y = 20x - 250
Complete the remainder of the table for the given rules
To complete the table you have to input each value of x in the given equation and solve for y:
Function:
[tex]y=-2x+9[/tex]For x= -2
[tex]\begin{gathered} y=-2\cdot(-2)+9 \\ y=4+9 \\ y=13 \end{gathered}[/tex]x= -2 → y=13
For x= 0
[tex]\begin{gathered} y=-2\cdot0+9 \\ y=0+9 \\ y=9 \end{gathered}[/tex]x=0 → y=9
For x= 2
[tex]\begin{gathered} y=-2\cdot2+9 \\ y=-4+9 \\ y=5 \end{gathered}[/tex]x=2 → y=5
For x= 4
[tex]\begin{gathered} y=-2\cdot4+9 \\ y=-8+9 \\ y=1 \end{gathered}[/tex]x=4 → y=1
Find the largest angle of △TUV. Assume that s is a positive number.
Remember that
In any triangle: The shortest side is always opposite the smallest interior angle. The longest side is always opposite the largest interior angle
so
In this problem
the largest interior angle is opposite to the longest side (TU)
that means
the largest interior angle isAt store A, oranges are $3.99 for 5 apples. At store B oranges are $20 for 7 apples which is the better deal?
Answer:
Store A
Explanation:
To know which is the best deal, we need to find the price per apple for each store, so we need to divide the price by the number of apples.
For store A:
[tex]\frac{\text{ \$3.99}}{5\text{ Apples}}=0.798\text{ per apple}[/tex]For Store B:
[tex]\frac{\text{ \$20}}{7\text{ Apples}}=2.85\text{ per apple}[/tex]So, the best deal is Store A because the price per apple is less than the price of Store B.
The lowest airport in the world is Atyrau Airport in Kazakhstan at 72 feet below sea level. How would we represent this elevation using negative numbers? 6.NS.5
ANSWER
-72 ft
EXPLANATION
We can draw a number line:
If the 0 of the number line is sea level, we would normally say that all positive numbers are those that are above sea level and negative numbers those that are below sea level.
Therefore, to represent an elevation that is below sea level, we'd write it as a negative number: -72 ft
Find the circumference of this circleusing 3 for T.C ~ [?]14C = 27r
Hello! To calculate the circumference, we have to use the formula below:
[tex]C=2\cdot\pi\cdot r[/tex]pi = 3
radius (r) = 14
Replacing these values in the formula, we will have:
[tex]\begin{gathered} C=2\cdot3\cdot14 \\ C=6\cdot14 \\ C=84 \end{gathered}[/tex]Shaun estimated that the attendance at a college basketball game was 4,000. The actual attendance was 3,475. What is the percent error of Shaun's estimate? Round to the nearest whole percent.
Percentage = 100 * (4000 - 3475)/3475 = 100 * (525/3475) = 52500/3475 = 15.1 %
Answer:
15.1%
What are the coordinates of vertex C'after rotating the figure 180° about theorigin?у6BID42A АEXo024 6A. (-6,4)B. (4.-6)C. (4,6)D. (-4,-6)
Vertex C (4, 6 ) Rotation 180º about the origin CCW c' (-4, -6)
C (x, y ) C ' (-x, -y )
________________
Answer
Option D
Ronald was 1.5 times olderthan Megan. If Ronald was 27years old, how old is Megan?Write an equation to solve.
Solution:
Let x represent Ronald's age, and y represent Megan's age.
