of AlCl3
133.5 x 3.85 = 513.975g
I have a balloon that can hold 100. liters
of air. If I blow up this balloon with 3.0
moles of oxygen gas at a pressure of 1.0
atmosphere, what is the temperature of
the balloon?
Answer:
T = 4.062V
Explanation:
from PV = nRT => T = PV/RT
P = 1 atm
V = Final Volume
n = 3 moles
R = 0.08206 L·atm/mol·K
T = ?
T = 1 atm · V(Liters)/(3 moles)(0.08206L·atm/mol·K) = 4.062·V(final) Kelvin
The temperature of the balloon is 406 K
We'll begin by listing out what was given from the question. This is shown below:
Volume (V) = 100 L
Mole of oxygen (n) = 3 moles
Pressure (P) = 1 atm
Temperature (T) =?We can obtain the temperature of the balloon by using the ideal gas equation as shown below:
PV = nRTNOTE:P is the pressure.
V is the volume.
n is the number of mole
R is the gas constant (0.0821 atm.L/Kmol)
T is the temperature.
Applying the ideal gas equation, we have:
PV = nRT
1 × 100 = 3 × 0.0821 × T
100 = 0.2463 × T
Divide both side by 0.2463
T = 100 / 0.2463
T = 406 KTherefore, the temperature of the balloon is 406 K
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How many sulfur atoms are in 3.7 mol of SO2?
× 10 S atoms
Answer: 22.3 *10^23 S atoms
Explanation:
What is the molar mass of V(CO3)2?
Calculate the percent composition (out of 100) by weight of potassium in potassium carbonate decahydrate.
Answer:
12.26%
Explanation:
MM K = 39.1 g/mol
MM K2CO3 . 10H2O = 2x39.1 + 12.01 + 3 x 15.99 + 10 x 18.02= 318.38 g/mol
% by weight = (MM K/MM K2CO3.10H2O ) x 100= (39.1/318.8) x 100=12.26 %
The percent composition by weight of potassium in potassium carbonate decahydrate is 13.98%
Let's represent the chemical formula of the compound as follows;
potassium carbonate decahydrate = CH₂0KO₁₃
The molecular mass of the compound can be calculated as follows:
Molecular mass of CH₂₀KO₁₃molecular mass = 12 + 20 + 39 + (16×13) = 279 g/molmass of potassium = 39 g
Therefore,
% mass of potassium = 39 / 279 × 100
% mass of potassium = 3900 / 279
% mass of potassium = 13.9784946237
% mass of potassium = 13.98 %
learn more on percentage composition here: https://brainly.com/question/3905173
An aqueous solution contains
32.7% KCI (weight weight %)
How many grams of KCl are
contained in 100 g of this solution
Molar Mass
KCE: 74.55 g/mol
H20 18.016 g/mol
Answer:
32.7
Explanation:
I just did it and got it right
which statement explains this observation?
Answer:
should be D. Hope this helpsss!
If you have 9.56 moles of aluminum oxide how many moles of sodium oxide could you produce?
Answer:
The answer is 28.68 moles
Explanation:
Hope this helped Mark BRAINLEST!!!
how many atoms are in 4.67 grams of sample of silicon
Hyenas eat larger mammals like antelope and wildebeest, but will also eat lizards, birds, snakes, and insects. What type of teeth would you expect a hyena to have?
Answer:
Large Sharp Teeth
Explanation:
i got a 100 on my test!
Large Sharp Teeth !
i got it right on my quiz
which property is a property of water
Answer: Polarity, Boiling and Freezing Points, Specific Heat Capacity, Density, Surface Tension, Heat of Vaporization and Vapor Pressure, Capillary Action, Solid State (Ice), Liquid State (Liquid Water), Gas State (Steam),
Explanation: Water molecules are polar, so they form hydrogen bonds. This gives water unique properties, such as a relatively high boiling point, high specific heat, cohesion, adhesion, and density.
Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial chemist studying this reaction fills a flask with of sulfur dioxide gas and of oxygen gas, and when the mixture has come to equilibrium measures the partial pressure of sulfur trioxide gas to be . Calculate the pressure equilibrium constant for the reaction of sulfur dioxide and oxygen at the final temperature of the mixture. Round your answer to significant digits.
Answer:
The answer is "[tex]\bold{4.97 \times 10^{-2}}[/tex]"
Explanation:
Please find the complete question in the attached file.
Equation:
[tex]2SO_2+O_2 \leftrightharpoons 2SO_3[/tex]
at [tex]t=0 3.3 \ \ \ \ \ \ \ \ \ \ 0.79[/tex]
at equilibrium [tex]3.3-p \ \ \ \ \ \ \ \ \ \ 0.79 - \frac{P}{2} \ \ \ \ \ \ \ \ \ \ \ \ P[/tex]
[tex]p= 0.47 \ \ atm\\\\SO_2=3.3-0.47 = 2.83 \ \ atm\\\\O_2= 0.74 -\frac{0.47}{2}=0.74-0.235=0.555 \ atm\\\\K_P=\frac{[PSO_3]^2}{[PSO_2]^2[PO_2]}\\\\[/tex]
[tex]=\frac{0.47^2}{2.83^2\times 0.555}\\\\=4.97 \times 10^{-2}[/tex]
What is the molar mass of H2CO3?
(Molar mass of H = 1.0079 g/mol; C = 12.010 g/mol; O = 15.999 g/mol)
Answer:
molar mass of H2CO3 = 72.0228
Answer:
62.02 g/mol
Explanation:
Took the test and got it right. if you have enough faith in brainly youll choose the right answer
If 4 moles of sulfur reacts with 9.5 moles of oxygen, how many moles of oxygen would remain after the reaction ?
Which part of a calcium atom in the ground state is represented by the dots in its Lewis electron-dot diagram?
Answer:
There are two dots are present on the left side of calcium atom which represents the unpaired electrons present in the outermost shell. This structure is presented by Lewis in order to show the number of unpaired electrons in the atom.
Explanation:
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