16) Select the sequence of transformations that will carry triangle A onto triangle A'Atranslate 6 units down, then reflect acrossA)'the y-axis5B) reflect over the y-axis, reflect over the x-axis,then 2 units upC)reflect over the x-axis, translate 2 units up,then 8 units left-5D)reflect over the x-axis, rotate 90° clockwise,then translate 4 units down

16) Select The Sequence Of Transformations That Will Carry Triangle A Onto Triangle A'Atranslate 6 Units

Answers

Answer 1

C

16) Let's first locate the points that make up the pre-image A, and the image A' picking them from each one of those three vertices.

A

(-3,5)

(-5, 5)

(-5,3)

A'

(5,-1)

(5,-3)

(3,-3)

16.2) Then let's pick just one point and apply the transformations, in this case, let's pick point (-3,5)

Counting on the graph

So if we reflect it over the x-axis, we'll get from (-3,5) to (3,-5) and translating up two units, we'll arrive at (-3,-3) and finally to (5,-3) one of the coordinates of the Image A'

16.3) Hence, the answer is C


Related Questions

Determine which of the value(s), if any, must be excluded from the domain of the variable in the expression x^2/x^2+25Options:x=3,x=5,x=0,x=-5None

Answers

Given:

The expression is,

[tex]\frac{x^2}{x^2+25}[/tex]

The domain of the function is values of independent variable for which expression is defined. Since expression is not defined when,

[tex]x^2+25=0[/tex]

Sinece there is no real value of x for which denominator of expression,

[tex]x^2+25[/tex]

is zero. So domain of the expression is,

[tex](-\infty,\infty)[/tex]

So all values of x is included in the domain of the function. Thus answer is None.

A store had 896 swimsuits that were marked to sell at $40.99. Each suit was marked down $17.90. Find the reduced price using the formula M=S-N, where M is the markdown, S is the original selling price, and N is the reduced price. The reduced price is?

Answers

Let us assumed that each of the swimsuit is marked to sell at $40.99, and each suit was marked down $17.90 (given).

With the given formula below, we solve for the reduced price

[tex]M=S-N[/tex][tex]\begin{gathered} M=\text{ \$17.90(given)} \\ S=\text{ \$40.99(given)} \\ N=\text{reduced price} \end{gathered}[/tex]

Substitute the value of M and S in the given formula to solve for N as shown below:

[tex]\begin{gathered} 17.90=40.99-N \\ 17.90+N=40.99-N+N \\ 17.90+N=40.99 \\ 17.90+N-17.90=40.99-17.90 \\ N=23.09 \end{gathered}[/tex]

Hence, the reduce price is $23.09

What is the M and B forX = 5M=B=

Answers

ANSWER

m = undefined

b = doesn't exist

EXPLANATION

x = 5 is a vertical line where in all points x is 5. Therefore, if we use the formula for the slope:

[tex]m=\frac{y_1-y_2}{x_1-x_2}[/tex]

The denominator will always be 0. Since we can't divide by 0, the slope is undefined.

Since it's a vertical line, there's no y-intercept. This is because the y-intercept is the value of y when x = 0 and in a vertical line x has always the same value: in this case, 5.

Sketch the graph of the equation Y=2x^2-10x+9

Answers

Solution:

The equation is given below as

[tex]y=2x^2-10x+9[/tex]

Step 1:

We will figure out the y-intercept by putting x=0

[tex]\begin{gathered} y=2x^{2}-10x+9 \\ y=2(0)^2-10(0)+9 \\ y=9 \\ (0,9) \end{gathered}[/tex]

Step 2:

Calculate the vertex of the graph using the formula below

[tex]\begin{gathered} y=2x^2-10x+9 \\ x=-\frac{b}{2a},b=-10,a=2,c=9 \\ x=\frac{-(-10)}{2(2)}=\frac{10}{4}=\frac{5}{2} \\ \\ y=2(\frac{5}{2})^2-10(\frac{5}{2})+9 \\ y=2(\frac{25}{4})-25+9 \\ y=\frac{25}{2}-16 \\ y\frac{=25-32}{2} \\ y=-\frac{7}{2} \end{gathered}[/tex]