Thus,
[tex]\begin{gathered} x\Rightarrow Ronald^{\prime}s\text{ age} \\ y\Rightarrow Megan^{\prime}s\text{ age} \end{gathered}[/tex]Given that Ronald was 1.5 times older than Megan, we have the equation to be represented
[tex]x=1.5y\text{ ---- equation 1}[/tex]If Ronald was 27 years old, we have
[tex]x=27[/tex]Substituting the value of 27 for x into equation 1, we have
[tex]\begin{gathered} 27=1.5y \\ solve\text{ for y by dividing both sides by the coefficient of y,} \\ \frac{27}{1.5}=\frac{1.5y}{1.5} \\ \Rightarrow y=18 \end{gathered}[/tex]This implies that Megan's age is
[tex]18\text{ years}[/tex]Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following probability, given the number of trials andthe probability of obtaining a success. Round your answer to four decimal places.P(X ≤ 4), n = 8, p = 0.4
Given:
n = 8, p = 0.4
To find:
P(X ≤ 4)
To determine the given probability, we will apply the binomial probability formula:
[tex]\begin{gathered} $$P(x=X)=^nC_x\times p^x\times q^{n-x}$$ \\ n\text{ = number of trials} \\ p\text{ = number of success} \\ q\text{ = number of failure} \end{gathered}[/tex][tex]P\left(X≤4\right)\text{ = P\lparen x = 0\rparen + P\lparen x = 1\rparen + P\lparen x =2 \rparen + P\lparen x = 3\rparen + P\lparen x = 4\rparen}[/tex][tex]\begin{gathered} p\text{ + q = 1} \\ q\text{ = 1- p} \\ q\text{ = 1 - 0.4} \\ q\text{ = 0.6} \\ \\ P(x=0)=\text{ }^8C_0\times(0.4)^0\times(0.6)^{8-0} \\ P(x\text{ = 0\rparen = 0.01679616} \\ \\ P(x=1)=\text{ }^8C_1\times(0.4)^1\times(0.6)^{8-1} \\ P(x\text{ = 1\rparen = 0.08957952} \end{gathered}[/tex][tex]\begin{gathered} P(x=2)=\text{ }^8C_2\times(0.4)^2\times(0.6)^{8-2} \\ P(x\text{ = 2\rparen = 0.20901888} \\ \\ P(x=3)=\text{ }^8C_3\times(0.4)^3\times(0.6)^{8-3} \\ P(x\text{ = 3\rparen = 0.27869184} \\ \\ P(x=4)=\text{ }^8C_4\times(0.4)^4\times(0.6)^{8-4} \\ P(x\text{ = 4\rparen = 0.2322432} \end{gathered}[/tex][tex]\begin{gathered} P(X≤4)\text{ = 0.01679616 + 0.08957952 + 0.20901888 + 0.27869184 + 0.2322432} \\ \\ P\left(X≤4\right)\text{ = 0.8263296} \\ \\ To\text{ 4 decimal place, P\lparen X \le4\rparen is 0.8263} \end{gathered}[/tex]The maximum value in this range is: Use the range rule of thumb to determine whether 1 girl in 10 births is a significantly low number of girls.
Answer:
The maximum value in the range is 8.113
1 girl in 10 births is a significantly low number of girls.
Explanation:
Note that the range rule of thumb says that the range of about 4 times the standard deviation.
We'll use the below formula to determine the standard deviation;
[tex]\begin{gathered} \sigma=\sqrt[]{\lbrack\sum^{}_{}x^2\cdot P(x)\rbrack-\mu^2} \\ \text{where }\mu=\text{ population mean} \end{gathered}[/tex]Let's go ahead and determine the mean as seen below;
[tex]\mu=\sum ^{}_{}\lbrack x\cdot P(x)\rbrack[/tex][tex]\begin{gathered} \mu=(0\cdot0.005)+(1\cdot0.12)+(2\cdot0.039)+(3\cdot0.113)+(4\cdot0.196)+(5\cdot0.235)+(6\cdot0.209) \\ +(7\cdot0.113)+(8\cdot0.036)+(9\cdot0.016)+(10\cdot0.026) \end{gathered}[/tex][tex]\begin{gathered} \mu=0.12+0.078+0.339+0.784+1.175+1.254+0.791+0.288+0.144+0.26 \\ \mu=5.233 \end{gathered}[/tex]Let's now determine the below;
[tex]\begin{gathered} \sum ^{}_{}x^2\cdot P(x)=(0^2\cdot0.005)+(1^2\cdot0.12)+(2^2\cdot0.039)+(3^2\cdot0.113)+(4^2\cdot0.196)+(5^2\cdot0.235) \\ +(6^2\cdot0.209)+(7^2\cdot0.113)+(8^2\cdot0.036)+(9^2\cdot0.016)+(10^2\cdot0.026) \end{gathered}[/tex][tex]\begin{gathered} \sum ^{}_{}x^2\cdot P(x)=0.012+0.156+1.017+3.136+5.875+7.524+5.537+2.304+1.296+2.6 \\ =29.457 \end{gathered}[/tex]So the standard deviation will be;
[tex]\sigma=\sqrt[]{29.457-5.233^2}=\sqrt[]{29.457-27.384}=\sqrt[]{2.073}=1.44[/tex]Let's determine the maximum and minimum value of the distribution as seen below;
[tex]\begin{gathered} Maximum\text{ value = }\mu+2\sigma=5.233+2(1.44)=5.233+2.88=8.113 \\ \text{Minimum value }=\mu-2\sigma=5.233-2(1.44)=5.233-2.88=2.353 \end{gathered}[/tex]We can see from the above that the number of girls born among 10 children should be between the range of 2.353 and 8.113, therefore 1 girl in 10 births is a significantly low number of girls.
