The volume of cone is calculated using this formula:
[tex]\begin{gathered} V=\frac{1}{3}\pi r^2h \\ r\colon\text{radius} \\ h\colon\text{height} \\ \pi\colon\text{ a constant with a value of }\frac{22}{7} \end{gathered}[/tex]So, to obtain the volume of a cone, the radius and the height must be known.
We then multiply the value of the constant pi by the square of the radius and the height, and then divide the final result by 3.
The unit is cubic unit.
Go step by step to reduce the radical. V 243 DVD try You must answer all questions above in order to submit.
We are given the following radical
[tex]\sqrt[]{243}[/tex]Let us reduce the above radical
We need to break the number 243 into a product of factors
Notice that 81 and 3 are the factors (83×3 = 243)
[tex]\sqrt[]{243}=\sqrt[]{81}\cdot\sqrt[]{3}[/tex]Since 81 is a perfect square so the radical becomes
[tex]\sqrt[]{243}=\sqrt[]{81}\cdot\sqrt[]{3}=9\cdot\sqrt[]{3}[/tex]Therefore, the simplified radical is
[tex]undefined[/tex]5.) The elements of f(x) are (-7,3).(-1, 6) and (8,-3). What is the range of the function?
The range of a function is all values of y the function have.
So, looking at the elements (-7, 3), (-1, 6) and (8, -3), the y-coordinates of these points are 3, 6 and -3.
So the range of f(x) is:
[tex]\text{range}=\mleft\lbrace-3,3,6\mright\rbrace[/tex]For which equation is x = 5 a solution ?
Given x = 5
We will find which equation will give a solution x = 5
1) x/2 = 10
so, x = 2 * 10 = 20
So, option (1) is wrong
2) x - 7 = 12
x = 12 + 7 = 19
So, option 2 is wrong
3) 2 + x = 3
x = 3 - 2 = 1
So, option 3 is wrong
4) 3x = 15
x = 15/3 = 5
So, the answer is option 3x = 15
1000=10 to the power 310,000= 10 to the power 4100,000=10 to the power 51,000,000= 10 to the power 6the next line is
According to the information, the question looks to construct the pattern given, at the left we can see that there is a 0 added in every line and at the right the exponent is added +1.
the next line in the pattern is
[tex]10,000,000=10^7[/tex]Drag and drop the expressions into the boxes to correctly complete the proof of the polynomial identity.(x2 + y2)2 + 2x?y– y4 = x(x² + 4y?)(x2 + y2)2 + 2x²y2 – y4 = x(+ 4y?)+2x²y2 – y4 = x2 (x2 + 4y?)x² (x² + 47²)= x2 (x2 + 4y2)x² (x² + 47²) x² – 2x²y² + y x² + yt x² + 4x²72 x + 2x²,2x² + 2x²y² + yt
Answer:
x^4 + y^4 + 2x^2 y^2
x^4 + 4x^2y^2
x^2 (x^2 + 4y^2 )
Explanation:
Expanding the the expression gives
[tex]\begin{gathered} (x^2+y^2)^4=(x^2)^2+(y^2)^2+2(x^2)(y^2) \\ =\boxed{x^4+y^4+2x^2y^2\text{.}} \end{gathered}[/tex]Simplifying the Left-hand side gives
[tex]\begin{gathered} x^4+y^4+2x^2y^2+2x^2y^2-y^4 \\ =\boxed{x^4+4x^2y^2\text{.}} \end{gathered}[/tex]Finally, factoring out x^2 from the left-hand side gives
[tex]x^4+4x^2y^2=\boxed{x^2\mleft(x^2+4y^2\mright)\text{.}}[/tex]Two monomials are shown below.18x³y 30x22What is the greatest common factor (GCF) of thesemonomials?
The given monomials are:
[tex]\begin{gathered} 18x^3y \\ 30x^2y^2 \end{gathered}[/tex]Factorizing each term, we get,
[tex]\begin{gathered} 18x^3y=2\times3\times3\times x^2\times y \\ 30x^2y^2=3\times2\times5\times x^2\times y^2 \end{gathered}[/tex]Therefore, the GCF is,
[tex]\text{GCF}=6x^2y[/tex]In a coordinate plane, the midpoint of AB is (2,5) and A is located at (-5,10). If (x,y) are the coordinates of B, find x and y.
In a coordinate plane, the midpoint of AB is (2,5) and A is located at (-5,10). If (x,y) are the coordinates of B, find x and y.