Hence,

The vertex of the equation is

[tex](\frac{5}{2},-\frac{7}{2})[/tex]

Using a graphing calculator, we will have the graph be

A clothing store is donating socks to various charities. The store gave 6 regular packs and 5 value packs to a homeless shelter, which contained a total of 163 pairs of socks. For foster children, the store donated 6 regular packs and 4 value packs, which equaled 146 pairs. How many pairs of socks are in each pack?

Answers

Let r and v be the number of socks ina regular pack and value pack, respectively. Since the store gave 6 regular packs and 5 value packs which contained 163 pair of socks, we can write

[tex]6r+5v=163[/tex]

Similarly, since the store donated 6 regular packs and 4 value pack which add 146 pair of socks, we can write

[tex]6r+4v=146[/tex]

Then, we have the following system of equations:

[tex]\begin{gathered} 6r+5v=163\ldots(a) \\ 6r+4v=146\ldots(b) \end{gathered}[/tex]

Solving by elimilation method.

By multiplying equation (b) by -1, we have an equivalent system of equations:

[tex]\begin{gathered} 6r+5v=163 \\ -6r-4v=-146 \end{gathered}[/tex]

Then, by adding both equations, we have

[tex]v=17[/tex]

Now, in order to obtain the number of socks in a regular pack, we must substitute the last result into equation (a). It yields,

[tex]6r+5(17)=163[/tex]

which gives

[tex]6r+85=163[/tex]

By subtracting 85 to both sides, we have

[tex]6r=78[/tex]

Then, r is given by

[tex]\begin{gathered} r=\frac{78}{6} \\ r=13 \end{gathered}[/tex]

Therefore, the answer is: There are 13 pairs of socks in each regular pack and 17 pairs in each value pack.

A.bMicah used the wrong sign for b in the formula x = -2aO B. Micah should have evaluated the function with x = 0 to find they-coordinate.O C. Micah did not use the correct order-of-operations dividing 47.5 by21 -9.5)OD. Micah should have found a positive value when he simplified the-9.5(2.5)2 term.The correct vertex is(Type an ordered pair.)

Answers

Answer

- Micah's mistake in calculating the vertex is that he used the wrong sign for b in using (-b/2a) to calculate the x-coordinate of the vertex.

The correct vertex is (-2.5, 122.375).

Explanation

The quadratic equation is

y = -9.5x² - 47.5x + 63

It is evident that Micah's mistake in calculating the vertex is that he used the wrong sign for b in using (-b/2a) to calculate the x-coordinate of the vertex.

To no calculate the correct vertex,

a = -9.5

b = -47.5

c = 63

x = (-b/2a)

[tex]\begin{gathered} x=-\frac{b}{2a} \\ x=-\frac{-47.5}{2\times-9.5} \\ x=-\frac{-47.5}{-19} \\ x=-2.5 \end{gathered}[/tex]

We can hen substitute this for x in the quadratic equation to get the corresponding y-coordinate for the vertex.

y = -9.5x² - 47.5x + 63

y = -9.5(-2.5)² - 47.5(-2.5) + 63

y = -9.5 (6.25) + 118.75 + 63

y = -59.375 + 118.75 + 63

y = 122.375

Hence, the vertex is (-2.5, 122.375)

Hope this Helps!!!