The maximum value in this range is 8.113
factorize 5m^3-10m^2+8m+2
The expression 5m³ - 10m² + 8m + 2 cannot be factorized
How to factorize the polynomial?From the question, the polynomial is given as
5m^3-10m^2+8m+2
Rewrite the polynomial properly
So, we have
5m³ - 10m² + 8m + 2
Next, we represent the above expression on a graph
From the attached graph, we can see that the polynomial expression only cross the x-axis at x = -0.197
This implies that the expression cannot be factored
So, we cannot further rewrite the given expression
Read more about factorized expressions at
https://brainly.com/question/2750166
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What is the volume of this cube? 2 cm 2cm 2cm
Answer:
The volume is
[tex]8\operatorname{cm}^3[/tex]Explanation:
The volume of a cube with length l is given by the formula:
[tex]V=l^3[/tex]Given the length 2 cm
The volume is:
[tex]V=2^3=8\operatorname{cm}^3[/tex]A county is planning to expand its train service. To better understand the current service, the county planner looked at which train stations are along or not along various train lines
Solution
(a)
5 stations are along the orange line
(b)
8 stations
Is 128 degrees plus 62 degrees supplementary or complimentary?
Let's begin by identifying key information given to us:
One angle = 128 degrees, Second angle = 62 degrees
Complementary angle are angles that sum up to 90 degrees
Supplementary angles are angles that sum up to 180 degrees
We will proceed to sum these two angles together. We have:
[tex]\begin{gathered} 128^{\circ}+62^{\circ}=180^{\circ} \\ \therefore These\text{ angles are supplementary angles since they sum up to 180 degr}ees \end{gathered}[/tex]Therefore, these angles are supplementary angles since they sum up to 180 degrees
The number of fish in a fish tank doubles each week. The function y=equals 3 (2)^x represents the population, where X is the number of one week periodsa. Describe the domains and range of the function. Then graph the functionb. Find and interpret the y intercept c. How many fish are in the tank at the end of first week?d. How many fish are in the tank after 4 weeks?
a. The domain of the function is the set of values of the independent variable (x) on which the function acts, in this case, the independent variable is time, since the time can only take positive values, the domain would be [0,∞) or x≥0.
The range is all the possible values that the dependent variable can take, in this case, the dependent variable is the population of fish, then it can't be a negative number, since you can't have for example -1 fish, then, again, the interval would be [0,∞) or y≥0
A graph of the function looks like this:
b. We can find the y-intercept by making x equals 0 in the formula of the function, like this:
y= 3*(2)^x
y= 3*(2)^0
y= 3*1, since any number raised to zero equals 1
y=3
Since x equals zero represents the initial time, the y-intercept represents the initial population of fish, then at the beginning, there were 3 fish.
c. We just have to replace 1 for x, and then calculate y, like this:
y= 3*(2)^x
y= 3*(2)^1
y= 3*(2)
y=6
At the end of the first week, there will be 6 fish.