Remember that
the formula to calculate the midpoint between two points is equal to
[tex]M=(\frac{x1+x2}{2},\frac{y1+y2}{2})[/tex]In this problem we have
M=(2,5)
(x1,y1)=A(-5,10)
(x2,y2)=B(x,y)
substitute the given values
[tex](2,5)=(\frac{-5+x}{2},\frac{10+y}{2})[/tex]step 1
Find the x-coordinate of B
equate the x-coordinates
so
2=(-5+x)/2
solve for x
4=-5+x
x=4+5=9
step 2
Find the y-coordinate of B
equate the y-coordinates
5=(10+y)/2
solve for y
10=y+10
y=0
therefore
the coordinates of B are (9,0)Use a calculator to find an angle θ on the interval [0∘,90∘] that satisfies the following equation.tanθ=3.54
Answer:
θ = 74.23°
Explanation:
The inverse function of the tangent is arctangent and it can be written as:
[tex]\arctan (x)=\tan ^{-1}(x)[/tex]So, if tan θ = 3.54, then:
[tex]\theta=\tan ^{-1}(3.54)[/tex]Then, using the calculator, we get:
[tex]\theta=74.23\text{ degrees}[/tex]So, the answer is θ = 74.23°
how many minutes until the heart beats 200 times
From the given table, we can read that the 200 beats is associated with the entry: "5 minutes", so that is the answer we pick.
which agrees with the first option in the provided list of possible answers.
It took Carmen 4 hours to drive 200 miles. Using context clues from the problem, what formula can be used to find George's rate of speed?
From the information given, we can find th rate of speed with the equation;
[tex]\text{distance = rate x time}[/tex]Or;
[tex]d=rt[/tex]Question 25.Show if given 1-1 functions are inverse of each other. Graph both functions on the same set of axes and show the line Y=x as a dotted line on graph.
Given:
[tex]\begin{gathered} f(x)=3x+1_{} \\ g(x)=\frac{x-1}{3} \end{gathered}[/tex]To check the given functions are inverses of each other,
[tex]\begin{gathered} To\text{ prove: }f\mleft(g\mleft(x\mright)\mright)=x\text{ and g(f(x)=x} \\ f(g(x))=f(\frac{x-1}{3}) \\ =3(\frac{x-1}{3})+1 \\ =x-1+1 \\ =x \end{gathered}[/tex]And,
[tex]\begin{gathered} g(f(x))=g(3x+1) \\ =\frac{(3x+1)-1}{3} \\ =\frac{3x+1-1}{3} \\ =\frac{3x}{3} \\ =x \end{gathered}[/tex]It shows that, the given functions are inverses of each other.
The graph of the function is,
Blue line represents g(x)
Red line represents f(x)
green line represents y=x
Let Iql = 5 at an angle of 45° and [r= 16 at an angle of 300°. What is 19-r|?13.00 14.2O 15.518.0
As given that:
[tex]|q|=5[/tex]At angle of45 degree
and |r| = 16 at 300 degree
so the |q| at 300 degree is:
[tex]\begin{gathered} |q|=5\times\frac{300}{45} \\ |q|=33.33 \end{gathered}[/tex]Now |q-r| is:
[tex]\begin{gathered} |q-r|=33.33-16 \\ |q-r|=17.33 \\ |q-r|\approx18 \end{gathered}[/tex]So the correct option is d.
In 6-13 round each number to the place of the underlined digit
6. 32.7
7. 3.25
8. 41.1
9. 0.41
10. 6.1
11. 6.1
12. 184
13. 905.26
1) Considering that the underline marks the place to be rounded off we can do the following:
Note that if the number is greater than or equal to 5 then we will round it up.
If the number is lesser than 5 it will be rounded down.
Based on that we can round like this.
6. 32.7
7. 3.25
8. 41.1
9. 0.41
10. 6.1
11. 6.1
12. 184
13. 905.26
2)
Perform a web search for images for the term graph of sales trends. Choose an image where there are both increasing and decreasing trends. Upload the image you found and discuss the time period(s) when the sales trend is increasing, and when it is decreasing. Also indicate any periods where the trend stayed constant (that is, it did not change).
Imagine you have a newsstand and you start to pay attention to how many magazines you sell each month for one year to understand which months you sell more and which months you sell less. So what you want is to understand the trends of your business.
