Answer:
m = 98
Step-by-step explanation:
9m/9 - 3 = 95
9m/9 = 95 + 3
9m/9 = 98
cross-multiply
9m = 98 × 9
9m = 882
Divide both sides by 9
m = 98
For how many books produced will the costs from the two methods be the same
Answer:
[tex]4780\text{ books}[/tex]Explanation:
Here, we want to get the number of books for which the cost of the two methods will be the same
What we have to do here is to get the cost of each method, then equate to find the number of books
Let the number of books be b
For the first method, we have it that:
[tex]\begin{gathered} 70976\text{ + }9.75(b) \\ =\text{ 70976 + 9.75b} \end{gathered}[/tex]For the second method, we have it that:
[tex]\begin{gathered} 16006\text{ + }21.25(b) \\ =\text{ 16006 + 21.25b} \end{gathered}[/tex]To get the number of books, we have to equate both
Mathematically, that would be:
[tex]\begin{gathered} 70976\text{ + 9.75b = 16006 + 21.25b} \\ 70976-16006\text{ = 21.25b-9.75b} \\ 54970\text{ = 11.5b} \\ b\text{ = }\frac{54970}{11.5} \\ b\text{ = 4,780} \end{gathered}[/tex]The volume of dis rectangular prism is zero. Seven to a cubic yards. What is the value of C in yards?
To get the volume of a prims, we do the products of the base times its height.
Being a rectangular prims, the area of its base is the product of its dimesions, so the volume of a rectangular prism is simply the product of its three dimensions:
[tex]V=l\cdot w\cdot h=1.3\cdot1.4\cdot c=1.82c[/tex]Since the volume is equal to 0.728 yd³, we have:
[tex]\begin{gathered} 0.728=1.82c \\ c=\frac{0.728}{1.82}=0.4 \end{gathered}[/tex]So, the measure of c is 0.4 yards.
-9 is to the _____ of -3 on a number line so -9 is _____ than -3.right left more less
Answer:
-9 is to the left of -3
-9 is less than -3
Explanation:
If we're to write -9 and -3 on a number line from right to left, we'll see that -3 is going to come before -9, which means that -9 is to the left of -3.
On a number line, any number to the left of another number is less than the other number.
Since -9 is to the left of -3, so -9 is less than -3
Question
Hong hikes at least 1 hour but not more than 4 hours. She hikes at an average rate of 2.7 mph. The function f(t)=2.7t represents the distance she hikes in t hours.
What is the practical range of the function?
Responses
all real numbers from 1 to 4, inclusive
all multiples of 2.7 between 2.7 and 10.8, inclusive
all real numbers
all real numbers from 2.7 to 10.8, inclusive
The practical range of the function is D. all real numbers from 2.7 to 10.8, inclusive.
What is a range?A function's range refers to all of the possible values for y. The formula for determining a function's range is y = f. (x). A function's range is the set of all its outputs. After we have substituted the domain, the range of a function is the complete set of all possible resulting values of the dependent variable (y, usually).
In this case, since the range is the value that satisfies the given function. For function f(t) = 2.7t the practical range of the function can be solved by substituting the lowest time and the highest possible time which are 1 and 4.
At t = 1 f(t) = 2.7 and at t = 4 f(t) = 10.8. so the range is all real numbers from 2.7 to 10.8, inclusive.
Therefore, the correct option is D.
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Kelly and nadir both had maths tests last week, Kelly scored 47/68 and nadir scored 35/52. Who got the higher percentage score
Answer:
Kelly got a higher percentage score.
Step-by-step explanation:
35 / 52 = 0.673
47 / 68 = 0.691
12)50 students took a quiz with five questions. The frequency table below shows the results of the quiz. Use the frequency table to answer the following questions. ValueFrequencyRelative FrequencyCumulative Frequency040.084180.1612260.1218320.04204150.3355150.350
e) Finding how many students answered at most 4 questions.
The number of students that answered at most 4 questions correctly is:
Students answered 0 questions correctly + Students answered 1 question correctly + Students answered 2 questions correctly + Students answered 3 questions correctly + Students answered 4 questions correctly
So, the number of students is:
4 + 8 + 6 + 2 + 15 = 35
35 students answered at most 4 questions correctly.
f) Finding the sum of relative frequency.
The sum of relative frequency is:
0.08 + 0.16 + 0.12 + 0.04 + 0.3 + 0.3
Sum = 1.