d. Now, we just have to replace 4 for x, like this:
y= 3*(2)^4
y= 3*16
y=48
Then, after 4 weeks, there will be 48 fish
Hi how are you today can you please help me with this question
$ 119.607
Explanation
we can easily solve this by using a rule of three
Step 1
Let
actual price(2020)=price of 2019 + 2%
so
actual price(2020)= 102 % and
price ( 2019)=100 %
let x represents the cost for 2019, so
[tex]\begin{gathered} \text{if} \\ 122\Rightarrow\text{ 102\%} \\ x\text{ }\Rightarrow\text{ 100 \%} \end{gathered}[/tex]the proportion would be
[tex]\begin{gathered} \frac{122}{102\text{ \%}}=\frac{x}{100\text{ \% }} \\ \text{ Multiply both sides by 100 \%} \\ \frac{122}{102\text{ \%}}\cdot100=\frac{x}{100\text{ \% }}\cdot100 \\ 119.607=x \end{gathered}[/tex]therefore, the cost in January of 2019 is
$ 119.607
I hope this helps you
he following list contains the average annual total returns (in percentage points) for 9 mutual funds. The mutual funds appear in an online brokerage firm'sall-star" list.-9, 23, 12, 4, 11, 5, 36, 7, 31Send data to calculator(a) What is the mean of this data set? If your answer is not aninteger, round your answer to one decimal place.(b) What is the median of this data set? If your answer is notan integer, round your answer to one decimal place.(c) How many modes does the data set have, and what aretheir values? Indicate the number of modes by clicking in theappropriate circle, and then indicate the value(s) of themode(s), if applicable.00zero modesone mode:two modes: andX
Given
average annual total returns for 9 mutual funds.
-9, 23, 12, 4, 11, 5, 36, 7, 31
Find
a) Mean
b) Median
c) Mode
Explanation
a) Mean = sum of observations/ total number of observation
so ,
[tex]\begin{gathered} mean=\frac{-9+23+12+4+11+5+36+7+31}{9} \\ \\ mean=\frac{120}{9} \\ \\ mean=13.33333\approx13.3 \end{gathered}[/tex]to find median , we need to arrange in ascending order :
-9 , 4 , 5 , 7 , 11 , 12 , 23 , 31 , 37
there are 9 entries which is an odd number
so , median = (n+1/2)th term
[tex]\begin{gathered} \frac{9+1}{2} \\ \frac{10th}{2} \\ 5th \end{gathered}[/tex]so , median = 11
there is no mode because no term is repeating.
Final Answer
Hence ,
mean = 13.3
median = 11
mode - zero mode
units givenQuestion 2 (3 points)toUsing the Rectangular Prism in the picture, find the Lateral Area, the Area of a Single Base,and the TOTAL Surface Area:.12 cm825 cm10 cmUse the face with dimensions 10cm x 5cm as the base.Lateral Area =cm²Single Base Area =64188 in48cm²
Solution:
Given the rectangular prism;
Where;
[tex]\begin{gathered} length,l=10cm \\ \\ width,w=5cm \\ \\ height,h=2cm \end{gathered}[/tex]Thus, the lateral area, L is;
[tex]\begin{gathered} L=2(l+w)h \\ \\ L=2(10+5)2 \\ \\ L=4(15) \\ \\ L=60cm^2 \end{gathered}[/tex]ANSWER:
[tex]Lateral\text{ }Area=60cm^2[/tex]Also, the single base area, B, is;
[tex]\begin{gathered} B=l\times w \\ \\ B=10\times5 \\ \\ B=50cm^2 \end{gathered}[/tex]ANSWER:
[tex]Single\text{ }Base\text{ }Area=50cm^2[/tex]Then, the surface area, S, is;
[tex]\begin{gathered} S=L+2B \\ \\ S=60+2(50) \\ \\ S=60+100 \\ \\ S=160cm^2 \\ \\ \end{gathered}[/tex]ANSWER:
[tex]Surface\text{ }Area=160cm^2[/tex]A pyramid has a square base with sides of length s. The height of the pyramid is equal to of the length of a side on the base. Which formularepresents the volume of the pyramid?OA. V = ¹8³OB. V=¹8³OC. V=8³OD. V=35³OE V=65³
Given,
The measure of the length of the side of square is s.