Determine the equation of the line that goes through the point (4, 4) with -1/4 slope. Enter your answer in slope-intercept form.Enter EquationPls see picture

Answers

The equation of a line in the slope intercept form is expressed as

y = mx + c

where

m represents slope

c represents y intercept

From the information given,

m = - 1/4

the line passes through the point (4, 4). This means that

x = 4, y = 4

We would find c by substituting m = - 1/4, x = 4 and y = 4 into the slope intercept equation. We have

4 = - 1/4 * 4 + c

4 = - 1 + c

Adding 1 to both sides of the equation,

4 + 1 = - 1 + 1 + c

c = 5

By substituting m = - 1/4 and c = 5 into the slope intercept equation, the equation of the line is

y = - x/4 + 5

12 Stefanie is painting her bedroom. She can paint 12 1/3 square feet in 1/5 of an hour. How many square feet can she paint in one hour?

Answers

stephanie can paint 12 1/3 square feet in 1/5 of an hour. So,

[tex]undefined[/tex]

Solve fort.-t = 9(t – 10)t=Stuck? Watch a video or us

Answers

We are to solve for t in the equation given

To do this, we have to expand the bracket

Expanding, we have

-t = 9(t-10)

-t = 9t - 90

Collecting the like terms, we have

90 = 9t + t

90 = 10t

Dividing both sides by 10 to get t, we have

[tex]\begin{gathered} t=\frac{90}{10} \\ t=9 \end{gathered}[/tex]

Therefore the value of t is 9.

what value of c would complete the square for the following trinomials?

Answers

[tex]x^2+6x+c\colon[/tex]

To find the value of c that will make the given expression a perfect square, we simply;

Step 1: Take the coefficient of x : that is, 6

Step 2: Divide the coefficient obtained in step 1 by 2: That is, 6/2 = 3

Step 3: Square the result in step 2: That is, 3^2 = 9

Hence, c = 9

The value of c in the first expression is 9.

Second Expression:

[tex]x^2-10x+c[/tex]

Step 1: 10 ( Do not bother yourself with the negative sign, just pick the number 10)

Step 2: 10/2 = 5

Step 3: 5^2 = 25

so, c = 25

Third expression:

[tex]x^2+32x+c[/tex]

Step 1: 32

Step 2: 32/2 = 16

Step 3: 16^2 = 256

So, c = 256

Fourth expression:

[tex]x^2-12x+c[/tex]

Step 1: 12

Step 2: 12/2 = 6

Step 3: 6^2 = 36

So, c = 36

Last expression:

[tex]x^2+8x+c[/tex]

Step 1: 8

Step 2: 8/2 = 4

Step 3: 4^2 = 16

so, c = 16

Jamie cut a rope into thirds.He used two of the pieces to make a swing

Answers

The complete length of the rope would be represented by 1

If he cut the rope into thirds, it means that each length woiuld be 1/3.

Given that he used two of the pieces to make a swing, it means that the length used in making the swing is

1/3 + 1/3 = 2/3

The left over rope is 1/3

Also, he used equal lengths of the left over rope on four picture frames. It means that the length used on each picture frame is

1/3 divided by 4

= 1/3 * 1/4 = 1/12

Thus, the fraction of the original rope that he used for each picture frame is 1/12. Option B is correct

How many ways can we award a 1st, 2nd, and 3rd place prize among eight contestants?

Answers

We have:

- There are 8 choices for awarding first prize.

- Then there are 7 choices for awarding second prize.

- And there are 6 choices for awarding third prize.

Therefore, there are:

[tex]8\cdot7\cdot6=336\text{ ways}[/tex]

Answer: 336 ways

select all of the trips that would take 5 hours 1. Drive 40 miles per hour between Bend and Portland, which are 200 miles apart 2. Take a train going 50 miles per hour from Martinez to Dunsmuir, which are 259 miles apart 3. Walk 4 miles per hour to school, wh6is 1.75 miles apart

Answers

Answer:

1. Yes

2. No

3. No.

Explanation:

The amount of time taken on a trip is equal to the distance travelled divided by the speed.