The sum of the relative frequency in a distribution is always 1.
g) Creating a histrogram
To create a histogram, create a bar for each result correct. The values of the frequency will be used in the y-axis.
Determine the interest rate capitalized once in a year which can triple any amount in 6 years
ANSWER
interest rate = 20%
EXPLANATION
let P = x, A = 3x, t = 6 and R = ?
[tex]A\text{ = P}\ast(1+R)^t[/tex][tex]\begin{gathered} 3x=x(1+R)^6 \\ 3=(1+R)^6 \\ 1+R=3^{\frac{1}{6}} \\ 1+R\text{ = 1.2} \\ R\text{ = 1.2 - 1} \\ R\text{ = 0.2} \\ R\text{ = 20\%} \end{gathered}[/tex]Use the drawing tools to form the correct answer on the graph.Graph the composite function &(/(e)¡(=)-2I• 5g(I) =1 - 1
Solution:
Given:
The functions are given below as
[tex]\begin{gathered} f(x)=-2x-5 \\ g(x)=x-1 \end{gathered}[/tex]To find:
[tex]g(f(x)[/tex]To figure out the value of the composite function, we will replace x with (-2x-5) in g(x)
[tex]\begin{gathered} g(f(x))=-2x-5-1 \\ g(f(x))=-2x-6 \end{gathered}[/tex]Hence,
Using a graphing tool, we will have the composite function be
what is 6 exponent 7 * 4 exponent 4 * 2 / 6 exponent 5 * 4 exponent 4 * 2.2
given
[tex]\frac{6^7\cdot4^4\cdot2}{6^5\cdot4^4\cdot2^2}[/tex][tex]=6^{7-5}\cdot4^{4-4}\cdot2^{1-2}=6^2\cdot4^0\cdot2^{-1}=\frac{6^2\cdot1}{2}=\frac{36}{2}=18[/tex]Note 4 exponent 0 = 1
jessica needs to bake 50 muffins her baking pan holds 12 muffins how many rounds of baking will she need to do
Let x be the number of rounds of baking. Jessica's baking pan holds 12 muffins. Total 50 muffins is to be made. Hence, we can write,
[tex]\begin{gathered} 12x=50 \\ x=\frac{50}{12}=\frac{25}{6}=4\frac{1}{6} \end{gathered}[/tex]So, we obtained that x is equal to 4 1/6. The number of rounds cannot be a fraction. Here, the number of rounds is equal to the sum of 4 and a fraction 1/6. So, we can say that 5 rounds is needed to make 50 muffins.
Simplify a^6 and a^2A: 2a^12B: 2a^8C: a^12 D: a^8
Using the following property:
[tex]x^y\cdot x^z=x^{y+z}[/tex]so:
[tex]a^6\cdot a^2=a^{6+2}=a^8[/tex]Answer:
a⁸
1. On a number line, graph the solution to the inequality -5(x + 1) > 7x +31? Also, write thesolution in interval notation.
We have the following:
[tex]\begin{gathered} -5\cdot\left(x+1\right)>7x+31 \\ -5x-5>7x+31 \\ -5x-5+5>7x+31+5 \\ -5x-7x>7x+36-7x \\ -12x>36 \\ x>\frac{36}{-12} \\ x<-3 \end{gathered}[/tex]interval notation:
[tex](-\infty,-3)[/tex]graph:
Lana owns an office supply shop. At the beginning of each school year, she chooses two or three products to donate to the local middle school.
The table shows the school supplies that Lana has in her shop and how many of each kind she has in stock. Lana is considering different options of supplies to donate. For each option, determine the greatest number of identical boxes she could pack and the number of each supply item she could put in the boxes.
school supplies stock:
pencils-78
markers-110
notebooks-195
erasers-143
folders-330
A option 1: pencils and erasers: ____boxes with ____ pencils and ____ erasers
B option 2: notebooks and folders: ____ boxes with ____notebooks and ____ folders in each box.
C option 3: erasers, markers, and folders: ____ boxes with ____ erasers ____ markers and ____ folders in each box.
Option-1: 221 boxes with 78 pencils and 143 erasers.
Option-2: 525 boxes with 195 notebooks and 330 folders in each box.
Option-3: 583 boxes with 143 erasers 110 markers and 330 folders in each box.
Given that,
Owning an office supplies store is Lana. Each school year, she selects two or three items to give to the neighborhood middle school.
We have to find the correct answer for the given options.