The height of the pyramid is 1/2 of the length of the side.
Required
The volume of the square pyramid.
The formula for the volume of the square pyramid is,
[tex]Volume\text{ =}\frac{side\times side\times height}{3}[/tex]Substituting the values then,
[tex]\begin{gathered} Volume\text{ =}\frac{s\times s\times s}{3\times2} \\ =\frac{s^3}{6} \end{gathered}[/tex]Hence, the volume of the pyramid is s^3/6.
if there are 36 successful outcomes in a sample size of 80 what is the sample proportion
The sample proportion is the number of successes over the sample size. That is:
36/80 = 9/20
Garrick gets paid $4.70 an hour with time-and-a-half for overtime(over 40 hours). How much did he earn one week when he worked 46hours?a. $195.05b. $220.90c. $230.30d. $188
Solution
For this case we can calculate the total with the following formula:
Fixed amount= 40*4$.70= $188
And now for the remain hours we can do this:
Extra = 6* 1.5*$4.70= $42.3
Then the total amount is:
Fixed amount+ Extra = 188$ + 42.3$ = $230.3
Then the answer is:
c. $230.30
find the surface area of a composite figure round to the nearest tenth if necessary to units
The composite image is that of a cuboid and a triangular prism
For the cuboid, the surface area will be
A = LB + 2BH + 2LH
L = 1.8
B= 1.1
H= 0.8
A = 1.8X1.1 + 2 X 1.1 X 0.8 + 2 X 1.8 X 0.8
A = 1.98 + 1.76 +2.88
Area of cuboid = 6.62
C Campus StudentCampus StudentGA-051 st AFJROTCGA-051 st AFJROTC5 New Tabebra_TC_Online LearningSubtracting with a Model3Subtract: 95 - 43Click or tap blocks to subtract them.032O 42O 52O 62
95 - 43= 52
9 5
- 4 3
______
5 2
____________
5-3 =2
9-4 = 5
______________
Answer
The third choice, 52
2500/10.5 please show work
The given expression is
2500/10.5
We would multiply the numerator and denominator by 10. We have
2500 x 10/10.5 x 10
= 25000/105
We would divide the numerator and denominator by common factors until they can't be simplified further. Dividing by 5, we have
5000/21
It can't be simplified further since there is no common factor of 5000 and 21. We would convert the fraction to mixed fraction
5000/21 = 238 remainder 2
Thus, if we write it as mixed fraction, we have
238 2/21
2 multiplied by the square root of 8
Note that the square root of 8 is written as:
[tex]\sqrt[]{8}[/tex]2 multiplied by the square root of 8 will then be expressed as:
[tex]\begin{gathered} 2\sqrt[]{8} \\ 2\text{ }\times\sqrt[]{8} \\ 2\text{ }\times\text{ }\sqrt[]{4}\text{ }\times\text{ }\sqrt[]{2} \\ 2\text{ }\times\text{ 2 }\times\text{ }\sqrt[]{2} \\ 4\text{ }\times\text{ }\sqrt[]{2} \\ 4\sqrt[]{2} \end{gathered}[/tex]Which of the following is equivalent to a rhombus? *O A rectangle with congruent diagonalsA parallelogram where opposite angles are congruentA parallelogram with two consecutive congruent sidesA quadrilateral where consecutive angles are supplementary
A parallelogram with two consecutive congruent sides.
1) Since a rhombus is a quadrilateral with 4 congruent sides. Then we can examine the options and state that
2) Given that a rhombus has congruent opposite angles, with four congruent sides.
3) The answer is
A parallelogram with two consecutive congruent sides.
With two consecutive sides, the whole polygon will have congruent sides.
The textbook isn't helping with the screenshot problem below.
From the frequency distribution, the measures are given as follows:
a) Total number of observations: 27.
b) The width of each class is of 5.
c) The midpoint of the second class if of 20.5.
d) The modal class is Class 12 - 17.
e) If another class was added, the limits would be 48 - 53.
What is represented by the frequency distribution?The frequency distribution gives the number of observations that is located in each class.
Hence the total number of observations is given by the sum of the frequencies, as follows:
Total = 9 + 1 + 3 + 8 + 6 = 27.