[tex]\text{time taken = }\frac{dist\text{ travelled }}{\text{speed}}[/tex]

1. The drive from Bend to Portland is 200 miles and the speed is 40 miles per hour; therefore, the time taken is

[tex]\text{time taken = }\frac{200}{40}=5\text{ hours.}[/tex]

2. The drive from Martinez to Dunsmuir is 259 and the speed is 50 miles per hour; therefore, the time taken is

[tex]\text{time taken = }\frac{259\text{ miles}}{50\text{ mile per hour}}\text{ = 5.18 hours}[/tex]

3.

The distance to the school is 1.75 miles and the speed is 4 miles per hour; therefore, the time taken is

[tex]\text{time taken = }\frac{1.75\text{ miles}}{4\text{ miles per hour }}=0.4375\text{ hours. }[/tex]

Hence, the only trip that takes 5 hours is trip 1.

Which tree is growing faster?Tree 2Tree 1 is growing 2 week 2 4 6 8 10inches every week. inches5 10 15 20 25tallHint: First calculate the unit rate for Tree 2.Enter the number that belongs in the numerator.Unit Rate[?]=inches/week

Answers

Calculating the unit rate for Tree 2 we have the following

[tex]\text{Unit Rate }=\frac{5\text{ inches}}{2\text{ week}}\text{ }=\frac{10\text{ inches}}{4\text{ week}}\text{ }=\frac{15\text{ inches}}{6\text{ week}}[/tex]

When simplified the unit rate is

[tex]\frac{5}{2}\text{ inches/week}[/tex]

This is 2.5 inches per week. Compared to Tree 1,

On June 10, Trudy Polanski deposited $1260 in a savings account that pays 5.5% interest compounded daily. How much interest will the money earn in 60 days?

Answers

The answer will be $32,893.43 compound interest will the money earn in 60 days.

What is compound interest?

The interest on savings that is computed on both the initial principal and the interest accrued over time is known as compound interest. Compound interest is computed by multiplying the starting principal amount by one and the annual interest rate raised to the number of compound periods minus one. The final step is to deduct the initial loan principal from the calculated value.

When the amount compounds quarterly, it means that the amount compounds 2 times, n=12. We use this fact to derive the quarterly compound interest formula. Thus, the quarterly compound interest formula is:

A = P (1 + r/12)^12t

A = 1260(1+5.5/12) ^12

A = $32,893.43

Hence the interest will be $32,893.43.

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Complete the following equation. Your answers will be algebraic expressions. (a+bi)^2= _____ + 2abiHint: think of i as an ordinary variable and then replace i^2 with -1.

Answers

The given expression is:

[tex](a+ib)^2[/tex]

Expand to get:

[tex]\begin{gathered} (a+ib)^2=a^2+i^2b^2+2abi \\ =a^2-b^2+2abi \end{gathered}[/tex]

The value is as above since it is given that i^2=-1.

So the expansion is:

[tex](a+ib)^2=a^2-b^2+2abi[/tex]

The blank should be:

[tex]a^2-b^2[/tex]

Filling in Table (decreasing)Dependent QuantityA Helicopter flying at 3509 feet begins its descent. Itdescends at a rate of 41 feet per minuteIndependent Quantity0Complete the missing part of the tables, and make afunction that describes the Helicopter's decent133222Your answer: Not there yet, keep working3140Share with Class

Answers

(0,3509)

(1,3468)

(3,3386)

(7,3222)

(9,3140)

h=3509-41x

Explanation

Step 1

as we can see, the independent quantity is the time , and the dependent quantity is the heigth because it depends on the time.

then when time = o, t=o

[tex]0\Rightarrow3509\text{ ft}[/tex]

after 1 minute the helicopter has descended 41 ft, then

when time = 1, t=1

[tex]\begin{gathered} heigth_1=3509-(1\cdot41) \\ heigth_1=3509-41 \\ heigth_1=3468 \\ (1,3468) \end{gathered}[/tex]

when t=3

[tex]\begin{gathered} heigth_3=3509-(3\cdot41) \\ heigth_3=3509-123 \\ heigth_3=3386 \end{gathered}[/tex]

when heigth=3222

[tex]\begin{gathered} \text{heigth}_x=3509-(x\cdot41) \\ 3222=3509-41x \\ \text{subtract 3509 in both sides} \\ 3222-3509=3509-41x-3509 \\ -287=-41x \\ \text{divide both sides by -41} \\ \frac{-287}{-41}=\frac{-41x}{-41} \\ 7=x \\ \text{hence}(7,3222) \end{gathered}[/tex]

when heigth=3140

[tex]\begin{gathered} \text{heigth}_x=3509-(x\cdot41) \\ \text{3140}=3509-41x \\ subtract\text{ 3509 in both sides} \\ \text{3140-3509}=3509-41x-3509 \\ -369=-41x \\ \text{divide both sides by -41} \\ \frac{-369}{-41}=\frac{-41x}{-41} \\ 9=x \\ x=9,\text{then} \\ (9,3140) \end{gathered}[/tex]

Step 2

now, the equation is

[tex]\begin{gathered} \text{Heigth}=3509-41x \\ h=3509-41x \\ \text{where} \\ h\text{ is the heigth in ft and t is the time in minutes} \end{gathered}[/tex]

I hope this helps you

Find the probability of X less than or equal to 2X 0 1 2 3P(x) 0.12 0.67 0.19 0.020.980.790.020.19

Answers

Step 1:

Probability of x less than or equal to 2.

[tex]\begin{gathered} \text{Probability of x less than or equal to 2 = 0.12 + 0.67 + 0.19} \\ =\text{ 0.98} \end{gathered}[/tex]

Step 2:

Final answer

= 0.98

Simplify.
Radical sign 45x
9

Answers

Answer:

20.12461179

Step-by-step explanation

In the figure below, find each of the following.A right triangle has a vertical side labeled "3.00", a horizontal side labeled "4.00" that goes rightwards from the bottom of the vertical side, and a hypotenuse labeled "5.00" that goes down and right from the top of the vertical side to the right of the horizontal side. The top left interior angle of the triangle is an acute angle and the bottom right interior angle is an acute angle .(a) the length of the side opposite (b) the length of the side adjacent to (c) cos()(d) sin()(e) tan()

Answers

Given

To find:

a) The length of the side opposite

(b) The length of the side adjacent to

(c) cos()

(d) sin()

(e) tan()

Explanation:

It is given that,

That implies,

(a) The length of the side opposite is 3.00.

(b) The length of the side adjacent to is 3.00.

(c) cos()

[tex]\begin{gathered} \cos(\theta)=\frac{adjacen\text{t }side}{hypotenuse} \\ =\frac{4.00}{5.00} \\ =\frac{4}{5} \\ =0.8 \end{gathered}[/tex]

(d) sin()

[tex]\begin{gathered} \sin(\varphi)=\frac{opposite\text{ }side}{hypotenuse} \\ =\frac{4.00}{5.00} \\ =\frac{4}{5} \\ =0.8 \end{gathered}[/tex]

(e) tan()

[tex]\begin{gathered} \tan(\varphi)=\frac{opposite\text{ }side}{adjacent\text{ }side} \\ =\frac{4.00}{3.00} \\ =\frac{4}{3} \\ =1.33 \end{gathered}[/tex]

Name the quadrant in which each of the point lies. (-2,5)

Answers

The quadrants have the following division.

Since the points (-2, 5) is located on the negative side of the x-axis, and in the positive side of the y axis, it belongs to the second quadrant.

The answer is quadrant II

A card is chosen from a standard deck, thena month of the year is chosen. Find theprobability of getting a face card and June. use the counting principle to find each probability

Answers

1) Gathering the data

1 face card out of one deck: 12 /52

1 month of the year: 1/12

2) In Probability, The counting principle says we can multiply two

events

The question, says the probability of getting a face card

We have 12 face cards in a deck so, using the counting principle:

P( face card and June) = 12/52 *1/12 =1/52

how do I find out whether an infinite geometric series converges and how do I find its sum. for example:6+3+3/2+3/4+...

Answers

We are given the following infinite geometric series

[tex]6+3+\frac{3}{2}+\frac{3}{4}+\cdots[/tex]

The general form of an infinite geometric series is given by

[tex]a_1+a_1r+a_1r^2+a_1r^3+\cdots[/tex]

Where a1 is the first term and r is the common ratio.

The first term is equal to 6

The common ratio is the division of any two consecutive numbers in the infinite geometric series.

[tex]\frac{3}{6}=\frac{1}{2}[/tex]

You can also take any other two consecutive numbers in the series and you will get the same common ratio.

[tex]\frac{\frac{3}{2}}{3}=\frac{3}{2}\cdot\frac{1}{3}=\frac{3}{6}=\frac{1}{2}[/tex]

As expected, we still got the same common ratio as before.

How do I find out whether an infinite geometric series converges?

An infinite geometric series converges if the absolute value of the common ratio is less than 1.

[tex]\begin{gathered} |r|<1 \\ \frac{1}{2}<1 \\ 0.5<1 \end{gathered}[/tex]

Since the absolute value of the common ratio is less than 1, the infinite geometric series converges.

How do I find its sum?

The sum of this infinite geometric series is given by

[tex]S=\frac{a_1}{1-r}[/tex]

Substitute the values of first term a1 and common ratio r.

[tex]S=\frac{6}{1-\frac{1}{2}}=\frac{6}{\frac{1}{2}}=6\cdot\frac{2}{1}=12[/tex]

Therefore, the sum of this infinite geometric series is 12.

ARITHMETIC AND ALCEBRA REVIEWWord problem on optimizing an area or perimeter

Answers

region 1 will require the most paint

Explanation:

length of tape = 24 ft

perimeter of the region to be painted = 24 ft

The region is rectangular, so we will apply the area of rectangle and perimeter to find the width.

perimeter = 2(length + width)

Area = length × width

We have 3 different regions with different lengths

For region 1:

length = 6 ft

from the formula for perimter, we can find the width:

perimeter = 2(length + width)

perimeter/2 = length + width

[tex]\text{width = }\frac{perimeter\text{ }}{2}-\text{ length}[/tex]

width for region 1 = 24/2 - 6 = 12 - 6

width = 6

Area = 6 × 6 = 36 ft²

For region 2:

length = 7 ft

width = 24/2 - 7 = 12 - 7

width = 5 ft

Area = 7 × 5 = 35 ft²

For region 3:

length = 8 ft

width = 24/2 - 8 = 12 - 8

width = 4 ft

Area = 8 × 4 = 32 ft²

b) The region that will require the most paint is the one that has the highest area. The higher the area, the larger the amount of paint that will be needed.

From calculations above, the highest area is 36 ft²

Hence, the region that will require the most paint is region 1

InequalitiesEvaluate. Show your work or explain how you arrived at your answer.-|-34|

Answers

The value of -|-34| is -34

-|-34|

Apply absolute rule: |-a|=a,  a>0 =-34

The absolute value (or modulus)| x |  of a real number x is its non-negative value regardless of its sign. For example, 5 has an absolute value of 5, and 5 has an absolute value of 5. A number's absolute value can be conceived of as its distance from zero along the real number line.

Absolute values for real numbers occur in a wide range of mathematical contexts. Absolute values, for example, are defined for complex numbers, quaternions, ordered rings, fields, and vector spaces. In numerous mathematical and physical contexts, the absolute value is intimately related to the concepts of magnitude, distance, and norm.

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Bob grew 1,102 plants with 29 seed packets. With 94 seed packets, how many total plants can Bob have in his backyard? Assume the relationship is directly proportional.