The table is
school supplies stock:
pencils-78
markers-110
notebooks-195
erasers-143
folders-330
Option1:
Pencils and erases:
78+143=221
221 boxes with 78 pencils and 143 erasers.
Option 2:
Notebooks and folders:
195+330=525
525 boxes with 195 notebooks and 330 folders in each box.
Option 3:
Erasers, markers, and folders:
143+110+330= 583
583 boxes with 143 erasers 110 markers and 330 folders in each box.
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An electronics store purchases laptops for $425.00. They use a markup rate of 60%. How much do they sell the laptop to their customers?
Given that An electronics store purchases laptops for $425.00.
markup rate of 60%.
Selling price is:
[tex]\begin{gathered} SP=425+(0.60)425 \\ Sp=425+255 \\ SP=680 \end{gathered}[/tex]they sell the laptop to their customers at $680.
How do u figure out what x is in a normal distribution question
Data:
• Mean (μ) = 50
,• Standard deviation (σ) = 3
,• P( ,x >=47 ,)
Procedure:
1. Since μ = 50 and σ = 3:
[tex]P(x\le47)=P(X-\mu<47-50)=P(\frac{x-\mu}{\sigma}<\frac{47-50}{3})[/tex][tex]Z=\frac{x-\mu}{\sigma}[/tex][tex]\frac{47-50}{3}=-1[/tex]2. Replacing the values:
[tex]P(x\le47)=P(Z\le-1)[/tex]With this, we do not have to figure out what x is.
3. Using the standard normal table:
[tex]P(Z\le-1)=0.1587\approx0.16[/tex]Answer: A. 0.16
1,1,2,6,24,_,_,_,_A) explain and complete the sequenceB) write an explicit and recursive formula for the sequence
As you can notice, this sequence is detailed as follows:
[tex]\begin{gathered} 1\cdot1=1 \\ 1\cdot2=2 \\ 2\cdot3=6 \\ 6\cdot4=24 \end{gathered}[/tex]Now, let's find the next four terms:
[tex]\begin{gathered} 24\cdot5=120 \\ 120\cdot6=720 \\ 720\cdot7=5040 \\ 5040\cdot8=40320 \end{gathered}[/tex]A possible formula could be:
[tex]a_n=n\cdot a_{n-1}[/tex]Where "n" is the number of the term given and it starts from 1. (a0 is 1) This is:
[tex]\begin{gathered} a_1=1.a_{1-1}=1\cdot a_0=1_{} \\ a_2=2\cdot a_{2-1}=2\cdot a_1=2 \\ a_3=3\cdot a_{3-1}=3\cdot a_2=6 \\ \text{and so on } \end{gathered}[/tex]The tables of ordered pairs represent some points on the graphs of Lines F and G.
Line F
x y
2 7
4 10.5
7 15.75
11 22.75
Line G
x y
-3 4
-2 0
1 -12
4 -24
Which system of equations represents Lines F and G?
1. y=1.75x+3.5
y=-4x-8
2. same as 1 but -8 is -2
3. 1.75 and 3.5 are switched
4. 2 and 3 combined
In linear equation, Equation for line F is y = 1.75x + 3.5 and equation for line G is y = -4x-8.
What is a linear equation example?
Ax+By=C is the typical form for linear equations involving two variables. A linear equation in standard form is, for instance, 2x+3y=5.Finding both intercepts of an equation in this format is rather simple (x and y).y = 1.75x + 3.5 (For line F)
let's take the point (2,7) and put in the equation,
y = 1.75*2 + 3.5
= 3.5 +0.35
= 7
which is true.
Hence, (2,7) satisfies the equation.
y = -4x-8 (For line G)
lets take the point (-3,4) and put in the equation,
y = (-4)*(3) - 8
= 12 - 8
= 4
which is true.
Hence, (-3,4) satisfies the equation.
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Do You Know How? In 3-8, estimate each product using rounding or compatible numbers. 4. 104 x 0.33 3. 0.87 x 112 0.90x110=99 6. 0.54 x 24 5. 9.02 x 80 9x80=720 7. 33.05 x 200 a. 0,79 x 51
Estimating Products
Some operations can be estimated and its results approximated by using rounding and number that are easier to calculate.
For example the product 0.87*112 can be estimated by using 0.9 (a very close rounded number) and 110 instead of 112. One of the factors was rounded up and the other was rounded down. The product should be very close to the real exact product.