So, after a year, you are able to draw a graph that represents all sales for this year per month as follows:
So, as we can see above, We have the sales of your newsstand from January to August. The x-axis indicates the months of the year and the y-axis indicate the number of magazines sold. We can see for January you sold 15 magazines and the number increased for February and Mars. Between Mars, April and May, it stayed constant and from May to August it decreased. It is represented by the line in red, where we have first an increasing trend, after a constant trend and finally a decreasing trend. So that is how it works, and now you can understand and explain how a graph of sales trends works and which kind of images you have to look for.
Find the roots of the equation 5x2 + 125 = 0
The given equation is:
[tex]5x^2+125=0[/tex]Divide through by 5
[tex]\begin{gathered} \frac{5x^2}{5}+\frac{125}{5}=\frac{0}{5} \\ \\ x^2+25=0 \\ \end{gathered}[/tex]This is further simplified as:
[tex]\begin{gathered} x^2=-25 \\ \\ \sqrt{x^2}=\pm\sqrt{-25} \\ \\ \sqrt{x^2}=\pm\sqrt{-1}\times\sqrt{25} \\ \\ x^=\pm5i \\ \\ x=5i\text{ and -5i} \\ \end{gathered}[/tex]Use your scatter plot of the temperature in 'n de in degrees North 2. The vertical intercept ans1°F The horizontal intercept ans2 °N
From the graph, the vertical intercept is 120°F
The slope, m, of the line that passes through the points (x1, y1) and (x2, y2) is computed as follows:
[tex]m=\frac{y_2-y_1}{x_2-x_!}[/tex]From the graph, the line passes through the points (0, 120) and (55, 60), then its slope is:
[tex]m=\frac{60-120}{55-0}=-\frac{12}{11}[/tex]The slope-intercept form of a line is:
y = mx + b
where m is the slope and b is the y-intercept. In this case, the equation is
y = -12/11x + 120
Substituting with y = 0, we get:
[tex]\begin{gathered} 0=-\frac{12}{11}x+120 \\ -120=-\frac{12}{11}x \\ (-120)\cdot(-\frac{11}{12})=x \\ 110=x \end{gathered}[/tex]The horizontal intercept is 110°N
list all numbers from the given set that are
Part a
Natural numbers are:
[tex]\sqrt[]{25}[/tex]because
[tex]\sqrt[]{25}=5[/tex]Part b
whole numbers
[tex]0,\text{ }\sqrt[]{25}[/tex]Part c
Integers
[tex]-9,0,\sqrt[]{25}[/tex]Part d
rational numbers
[tex]\frac{3}{4},-9,0.6,0,8.5,\sqrt[]{25}[/tex]Part e
Irrational numbers
[tex]\pi,\text{ }-\sqrt[]{2}[/tex]Part f
real numbers
[tex]\frac{3}{4},-9,0.6,0,\pi,8.5,\sqrt[]{25},\text{ -}\sqrt[]{2}[/tex]Hello can you assist me please i need to solo e and Identity sine cosine or tangent and identify opposite hypnose or adjeact #12
Solution (12):
Given the triangle;
The opposite side is labelled as x and the adjacent side is 17.
Using the tangent trigonometry ratio, we have;
[tex]\tan\theta=\frac{opposite}{adjacent}[/tex]Thus;
[tex]\begin{gathered} \tan(51^o)=\frac{x}{17} \\ \\ x=17\tan(51^o) \\ \\ x=20.99 \\ \\ x\approx21 \end{gathered}[/tex]13. Graph the inequality. xs-3 X>8 10 9
You have teh following inequality:
x ≤ -3
consider that the previous inequality includes all number lower and equal to -3, that is, -3,-4,-5,.., until - infinity.
Then, the graph is:
For the following inequality:
x > 8
consider that the solutions are all numbers greater than 8 without including it.
Then, for the graph, you have:
Find the missing side or angle.Round to the nearest tenth.b=15a=30c=29A=[ ? 1°
STEP 1
The given parameters are a=30, b=15 and c=29
The corresponding cosine rule needed to find the angle A is denoted below
[tex]A=\cos ^{-1}\mleft[\frac{b^2+c^2-a^2}{2bc}\mright]^{}[/tex]STEP 2
Substitute the given parameters into the equation.
[tex]\begin{gathered} A=\cos ^{-1}\mleft\lbrace\frac{15^2+29^2-30^2}{2\times15\times29}\mright\rbrace \\ A=\cos ^{-1}\mleft\lbrace\frac{225+841-900}{870}\mright\rbrace \\ A=\cos ^{-1}\mleft\lbrace\frac{166}{870}\mright\rbrace \\ A=\cos ^{-1}0.1908 \\ A=79.0^0 \end{gathered}[/tex]write and slove six less then the product of a number n and 1/4 is no more than 96 fill in the boxs
ANSWER:
[tex]n\leq408[/tex]STEP-BY-STEP EXPLANATION:
With the statement we deduce the following inequality
[tex]\frac{1}{4}\cdot n-6\leq96[/tex]Solving for n
[tex]\begin{gathered} 4\cdot\frac{1}{4}\cdot n-4\cdot6\leq4\cdot96 \\ n-24\leq384 \\ n\leq384+24 \\ n\leq408 \end{gathered}[/tex]The senior classes at High School A and High School B planned separate trips to New York City.The senior class at High School A rented and filled 2 vans and 6 buses with 366 students. HighSchool B rented and filled 6 vans and 3 buses with 213 students. Each van and each bus carriedthe same number of students. Find the number of students in each van and in each bus.Answer: A van hasstudents and bus has students
Let V be the number of students that fit inside a van and B the number of students that fit inside a bus. Since 366 students fit in 2 vans and 6 buses, then:
[tex]2V+6B=366[/tex]Since 213 students fit in 6 vans and 3 buses, then:
[tex]6V+3B=213[/tex]Multiply the second equation by 2:
[tex]\begin{gathered} 2(6V+3B)=2(213) \\ \Rightarrow12V+6B=426 \end{gathered}[/tex]Then, we have the system:
[tex]\begin{gathered} 2V+6B=366 \\ 12V+6B=426 \end{gathered}[/tex]Substract the first equation from the second one and solve for V:
[tex]\begin{gathered} (12V+6B)-(2V+6B)=426-366 \\ \Rightarrow12V-2V+6B-6B=60 \\ \Rightarrow10V=60 \\ \Rightarrow V=\frac{60}{10} \\ \therefore V=6 \end{gathered}[/tex]Substitute V=6 into the first equation and solve for B:
[tex]\begin{gathered} 2V+6B=366 \\ \Rightarrow2(6)+6B=366 \\ \Rightarrow12+6B=366 \\ \Rightarrow6B=366-12 \\ \Rightarrow6B=354 \\ \Rightarrow B=\frac{354}{6} \\ \therefore B=59 \end{gathered}[/tex]Therefore, a van has 6 students and a bus has 59 students.
Each expression below represents the area of a rectangle written as a product tha area model for each expression on your paper and label its length and then we nation showing that the area written as a product is equal to the area wimen as the the parts de prepared to share your equations with the class. a. (x+3)(2x + 1) ca(224) d. (2x + 5)(x + y + 2) • (20 - 1999 (2x-1) (2x-1) g. 2(325) ( 2+ y + 3) 2
We have the expression:
[tex]x(2x-y)[/tex]It can be thougth as the area of a rectangle with sides x and (2x-y).
We can also think of the the difference between an area of a rectangle with sides x and 2x and a rectangle with sides x and y:
[tex]x(2x-y)=x\cdot2x-x\cdot y=2x^2-xy[/tex]Answer: x(2x-y) = 2x^2-xy
HELP HELP HELP PLEASE!!!!!!!!!!
The slope of the given table is m = 5/4 or 1.25
The given table has various values of x and y
So given : y₂ = 30 and y₁ = 45
likewise x₂ = 8 and x₁ = 4
Thus the points are
P₁ = ( 4, 45 ) and P₂ = ( 8, 30 )
Since both points are positive thus these points lie in the first quadrant
Also to calculate the slope of a graph we use the formula
m or slope = y₂ - y₁ / x₂ - x₁
On substituting the above mentioned values
we will get
m or slope = 45 - 30/ 8 - 4
this further implies that
m or the slope = 5 /4 = 1.25
Thus the slope of the given values is 1.25
To know more about slope and coordinate geometry you may visit the link which is mentioned below:
https://brainly.com/question/16302642
#SPJ1
Find the exact area of la circle if its circumference is 367 cm.
Given the circumference to be 367 cm.
Recall that the formula for the circumference of a circle is given as;
[tex]\begin{gathered} C=2\pi r \\ \Rightarrow367=2\pi r \end{gathered}[/tex]If we make r the subject of the formula,
[tex]r=\frac{367}{2\pi}[/tex]The area of a circle is given as;
[tex]\begin{gathered} A=\pi r^2 \\ \Rightarrow\pi(\frac{367}{2\pi})^2=\frac{\pi}{4\pi^2}(367)^2=10718.21 \end{gathered}[/tex]Solve for x: |x - 2| + 10 = 12 A x = 0 and x = 4B x = -4 and x = 0C x = -20 and x=4 D No solution
|x - 2| + 10 = 12
|x - 2| = 12 -10
|x - 2| = 2
There are 2 solutions:
x-2 = 2 and x-2 = -2
Solve each:
x = 2+2
x = 4
x-2=-2
x =-2+2
x=0
solution: x=0 and x = 4
laws of exponent : multiplication and power to a poweranswer and help me step by step
All the numbers multiply in the normal way, and the powers of a power need to be multiplied.
[tex]72c^4d^8e^{10}[/tex]having a bit of a problem with this logarithmic equation I will upload a photo
SOLUTION
We are asked to solve the equation
[tex]4^{5x-6}=44[/tex]44 cannot be written in index form. So to solve this, we will take logarithm of both sides of the equation
We will have
[tex]\log 4^{5x-6}=\log 44[/tex]Solving for x, we have
[tex]\begin{gathered} \log 4^{5x-6}=\log 44 \\ \\ 5x-6\log 4=\log 44 \\ \\ \text{dividing both sides by log4} \\ \\ 5x-6=\frac{\log 44}{\log 4} \\ \\ 5x=\frac{\log44}{\log4}+6 \end{gathered}[/tex]The exact solution becomes
[tex]x=\frac{(\frac{\log44}{\log4}+6)}{5}[/tex]The approximate solution to 4 d.p
[tex]\begin{gathered} x=\frac{(\frac{\log44}{\log4}+6)}{5} \\ \\ x=\frac{(\frac{1.64345}{0.60206}+6)}{5} \\ \\ x=\frac{8.72971}{5} \\ \\ x=1.7459 \end{gathered}[/tex]what is the rate of change of the cube’s surface area when its edges are 50 mm long?
The first thing we are going to do is identify the volume and surface of the cube and their respective derivatives or rate of change
[tex]\begin{gathered} V\to\text{volume} \\ S\to\text{surface} \\ l=\text{side of a square} \end{gathered}[/tex][tex]\begin{gathered} V=l^3\to(1) \\ \frac{dV}{dt}=3l^2\frac{dl}{dt}\to(2) \end{gathered}[/tex][tex]\begin{gathered} S=6l^2\to(3) \\ \frac{dS}{dt}=12\cdot l\cdot\frac{dl}{dt}\to(4) \end{gathered}[/tex]From the exercise we know that:
[tex]\begin{gathered} \frac{dV}{dt}=300\frac{\operatorname{mm}^3}{s}\to(5) \\ 3l^2\frac{dl}{dt}=300\frac{\operatorname{mm}^3}{s}\to(2)=(5) \\ \frac{dl}{dt}=\frac{300}{3l^2}\frac{\operatorname{mm}^3}{s}\to(6) \end{gathered}[/tex]The exercise asks us to calculate the rate of change of the surface (4) so we substitute the differential of length (6) in (4)
[tex]\begin{gathered} \frac{dS}{dt}=12\cdot l\cdot(\frac{300}{3l^2}\frac{\operatorname{mm}^3}{s}) \\ \frac{dS}{dt}=\frac{1200}{l}\frac{\operatorname{mm}}{s} \end{gathered}[/tex]what is the rate of change of the cube’s surface area when its edges are 50 mm long?
[tex]\begin{gathered} l=50\operatorname{mm} \\ \frac{dS}{dt}=\frac{1200}{50\operatorname{mm}}\frac{\operatorname{mm}^3}{s} \\ \frac{dS}{dt}=24\frac{\operatorname{mm}^2}{s} \end{gathered}[/tex]The answer is 44mm²/sWhat is the Slope of HI ? Justify your answer .Please help
Solution:
Given:
A coordinate plane with two similar triangles.
To get the slope of HI, because the two triangles are similar, their hypotenuses will always have the same slope.
Hence, the slope of HI is also the slope of DE.
[tex]\begin{gathered} \text{Considering }\Delta DEF,\text{ using the points (8,32) and (12,24)} \\ \text{where;} \\ x_1=8 \\ y_1=32 \\ x_2=12 \\ y_2=24 \end{gathered}[/tex]
Using the formula for calculating slope (m),
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Substituting the values of the points gotten from triangle DEF,
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{24-32}{12-8} \\ m=\frac{-8}{4} \\ m=-2 \end{gathered}[/tex]Since the slope of triangle DEF is the hypotenuse of the right triangle DEF, then the slope HI is also the hypotenuse of triangle HIJ and both hypotenuses have the same slope since both triangles are similar.
Therefore, the slope of HI is -2.