Answers

If the relation between number of plants and the number of seed packets is directly proportional and x is the number of plants can Bob have for 94 seed packets, you can write;

[tex]\frac{x}{94}=\frac{1102}{29}[/tex]

By solving for x in the previous expression and simplifying, you get:

[tex]\begin{gathered} x=\frac{1102}{29}\cdot94 \\ x=3572 \end{gathered}[/tex]

Hence, Bob could have 3572 plants if he uses 29 seed packets.

A rocket is fired from the ground at an angle of 1.12 radians. Suppose the rocket has traveled 440 yards since it was launched. Draw a diagram and label the values that you know.How many yards has the rocket traveled horizontally from where it was launched?____ yards   What is the rocket's height above the ground? ____yards   

Answers

ANSWER

• Horizontal distance it traveled: ,191.7 yards

,

• Height above ground: ,396 yards

EXPLANATION

Diagram:

The height, the horizontal distance and the distance traveled form a right triangle.

Since we know the angle, we can find both x and y. The distance traveled is the hypotenuse of the triangle, y is the opposite side to the known angle and x is the adjacent side:

[tex]\sin (1.12)=\frac{y}{440}\Rightarrow y=440\cdot\sin (1.12)=440\cdot0.9=396[/tex][tex]\cos (1.12)=\frac{x}{440}\Rightarrow x=440\cdot\cos (1.12)=191.7[/tex]

A grocery store surveys its customers and asks them to indicate (a) how many times they go to the grocerystore in a typical month, (b) their age (in years), (c) whether or not they have ever had to wait in line at thegrocery store more than 10 minutes, (d) the product they purchase most often at the grocery store, and (e)how long (in years) they have shopped at this particular grocery store. We would consider the customer'sage in years to be aand whether or not the customer has had to wait in linemore than 10 minutes to be aO numerical variable; categorical variableO categorical variable; categorical variableO numerical variable; numerical variableO explanatory variable; response variableO categorical variable; numerical variable

Answers

The age in years is a numerical variable because it can be listed in ascending or descending order. while whether or not the customer has had to wait in line more than 10 minutes is a categorica

The ratio of the amount of money Rachel saved to the amount of money Timothy saved was12 : 13. After Timothy spent $27, Rachel had 3 times as much as Timothy,A. How much did Rachel save?b How much did they save altogether at first?

Answers

For a)

Before

Rachel : Timothy

12 : 13

After

Rachel : Timothy

3 : 1

In order to have the same amount for Rachel

12: 4

Timothy

13units -4 units =9 units

9units=$27

1 unit=27/9

1unit = $3

For Rachel

Rachel saved $36

b)

Total units at first =12+13=25

If 1units is $3

25 units is 3x25

25 units is $75

They saved together 75

ANSWER

Rachel saved $36

They saved together 75

Determine whether the function is linear. If it is, State the rate of change.Question 8

Answers

Question 8.

Given the table:

x -7 -5 -3 -1 0

y 11 14 17 20 23

To determine if the function is linear, let's calculate to see if the rate of change is constant.

The x-values need to have a constant rate of change and the y-values need to have a constant rate of change.

If the function has a constant rate of change, then the functioncan be said to be linear.

To calculate the rate of change, we have:

[tex]\begin{gathered} x2-x1=-5\text{ - (-7) = -5 + 7 = 2} \\ \\ x3-x2=-3-(-5)=-3+5=2 \\ \\ x4-x3=-1-(-3)=-1+3=2 \\ \\ x5-x4=0-(-1)=0+1=1 \\ \\ We\text{ can se}e\text{ the x-values do not have a constant rate of change} \end{gathered}[/tex][tex]\begin{gathered} y2-y1=14-11=3 \\ \\ y3-y2=17-14=3 \\ \\ y4-y3=20-17=3 \\ \\ y5-y4=23-20=3 \\ \\ \text{The y-values have a constant rate of change} \end{gathered}[/tex]

Since the x-values do not have a constant rate of change that means the function is not linear.

ANSWER:

The table does not represent a linear function

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