Now for 104*0.33. 104 can be rounded to 100 and it can be easily multiplied by 0.33. 100*0.33 = 33
0.54*24 can be estimated as 0.5*26=13 or as 0.6*30=18
33.05*200 is approximated as 33*200 = 6600
0.79*51 is estimated as 0.8*50 = 400
Some of the estimations above can be challenged and some people can propose better combinations for more accurate results. It's a subjective task.
If Guillermo deposits $5000 into an account paying 6% annual interest compounded monthly, how long until there is $8000 in the account?
We have the following:
The formula in this case is the following:
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]solving for t:
replacing
A is 8000, P is 5000, n is 12 and r is 6% (0.06)
[tex]\begin{gathered} 8000=5000(1+\frac{0.06}{12})^{12t} \\ \frac{8000}{5000}=1.005^{12t} \\ \ln (\frac{8}{5})=12\cdot t\ln (1.005)_{} \\ t=\frac{\ln (\frac{8}{5})}{12\ln (1.005)} \\ t=7.85 \end{gathered}[/tex]therefore, the answer is 7.9 years
Please solve the problem in the attachment and provide the steps, the reason why your answer is correct and why all the other answer choices are incorrect.
Answer:
A
[tex]A\text{. Rectangles also have four right angles}[/tex]Explanation:
We want to find a counterexample to disprove the conjecture below;
- A square is a figure with four right angles.
To disprove this, we need to find a shape that also has four right angles but is not a square.
So, from the option the only shape that also has four right angles is a rectangle.
Therefore, the counterexample to disprove the conjecture is;
[tex]A\text{. Rectangles also have four right angles}[/tex]V8 Splash $2.28 64 oz Walmart 0.04 cents per ozV8 Splash $ 2.49 64 oz Kroger 3.89 cents per ozWhich is the better deal?
Given:
V8 Splash $2.28 64 oz Walmart 0.04 cents per oz
V8 Splash $ 2.49 64 oz Kroger 3.89 cents per oz.
Best deal is
V8 Splash $2.28 64 oz Walmart 0.04 cents per oz
REWRITE EACH PROBLEM AS A MULTIPLICATION QUESTION!!!Students were surveyed about their favorite colors. 1/4 of the students preffered red, 1/8 of the students blue, and 3/5 of the remaining students preffered green. If 15 students preffered green, how many student were surveyed?
Let there are x total student surveyed, the 1/4x students prefer red, 1/8x prefer blue.
Determine the remaining students.
[tex]\begin{gathered} S=x-\frac{x}{4}-\frac{x}{8} \\ =\frac{8x-2x-x}{8} \\ =\frac{5}{8}x \end{gathered}[/tex]Determine the students that prefer green.
[tex]\frac{3}{5}\cdot\frac{5}{8}x=\frac{3x}{8}[/tex]The students who preferred green is 15. So equation for x is,
[tex]\begin{gathered} \frac{3x}{8}=15 \\ x=\frac{15\cdot8}{3} \\ =40 \end{gathered}[/tex]So total students that were surveyed is equal to 40.
.converge or diverge? If it converges, to what value does it converge?
Given the series;
[tex]\sum ^{\infty}_{n\mathop=0}3(\frac{1}{5})^{n-1}[/tex]To obtain the sum of the series above and decide if it converges or diverges, we will
[tex]\begin{gathered} \sum ^{\infty}_{n\mathop{=}0}3(\frac{1}{5})^{n-1}=\sum ^{\infty}_{n\mathop{=}0}3(5)^{-(n-1)} \\ =\sum ^{\infty}_{n\mathop{=}0}3(5)^{(1-n)} \\ =\sum ^{\infty}_{n\mathop{=}0}15\times5^{-n} \\ =15\sum ^{\infty}_{n\mathop{=}0}(\frac{1}{5})^n \end{gathered}[/tex]Simplify the resulting geometric series and decide if it converge or diverge
[tex]\sum ^{\infty}_{n\mathop{=}0}(\frac{1}{5})^n\Rightarrow is\text{ an infinite geometric series, with first term a= 1 and common ratio r=}\frac{1}{5}[/tex]Solve for the sum to infinity of the geometric series
[tex]S_{\infty}=\frac{a}{1-r}=\frac{1}{1-\frac{1}{5}}=\frac{1}{\frac{4}{5}}=\frac{5}{4}[/tex]The sum of the series wil be
[tex]15\sum ^{\infty}_{n\mathop{=}0}(\frac{1}{5})^n\Rightarrow15\times\frac{5}{4}=\frac{75}{4}[/tex]Hence,
[tex]\begin{gathered} \sum ^{\infty}_{n\mathop{=}0}3(\frac{1}{5})^{n-1}=\frac{75}{4} \\ \text{The series converges} \end{gathered}[/tex]The table below shows the probability distribution of a random variable X Х P(X) -10 0.07 -9 0.09 -8 0.67 -7 0 -6 0.17 What is the expected value of X? Write your answer as a decimal.
Teshawn, this is the solution to the problem:
We use the following formula to calculate the expected value of x, as follows:
Expected value of x = -10 * 0.07 + - 9 * 0.09 + -8 * 0.67 + -7 * 0 + -6 * 0.17
Expected value of x = -0.7 + -0.81 + - 5.36 + 0 + - 1.02
Expected value of x = -0.7 - 0.81 - 5.36 - 1.02
Expected value of x = -7.89
Which expressions are equivalent to the one below? Check all that apply.ln(e5)A.1B.5C.5 • ln eD.5e
SOLUTION:
We want to find the equivalent expression to;
[tex]ln(e^5)[/tex]We can rewrite it as;
[tex]\begin{gathered} 5ln(e) \\ =5 \end{gathered}[/tex]Thus, the answers are;
[tex]5Ine\text{ }and\text{ }5[/tex]OPTION B and C
A car's rear windshield wiper rotates 135°. The total length of the wiper mechanism is 21 inches and the length of the wiper blade is 12 inches. Find the area wiped by the wiper blade. (Round your answer to one decimal place.)
The area wiped by the wiper blade is 424.08 in².
How to find the area?Using this formula to find the area
A= 1/2r² Ф
Where:
A = Area
r = Radius
Let plug in the formula
A = [1/2 × (21)² × 135° ×π /180 ] - [1/2 × (21 -12)² × 135° ×π /180 ]
A = [1/2 × (21)² × 135° ×π /180 ] - [1/2 × (9)² × 135° ×π /180 ]
A = [1/2 × (441) × 135° ×π /180 ] - [1/2 × (81) × 135° ×π /180 ]
A = 519.54 - 95.43
A = 424.08 in²
Therefore the area is 424.08 in².
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The mean height of men is known to 5.9 ft with a standard deviation of 0.2 ft. The height of a man (in ft) corresponding to a z-score of 2 is:Group of answer choices6.16.36.25.9
The average height is μ= 5.9ft and has a standard deviation of σ=0.2ft.
You have to determine the height (X) for the Z-score z=2
To determine this value, you have to use the formula of the standard deviation:
[tex]Z=\frac{X-\mu}{\sigma}[/tex]First, write the equation for X:
-Multiply both sides by sigma:
[tex]\begin{gathered} Z\sigma=\sigma\frac{X-\mu}{\sigma} \\ \\ Z\sigma=X-\mu \end{gathered}[/tex]-Add mu to both sides of it:
[tex]\begin{gathered} (Z\sigma)+\mu=X-\mu+\mu \\ X=(Z\sigma)+\mu \end{gathered}[/tex]Replace the expression obtained for X with the known values of z, sigma, and mu
[tex]\begin{gathered} X=2\cdot0.2+5.9 \\ X=\text{0}.4+5.9 \\ X=6.3 \end{gathered}[/tex]The height of a man that corresponds to z=2 is 6.3 ft
Evaluate the following expression.C(8,3)C=combinations
The formula for combination is
nCr = n!/(n - r)!r!
C represents the number of combinations
n represents the total number of objects to choose from
r represents the number of items selscted from n
From the information given,
n = 8 and r = 3
8C3 = 8!/(8 - 3)!3!
= 8! /5!3!
= 8 * 7 * 6 * 5 * 4 * 3!/5 * 4 * 3 * 2 * 1 * 3!
The 3! cancels out. It becomes
8 * 7 * 6 * 5 * 4 /5 * 4 * 3 * 2 * 1
= 6720/120
= 56
The answer is 56
Find a recursive formula for the following sequence:4, 11, 25, 53, 109, ...
Notice the following pattern in the given sequence:
[tex]\begin{gathered} 11=4\cdot2\text{ +3,} \\ 25=11\cdot2+3, \\ 53=25\cdot2+3, \\ 109=53\cdot2+3. \end{gathered}[/tex]Therefore, the n-term of the sequence has the following form:
[tex]a_n=a_{n-1\text{ }}+3.[/tex]Answer:
[tex]a_n=a_{n-1\text{ }}+3.[/tex]MATH HELP WILL MARK BRAINLEST