The modal class is class with the highest number of observations, hence it is of:
Class 12-17.
The width of a class is given by the subtraction of the limits, hence:
Width = 47 - 42 = ... = 23 - 18 = 17 - 12 = 5.
For an added class, the lower bound would be one more than the last class, while the upper bound would be five added to the lower bound, hence the limits are:
48 - 53.
The midpoint of each class is given by the mean of the coordinates, hence, for the second class, it is of:
Midpoint = (18 + 23)/2 = 41/2 = 20.5.
More can be learned about frequency distributions at https://brainly.com/question/24623209
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I need help with this question please1) Picture2) In(2x) + ln(7) = 4
1) We must solve for x the following equation:
[tex]e^{5x}=25.[/tex]To solve this equation, we take the natural logarithm to both sides of the equation:
[tex]\begin{gathered} \ln (e^{5x})=\ln (25), \\ 5x\cdot\ln e=\ln 25. \end{gathered}[/tex]Now, we use the following results:
[tex]\begin{gathered} \ln e=1, \\ \ln (25)=\ln (5^2)=2\cdot\ln 5. \end{gathered}[/tex]Replacing these results in the equation above, we have:
[tex]5x=2\cdot\ln 5.[/tex]Solving for x, we get:
[tex]x=\frac{2}{5}\cdot\ln 5\cong0.64.[/tex]2) We must solve for x the following equation:
[tex]\ln (2x)+\ln (7)=4.[/tex]To solve this problem, we isolate the part that involves the x:
[tex]\ln (2x)=4-\ln (7)\text{.}[/tex]Now, using the following property:
[tex]\ln y=z\rightarrow y=e^z\text{.}[/tex]with:
[tex]\begin{gathered} y=2x, \\ z=4-\ln 7. \end{gathered}[/tex]we have:
[tex]\ln (2x)=4-\ln 7\rightarrow2x=e^{4-\ln 7}.[/tex]Solving the last equation for x, we get:
[tex]x=\frac{1}{2}\cdot e^{4-\ln 7}\cong3.90.[/tex]Answers
1) The value of x that solves the first equation is 0.64 to two decimal places.
2) The value of x that solves the second equation is 3.90 to two decimal places.
Review of the base of a logarithm
We can define the logarithm in base a through the following equations:
[tex]\begin{gathered} \log _aa=1, \\ \log _aa^x=x\cdot\log _aa=x\cdot1=x\text{.} \end{gathered}[/tex]When we use as a base the Euler number e ≅ 2.718, the logarithm is called "natural" and we use the following notation for it:
[tex]_{}\log _e=\ln .[/tex]With this notation, we have the following properties:
[tex]\begin{gathered} \ln e=1, \\ \ln e^x=x\cdot\ln e=x\cdot1=x\text{.} \end{gathered}[/tex]In 2010, the population of a city was 170,000. From 2010 to 2015, the population grew by 4.5%. From 2015 to 2020, it fell by 3.3%. To the nearest 100 people, what was the population in 2020?
Given a percentage of change we can calculate the final population by the end of a period with the following formula:
P = P0 + xP0
Where P is the final population, P0 is the initial population at the beginning of the period and x is the percentage of change, if the population grew x will be a positive value and if the population fell x will be a negative value.
For the period 2010 to 2015, the population was initially 170,000 and it grew by a 4.5%. Then by replacing 0.045 for x (4.5/100) and 170000 for P0, we get:
P2015 = 170000 + 0.045×170000 = 177650
From 2015 the population decay by 3.3%, then we can calculate the population by 2020 to get:
P2020 = 177650 + 177650×(-0.033) = 171787
Then, rounding to the nearest 100 people we get 171,800
21. The table below shows the frequency of chirps for the striped ground cricket compared to the ambient temperature, in degrees Fahrenheit.Chirps per SecondTemperature208916722093188417811675157017821569Draw a scatterplot for this data, using x to represent the chirping frequency and y to represent temperature.131415161718192021226768697071727374757677787980818283848586878889909192939495
Using a graphing calculator :
The scatter plot will look thus: